Incomplete cube












13















I want to draw an incomplete cube, as in the following figure.



enter image description here



But, I can only draw a complete cube, see below.



enter image description here



documentclass[12pt]{article}
usepackage{tikz}
usepackage{verbatim}
usetikzlibrary{positioning}
begin{document}
begin{tikzpicture}[on grid][scale=1.4]
shade[yslant=-0.5,right color=white, left color=white]
(0,0) rectangle +(3,3);
draw[yslant=-0.5] (0,0) grid (3,3);
shade[yslant=0.5,right color=white,left color=white]
(3,-3) rectangle +(3,3);
draw[yslant=0.5] (3,-3) grid (6,0);
shade[yslant=0.5,xslant=-1,bottom color=white,
top color=white] (6,3) rectangle +(-3,-3);
draw[yslant=0.5,xslant=-1] (3,0) grid (6,3);
end{tikzpicture}
end{document}









share|improve this question





























    13















    I want to draw an incomplete cube, as in the following figure.



    enter image description here



    But, I can only draw a complete cube, see below.



    enter image description here



    documentclass[12pt]{article}
    usepackage{tikz}
    usepackage{verbatim}
    usetikzlibrary{positioning}
    begin{document}
    begin{tikzpicture}[on grid][scale=1.4]
    shade[yslant=-0.5,right color=white, left color=white]
    (0,0) rectangle +(3,3);
    draw[yslant=-0.5] (0,0) grid (3,3);
    shade[yslant=0.5,right color=white,left color=white]
    (3,-3) rectangle +(3,3);
    draw[yslant=0.5] (3,-3) grid (6,0);
    shade[yslant=0.5,xslant=-1,bottom color=white,
    top color=white] (6,3) rectangle +(-3,-3);
    draw[yslant=0.5,xslant=-1] (3,0) grid (6,3);
    end{tikzpicture}
    end{document}









    share|improve this question



























      13












      13








      13


      1






      I want to draw an incomplete cube, as in the following figure.



      enter image description here



      But, I can only draw a complete cube, see below.



      enter image description here



      documentclass[12pt]{article}
      usepackage{tikz}
      usepackage{verbatim}
      usetikzlibrary{positioning}
      begin{document}
      begin{tikzpicture}[on grid][scale=1.4]
      shade[yslant=-0.5,right color=white, left color=white]
      (0,0) rectangle +(3,3);
      draw[yslant=-0.5] (0,0) grid (3,3);
      shade[yslant=0.5,right color=white,left color=white]
      (3,-3) rectangle +(3,3);
      draw[yslant=0.5] (3,-3) grid (6,0);
      shade[yslant=0.5,xslant=-1,bottom color=white,
      top color=white] (6,3) rectangle +(-3,-3);
      draw[yslant=0.5,xslant=-1] (3,0) grid (6,3);
      end{tikzpicture}
      end{document}









      share|improve this question
















      I want to draw an incomplete cube, as in the following figure.



      enter image description here



      But, I can only draw a complete cube, see below.



      enter image description here



      documentclass[12pt]{article}
      usepackage{tikz}
      usepackage{verbatim}
      usetikzlibrary{positioning}
      begin{document}
      begin{tikzpicture}[on grid][scale=1.4]
      shade[yslant=-0.5,right color=white, left color=white]
      (0,0) rectangle +(3,3);
      draw[yslant=-0.5] (0,0) grid (3,3);
      shade[yslant=0.5,right color=white,left color=white]
      (3,-3) rectangle +(3,3);
      draw[yslant=0.5] (3,-3) grid (6,0);
      shade[yslant=0.5,xslant=-1,bottom color=white,
      top color=white] (6,3) rectangle +(-3,-3);
      draw[yslant=0.5,xslant=-1] (3,0) grid (6,3);
      end{tikzpicture}
      end{document}






      tikz-pgf






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Apr 1 at 11:25









      sheß

      2,06511436




      2,06511436










      asked Apr 1 at 10:51









      Benedito FreireBenedito Freire

      1307




      1307






















          3 Answers
          3






          active

          oldest

          votes


















          14














          Just for fun: everything is in 2D



          documentclass[tikz]{standalone}
          begin{document}
          begin{tikzpicture}
          draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
          draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
          draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
          draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
          draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
          end{tikzpicture}
          end{document}


          enter image description here



          With colors



          documentclass[tikz]{standalone}
          begin{document}
          begin{tikzpicture}
          fill[black!70] (3,0)--(3.6,.6)--(3.6,2.6)--(3.4,2.4)--(3.4,1.4)--(3,1)--cycle (2.4,2.4)--(2.6,2.6)--(2.6,3.6)--(2.4,3.4)--(2.4,1.4)--(2,1)--(2,2)--cycle (1,2)--(1.4,2.4)--(1.4,3.4)--(1,3)--cycle;
          fill[black!30] (0,3)--(.6,3.6)-_(2.6,3.6)--(2.4,3.4)--(1.4,3.4)--(1,3)--cycle (2.4,2.4)--(2.6,2.6)--(3.6,2.6)--(3.4,2.4)--(1.4,2.4)--(1,2)--(2,2)--cycle (2,1)--(2.4,1.4)--(3.4,1.4)--(3,1)--cycle;
          draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
          draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
          draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
          draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
          draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer































            17














            You can define a single cube as pic and place it where you want (starting from bottom back to top front).



            documentclass[tikz,border=7pt]{standalone}
            tikzset{
            cube/.pic={
            draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0);
            draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0);
            draw[fill=white] (0,0,0) rectangle (1,1,0);
            }
            }
            begin{document}
            tikz[z={(.4,.3)}]pathpgfextra{def~{pic{cube}}} % <--- to make the code shorter
            (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~
            (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~
            (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;
            end{document}


            enter image description here






            share|improve this answer





















            • 1





              ...better to use the redefined ~ version inside a group, even if it's just to shorten your code. As in, begingroup def~{pic{code}} begin{tikzpicture} ... end{tikzpicture}.

              – Werner
              Apr 1 at 19:22











            • @Werner Agree, thanks. Done.

              – Kpym
              Apr 1 at 19:30











            • The pgfextra and {...} only to avoid { and }? ` tikz[z={(.4,.3)}]{def~{pic{cube}} path (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~ (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~ (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;}`

              – marmot
              Apr 1 at 20:23











            • @marmot I never avoid shorter code in general ;) But here, as redefining ~ is not a good practice, I decided to follow the comment of @Werner and to make its definition as local as possible : so local to the path is better to local for the entire tikz.

              – Kpym
              Apr 1 at 20:49











            • If that's your aim:documentclass[tikz,border=7pt]{standalone} tikzset{ cube/.pic={ draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0); draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0); draw[fill=white] (0,0,0) rectangle (1,1,0); },icube/.style={insert path={#1 pic{cube}}} } begin{document} tikz[z={(.4,.3)}]path[icube/.list={(2,0,2),(2,0,1),(0,0,0),(1,0,0),(2,0,0), (2,1,2),(1,1,1),(0,1,0),(1,1,0), (0,2,2),(1,2,2),(0,2,1),(0,2,0)}]; end{document}

              – marmot
              Apr 1 at 20:59



















            10














            I would like to argue that one should use orthographic projections and write it in such a way that one can change the view angle. There are already many posts on this, perhaps most impressingly this one. The idea to use pics for the unit cubes to draw 3d cubes with some little cubes missing is also not new, it has been used here, where the cubes are rotatable in 3d. I just recycled the code to get



            documentclass[tikz,border=3.14mm]{standalone}
            usepackage{tikz-3dplot}
            usetikzlibrary{calc}
            tikzset{plane/.style n args={3}{insert path={%
            #1 -- ++ #2 -- ++ #3 -- ++ ($-1*#2$) -- cycle}},
            unit xy plane/.style={plane={#1}{(1,0,0)}{(0,1,0)}},
            unit xz plane/.style={plane={#1}{(1,0,0)}{(0,0,1)}},
            unit yz plane/.style={plane={#1}{(0,1,0)}{(0,0,1)}},
            get projections/.style={insert path={%
            let p1=(1,0,0),p2=(0,1,0) in
            [/utils/exec={pgfmathtruncatemacro{xproj}{sign(x1)}xdefxproj{xproj}
            pgfmathtruncatemacro{yproj}{sign(x2)}xdefyproj{yproj}
            pgfmathtruncatemacro{zproj}{sign(cos(tdplotmaintheta))}xdefzproj{zproj}}]}},
            pics/unit cube/.style={code={
            path[get projections];
            draw (0,0,0) -- (1,1,1);
            ifnumzproj=-1
            path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,0)}];
            fi
            ifnumyproj=1
            path[3d cube/every face,3d cube/yz face,unit yz plane={(1,0,0)}];
            else
            path[3d cube/every face,3d cube/yz face,unit yz plane={(0,0,0)}];
            fi
            ifnumxproj=1
            path[3d cube/every face,3d cube/xz face,unit xz plane={(0,0,0)}];
            else
            path[3d cube/every face,3d cube/xz face,unit xz plane={(0,1,0)}];
            fi
            ifnumzproj>-1
            path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,1)}];
            fi
            }},
            3d cube/.cd,
            xy face/.style={fill=gray!20},
            xz face/.style={fill=gray!50},
            yz face/.style={fill=gray!90},
            every face/.style={draw,very thick}
            }
            begin{document}
            foreach Angle in {5,15,...,355}
            {tdplotsetmaincoords{60}{Angle} % the first argument cannot be larger than 90
            begin{tikzpicture}[line join=round]
            pgfmathtruncatemacro{NumCubes}{7}
            path[use as bounding box] (-NumCubes/2-3,-NumCubes/2-2)
            rectangle (NumCubes/2+3,NumCubes/2+4);
            begin{scope}[tdplot_main_coords]
            pgfmathtruncatemacro{NextToLast}{NumCubes-1}
            path[get projections];
            ifnumyproj=1
            defLstX{1,2,3}
            else
            defLstX{3,2,1}
            fi
            ifnumxproj=-1
            defLstY{1,2,3}
            else
            defLstY{3,2,1}
            fi
            foreach X in LstX
            {foreach Y in LstY
            {ifnumY=3
            pgfmathtruncatemacro{Zmax}{5-max(X,2)}
            else
            pgfmathtruncatemacro{Zmax}{4-X}
            fi
            foreach Z in {1,...,Zmax}
            {path (X-2,Y-2,Z-1) pic{unit cube};}}
            }
            end{scope}
            end{tikzpicture}}
            end{document}


            enter image description here






            share|improve this answer
























            • "I would like to argue that one should use orthographic projections". Spoken like a true engineer! +1

              – Steven B. Segletes
              Apr 1 at 14:13












            Your Answer








            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "85"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f482561%2fincomplete-cube%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            14














            Just for fun: everything is in 2D



            documentclass[tikz]{standalone}
            begin{document}
            begin{tikzpicture}
            draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
            draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
            draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
            draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
            draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
            end{tikzpicture}
            end{document}


            enter image description here



            With colors



            documentclass[tikz]{standalone}
            begin{document}
            begin{tikzpicture}
            fill[black!70] (3,0)--(3.6,.6)--(3.6,2.6)--(3.4,2.4)--(3.4,1.4)--(3,1)--cycle (2.4,2.4)--(2.6,2.6)--(2.6,3.6)--(2.4,3.4)--(2.4,1.4)--(2,1)--(2,2)--cycle (1,2)--(1.4,2.4)--(1.4,3.4)--(1,3)--cycle;
            fill[black!30] (0,3)--(.6,3.6)-_(2.6,3.6)--(2.4,3.4)--(1.4,3.4)--(1,3)--cycle (2.4,2.4)--(2.6,2.6)--(3.6,2.6)--(3.4,2.4)--(1.4,2.4)--(1,2)--(2,2)--cycle (2,1)--(2.4,1.4)--(3.4,1.4)--(3,1)--cycle;
            draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
            draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
            draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
            draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
            draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer




























              14














              Just for fun: everything is in 2D



              documentclass[tikz]{standalone}
              begin{document}
              begin{tikzpicture}
              draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
              draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
              draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
              draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
              draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
              end{tikzpicture}
              end{document}


              enter image description here



              With colors



              documentclass[tikz]{standalone}
              begin{document}
              begin{tikzpicture}
              fill[black!70] (3,0)--(3.6,.6)--(3.6,2.6)--(3.4,2.4)--(3.4,1.4)--(3,1)--cycle (2.4,2.4)--(2.6,2.6)--(2.6,3.6)--(2.4,3.4)--(2.4,1.4)--(2,1)--(2,2)--cycle (1,2)--(1.4,2.4)--(1.4,3.4)--(1,3)--cycle;
              fill[black!30] (0,3)--(.6,3.6)-_(2.6,3.6)--(2.4,3.4)--(1.4,3.4)--(1,3)--cycle (2.4,2.4)--(2.6,2.6)--(3.6,2.6)--(3.4,2.4)--(1.4,2.4)--(1,2)--(2,2)--cycle (2,1)--(2.4,1.4)--(3.4,1.4)--(3,1)--cycle;
              draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
              draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
              draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
              draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
              draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
              end{tikzpicture}
              end{document}


              enter image description here






              share|improve this answer


























                14












                14








                14







                Just for fun: everything is in 2D



                documentclass[tikz]{standalone}
                begin{document}
                begin{tikzpicture}
                draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
                draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
                draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
                draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
                draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
                end{tikzpicture}
                end{document}


                enter image description here



                With colors



                documentclass[tikz]{standalone}
                begin{document}
                begin{tikzpicture}
                fill[black!70] (3,0)--(3.6,.6)--(3.6,2.6)--(3.4,2.4)--(3.4,1.4)--(3,1)--cycle (2.4,2.4)--(2.6,2.6)--(2.6,3.6)--(2.4,3.4)--(2.4,1.4)--(2,1)--(2,2)--cycle (1,2)--(1.4,2.4)--(1.4,3.4)--(1,3)--cycle;
                fill[black!30] (0,3)--(.6,3.6)-_(2.6,3.6)--(2.4,3.4)--(1.4,3.4)--(1,3)--cycle (2.4,2.4)--(2.6,2.6)--(3.6,2.6)--(3.4,2.4)--(1.4,2.4)--(1,2)--(2,2)--cycle (2,1)--(2.4,1.4)--(3.4,1.4)--(3,1)--cycle;
                draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
                draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
                draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
                draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
                draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
                end{tikzpicture}
                end{document}


                enter image description here






                share|improve this answer













                Just for fun: everything is in 2D



                documentclass[tikz]{standalone}
                begin{document}
                begin{tikzpicture}
                draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
                draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
                draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
                draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
                draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
                end{tikzpicture}
                end{document}


                enter image description here



                With colors



                documentclass[tikz]{standalone}
                begin{document}
                begin{tikzpicture}
                fill[black!70] (3,0)--(3.6,.6)--(3.6,2.6)--(3.4,2.4)--(3.4,1.4)--(3,1)--cycle (2.4,2.4)--(2.6,2.6)--(2.6,3.6)--(2.4,3.4)--(2.4,1.4)--(2,1)--(2,2)--cycle (1,2)--(1.4,2.4)--(1.4,3.4)--(1,3)--cycle;
                fill[black!30] (0,3)--(.6,3.6)-_(2.6,3.6)--(2.4,3.4)--(1.4,3.4)--(1,3)--cycle (2.4,2.4)--(2.6,2.6)--(3.6,2.6)--(3.4,2.4)--(1.4,2.4)--(1,2)--(2,2)--cycle (2,1)--(2.4,1.4)--(3.4,1.4)--(3,1)--cycle;
                draw (0,0) rectangle (1,1) (1,1) rectangle (2,2) (0,1) rectangle (1,2) (0,2) rectangle (1,3) (1,0) rectangle (2,1) (2,0) rectangle (3,1);
                draw (3.6,1.6)--(3.6,.6)--(3,0)--(3,1)--cycle--(3.6,2.6)--(2.6,2.6)--(2.6,3.6)--(.6,3.6)--(0,3);
                draw (2,1)--(2.4,1.4) (2,2)--(2.6,2.6) (1,2)--(1.4,2.4) (1,3)--(1.6,3.6) (2.4,3.4)--(2.6,3.6) (3.4,2.4)--(3.6,2.6);
                draw (2.4,1.4) rectangle (3.4,2.4) (1.4,2.4) rectangle (2.4,3.4);
                draw (.4,3.4)--(1.4,3.4) (3.4,1.4)--(3.4,.4) (.2,3.2)--(1.2,3.2)--(1.2,2.2)--(2.2,2.2)--(2.2,1.2)--(3.2,1.2)--(3.2,.2);
                end{tikzpicture}
                end{document}


                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Apr 1 at 11:07









                JouleVJouleV

                11.4k22561




                11.4k22561























                    17














                    You can define a single cube as pic and place it where you want (starting from bottom back to top front).



                    documentclass[tikz,border=7pt]{standalone}
                    tikzset{
                    cube/.pic={
                    draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=white] (0,0,0) rectangle (1,1,0);
                    }
                    }
                    begin{document}
                    tikz[z={(.4,.3)}]pathpgfextra{def~{pic{cube}}} % <--- to make the code shorter
                    (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~
                    (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~
                    (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;
                    end{document}


                    enter image description here






                    share|improve this answer





















                    • 1





                      ...better to use the redefined ~ version inside a group, even if it's just to shorten your code. As in, begingroup def~{pic{code}} begin{tikzpicture} ... end{tikzpicture}.

                      – Werner
                      Apr 1 at 19:22











                    • @Werner Agree, thanks. Done.

                      – Kpym
                      Apr 1 at 19:30











                    • The pgfextra and {...} only to avoid { and }? ` tikz[z={(.4,.3)}]{def~{pic{cube}} path (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~ (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~ (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;}`

                      – marmot
                      Apr 1 at 20:23











                    • @marmot I never avoid shorter code in general ;) But here, as redefining ~ is not a good practice, I decided to follow the comment of @Werner and to make its definition as local as possible : so local to the path is better to local for the entire tikz.

                      – Kpym
                      Apr 1 at 20:49











                    • If that's your aim:documentclass[tikz,border=7pt]{standalone} tikzset{ cube/.pic={ draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0); draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0); draw[fill=white] (0,0,0) rectangle (1,1,0); },icube/.style={insert path={#1 pic{cube}}} } begin{document} tikz[z={(.4,.3)}]path[icube/.list={(2,0,2),(2,0,1),(0,0,0),(1,0,0),(2,0,0), (2,1,2),(1,1,1),(0,1,0),(1,1,0), (0,2,2),(1,2,2),(0,2,1),(0,2,0)}]; end{document}

                      – marmot
                      Apr 1 at 20:59
















                    17














                    You can define a single cube as pic and place it where you want (starting from bottom back to top front).



                    documentclass[tikz,border=7pt]{standalone}
                    tikzset{
                    cube/.pic={
                    draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=white] (0,0,0) rectangle (1,1,0);
                    }
                    }
                    begin{document}
                    tikz[z={(.4,.3)}]pathpgfextra{def~{pic{cube}}} % <--- to make the code shorter
                    (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~
                    (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~
                    (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;
                    end{document}


                    enter image description here






                    share|improve this answer





















                    • 1





                      ...better to use the redefined ~ version inside a group, even if it's just to shorten your code. As in, begingroup def~{pic{code}} begin{tikzpicture} ... end{tikzpicture}.

                      – Werner
                      Apr 1 at 19:22











                    • @Werner Agree, thanks. Done.

                      – Kpym
                      Apr 1 at 19:30











                    • The pgfextra and {...} only to avoid { and }? ` tikz[z={(.4,.3)}]{def~{pic{cube}} path (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~ (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~ (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;}`

                      – marmot
                      Apr 1 at 20:23











                    • @marmot I never avoid shorter code in general ;) But here, as redefining ~ is not a good practice, I decided to follow the comment of @Werner and to make its definition as local as possible : so local to the path is better to local for the entire tikz.

                      – Kpym
                      Apr 1 at 20:49











                    • If that's your aim:documentclass[tikz,border=7pt]{standalone} tikzset{ cube/.pic={ draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0); draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0); draw[fill=white] (0,0,0) rectangle (1,1,0); },icube/.style={insert path={#1 pic{cube}}} } begin{document} tikz[z={(.4,.3)}]path[icube/.list={(2,0,2),(2,0,1),(0,0,0),(1,0,0),(2,0,0), (2,1,2),(1,1,1),(0,1,0),(1,1,0), (0,2,2),(1,2,2),(0,2,1),(0,2,0)}]; end{document}

                      – marmot
                      Apr 1 at 20:59














                    17












                    17








                    17







                    You can define a single cube as pic and place it where you want (starting from bottom back to top front).



                    documentclass[tikz,border=7pt]{standalone}
                    tikzset{
                    cube/.pic={
                    draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=white] (0,0,0) rectangle (1,1,0);
                    }
                    }
                    begin{document}
                    tikz[z={(.4,.3)}]pathpgfextra{def~{pic{cube}}} % <--- to make the code shorter
                    (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~
                    (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~
                    (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;
                    end{document}


                    enter image description here






                    share|improve this answer















                    You can define a single cube as pic and place it where you want (starting from bottom back to top front).



                    documentclass[tikz,border=7pt]{standalone}
                    tikzset{
                    cube/.pic={
                    draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0);
                    draw[fill=white] (0,0,0) rectangle (1,1,0);
                    }
                    }
                    begin{document}
                    tikz[z={(.4,.3)}]pathpgfextra{def~{pic{cube}}} % <--- to make the code shorter
                    (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~
                    (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~
                    (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;
                    end{document}


                    enter image description here







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Apr 1 at 19:30

























                    answered Apr 1 at 11:49









                    KpymKpym

                    17.8k24191




                    17.8k24191








                    • 1





                      ...better to use the redefined ~ version inside a group, even if it's just to shorten your code. As in, begingroup def~{pic{code}} begin{tikzpicture} ... end{tikzpicture}.

                      – Werner
                      Apr 1 at 19:22











                    • @Werner Agree, thanks. Done.

                      – Kpym
                      Apr 1 at 19:30











                    • The pgfextra and {...} only to avoid { and }? ` tikz[z={(.4,.3)}]{def~{pic{cube}} path (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~ (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~ (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;}`

                      – marmot
                      Apr 1 at 20:23











                    • @marmot I never avoid shorter code in general ;) But here, as redefining ~ is not a good practice, I decided to follow the comment of @Werner and to make its definition as local as possible : so local to the path is better to local for the entire tikz.

                      – Kpym
                      Apr 1 at 20:49











                    • If that's your aim:documentclass[tikz,border=7pt]{standalone} tikzset{ cube/.pic={ draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0); draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0); draw[fill=white] (0,0,0) rectangle (1,1,0); },icube/.style={insert path={#1 pic{cube}}} } begin{document} tikz[z={(.4,.3)}]path[icube/.list={(2,0,2),(2,0,1),(0,0,0),(1,0,0),(2,0,0), (2,1,2),(1,1,1),(0,1,0),(1,1,0), (0,2,2),(1,2,2),(0,2,1),(0,2,0)}]; end{document}

                      – marmot
                      Apr 1 at 20:59














                    • 1





                      ...better to use the redefined ~ version inside a group, even if it's just to shorten your code. As in, begingroup def~{pic{code}} begin{tikzpicture} ... end{tikzpicture}.

                      – Werner
                      Apr 1 at 19:22











                    • @Werner Agree, thanks. Done.

                      – Kpym
                      Apr 1 at 19:30











                    • The pgfextra and {...} only to avoid { and }? ` tikz[z={(.4,.3)}]{def~{pic{cube}} path (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~ (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~ (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;}`

                      – marmot
                      Apr 1 at 20:23











                    • @marmot I never avoid shorter code in general ;) But here, as redefining ~ is not a good practice, I decided to follow the comment of @Werner and to make its definition as local as possible : so local to the path is better to local for the entire tikz.

                      – Kpym
                      Apr 1 at 20:49











                    • If that's your aim:documentclass[tikz,border=7pt]{standalone} tikzset{ cube/.pic={ draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0); draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0); draw[fill=white] (0,0,0) rectangle (1,1,0); },icube/.style={insert path={#1 pic{cube}}} } begin{document} tikz[z={(.4,.3)}]path[icube/.list={(2,0,2),(2,0,1),(0,0,0),(1,0,0),(2,0,0), (2,1,2),(1,1,1),(0,1,0),(1,1,0), (0,2,2),(1,2,2),(0,2,1),(0,2,0)}]; end{document}

                      – marmot
                      Apr 1 at 20:59








                    1




                    1





                    ...better to use the redefined ~ version inside a group, even if it's just to shorten your code. As in, begingroup def~{pic{code}} begin{tikzpicture} ... end{tikzpicture}.

                    – Werner
                    Apr 1 at 19:22





                    ...better to use the redefined ~ version inside a group, even if it's just to shorten your code. As in, begingroup def~{pic{code}} begin{tikzpicture} ... end{tikzpicture}.

                    – Werner
                    Apr 1 at 19:22













                    @Werner Agree, thanks. Done.

                    – Kpym
                    Apr 1 at 19:30





                    @Werner Agree, thanks. Done.

                    – Kpym
                    Apr 1 at 19:30













                    The pgfextra and {...} only to avoid { and }? ` tikz[z={(.4,.3)}]{def~{pic{cube}} path (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~ (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~ (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;}`

                    – marmot
                    Apr 1 at 20:23





                    The pgfextra and {...} only to avoid { and }? ` tikz[z={(.4,.3)}]{def~{pic{cube}} path (2,0,2)~(2,0,1)~(0,0,0)~(1,0,0)~(2,0,0)~ (2,1,2)~(1,1,1)~(0,1,0)~(1,1,0)~ (0,2,2)~(1,2,2)~(0,2,1)~(0,2,0)~;}`

                    – marmot
                    Apr 1 at 20:23













                    @marmot I never avoid shorter code in general ;) But here, as redefining ~ is not a good practice, I decided to follow the comment of @Werner and to make its definition as local as possible : so local to the path is better to local for the entire tikz.

                    – Kpym
                    Apr 1 at 20:49





                    @marmot I never avoid shorter code in general ;) But here, as redefining ~ is not a good practice, I decided to follow the comment of @Werner and to make its definition as local as possible : so local to the path is better to local for the entire tikz.

                    – Kpym
                    Apr 1 at 20:49













                    If that's your aim:documentclass[tikz,border=7pt]{standalone} tikzset{ cube/.pic={ draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0); draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0); draw[fill=white] (0,0,0) rectangle (1,1,0); },icube/.style={insert path={#1 pic{cube}}} } begin{document} tikz[z={(.4,.3)}]path[icube/.list={(2,0,2),(2,0,1),(0,0,0),(1,0,0),(2,0,0), (2,1,2),(1,1,1),(0,1,0),(1,1,0), (0,2,2),(1,2,2),(0,2,1),(0,2,0)}]; end{document}

                    – marmot
                    Apr 1 at 20:59





                    If that's your aim:documentclass[tikz,border=7pt]{standalone} tikzset{ cube/.pic={ draw[fill=black!20] (0,1,0) -- (0,1,1) -- (1,1,1) -- (1,1,0); draw[fill=black!50] (1,0,0) -- (1,0,1) -- (1,1,1) -- (1,1,0); draw[fill=white] (0,0,0) rectangle (1,1,0); },icube/.style={insert path={#1 pic{cube}}} } begin{document} tikz[z={(.4,.3)}]path[icube/.list={(2,0,2),(2,0,1),(0,0,0),(1,0,0),(2,0,0), (2,1,2),(1,1,1),(0,1,0),(1,1,0), (0,2,2),(1,2,2),(0,2,1),(0,2,0)}]; end{document}

                    – marmot
                    Apr 1 at 20:59











                    10














                    I would like to argue that one should use orthographic projections and write it in such a way that one can change the view angle. There are already many posts on this, perhaps most impressingly this one. The idea to use pics for the unit cubes to draw 3d cubes with some little cubes missing is also not new, it has been used here, where the cubes are rotatable in 3d. I just recycled the code to get



                    documentclass[tikz,border=3.14mm]{standalone}
                    usepackage{tikz-3dplot}
                    usetikzlibrary{calc}
                    tikzset{plane/.style n args={3}{insert path={%
                    #1 -- ++ #2 -- ++ #3 -- ++ ($-1*#2$) -- cycle}},
                    unit xy plane/.style={plane={#1}{(1,0,0)}{(0,1,0)}},
                    unit xz plane/.style={plane={#1}{(1,0,0)}{(0,0,1)}},
                    unit yz plane/.style={plane={#1}{(0,1,0)}{(0,0,1)}},
                    get projections/.style={insert path={%
                    let p1=(1,0,0),p2=(0,1,0) in
                    [/utils/exec={pgfmathtruncatemacro{xproj}{sign(x1)}xdefxproj{xproj}
                    pgfmathtruncatemacro{yproj}{sign(x2)}xdefyproj{yproj}
                    pgfmathtruncatemacro{zproj}{sign(cos(tdplotmaintheta))}xdefzproj{zproj}}]}},
                    pics/unit cube/.style={code={
                    path[get projections];
                    draw (0,0,0) -- (1,1,1);
                    ifnumzproj=-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,0)}];
                    fi
                    ifnumyproj=1
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(1,0,0)}];
                    else
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(0,0,0)}];
                    fi
                    ifnumxproj=1
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,0,0)}];
                    else
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,1,0)}];
                    fi
                    ifnumzproj>-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,1)}];
                    fi
                    }},
                    3d cube/.cd,
                    xy face/.style={fill=gray!20},
                    xz face/.style={fill=gray!50},
                    yz face/.style={fill=gray!90},
                    every face/.style={draw,very thick}
                    }
                    begin{document}
                    foreach Angle in {5,15,...,355}
                    {tdplotsetmaincoords{60}{Angle} % the first argument cannot be larger than 90
                    begin{tikzpicture}[line join=round]
                    pgfmathtruncatemacro{NumCubes}{7}
                    path[use as bounding box] (-NumCubes/2-3,-NumCubes/2-2)
                    rectangle (NumCubes/2+3,NumCubes/2+4);
                    begin{scope}[tdplot_main_coords]
                    pgfmathtruncatemacro{NextToLast}{NumCubes-1}
                    path[get projections];
                    ifnumyproj=1
                    defLstX{1,2,3}
                    else
                    defLstX{3,2,1}
                    fi
                    ifnumxproj=-1
                    defLstY{1,2,3}
                    else
                    defLstY{3,2,1}
                    fi
                    foreach X in LstX
                    {foreach Y in LstY
                    {ifnumY=3
                    pgfmathtruncatemacro{Zmax}{5-max(X,2)}
                    else
                    pgfmathtruncatemacro{Zmax}{4-X}
                    fi
                    foreach Z in {1,...,Zmax}
                    {path (X-2,Y-2,Z-1) pic{unit cube};}}
                    }
                    end{scope}
                    end{tikzpicture}}
                    end{document}


                    enter image description here






                    share|improve this answer
























                    • "I would like to argue that one should use orthographic projections". Spoken like a true engineer! +1

                      – Steven B. Segletes
                      Apr 1 at 14:13
















                    10














                    I would like to argue that one should use orthographic projections and write it in such a way that one can change the view angle. There are already many posts on this, perhaps most impressingly this one. The idea to use pics for the unit cubes to draw 3d cubes with some little cubes missing is also not new, it has been used here, where the cubes are rotatable in 3d. I just recycled the code to get



                    documentclass[tikz,border=3.14mm]{standalone}
                    usepackage{tikz-3dplot}
                    usetikzlibrary{calc}
                    tikzset{plane/.style n args={3}{insert path={%
                    #1 -- ++ #2 -- ++ #3 -- ++ ($-1*#2$) -- cycle}},
                    unit xy plane/.style={plane={#1}{(1,0,0)}{(0,1,0)}},
                    unit xz plane/.style={plane={#1}{(1,0,0)}{(0,0,1)}},
                    unit yz plane/.style={plane={#1}{(0,1,0)}{(0,0,1)}},
                    get projections/.style={insert path={%
                    let p1=(1,0,0),p2=(0,1,0) in
                    [/utils/exec={pgfmathtruncatemacro{xproj}{sign(x1)}xdefxproj{xproj}
                    pgfmathtruncatemacro{yproj}{sign(x2)}xdefyproj{yproj}
                    pgfmathtruncatemacro{zproj}{sign(cos(tdplotmaintheta))}xdefzproj{zproj}}]}},
                    pics/unit cube/.style={code={
                    path[get projections];
                    draw (0,0,0) -- (1,1,1);
                    ifnumzproj=-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,0)}];
                    fi
                    ifnumyproj=1
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(1,0,0)}];
                    else
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(0,0,0)}];
                    fi
                    ifnumxproj=1
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,0,0)}];
                    else
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,1,0)}];
                    fi
                    ifnumzproj>-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,1)}];
                    fi
                    }},
                    3d cube/.cd,
                    xy face/.style={fill=gray!20},
                    xz face/.style={fill=gray!50},
                    yz face/.style={fill=gray!90},
                    every face/.style={draw,very thick}
                    }
                    begin{document}
                    foreach Angle in {5,15,...,355}
                    {tdplotsetmaincoords{60}{Angle} % the first argument cannot be larger than 90
                    begin{tikzpicture}[line join=round]
                    pgfmathtruncatemacro{NumCubes}{7}
                    path[use as bounding box] (-NumCubes/2-3,-NumCubes/2-2)
                    rectangle (NumCubes/2+3,NumCubes/2+4);
                    begin{scope}[tdplot_main_coords]
                    pgfmathtruncatemacro{NextToLast}{NumCubes-1}
                    path[get projections];
                    ifnumyproj=1
                    defLstX{1,2,3}
                    else
                    defLstX{3,2,1}
                    fi
                    ifnumxproj=-1
                    defLstY{1,2,3}
                    else
                    defLstY{3,2,1}
                    fi
                    foreach X in LstX
                    {foreach Y in LstY
                    {ifnumY=3
                    pgfmathtruncatemacro{Zmax}{5-max(X,2)}
                    else
                    pgfmathtruncatemacro{Zmax}{4-X}
                    fi
                    foreach Z in {1,...,Zmax}
                    {path (X-2,Y-2,Z-1) pic{unit cube};}}
                    }
                    end{scope}
                    end{tikzpicture}}
                    end{document}


                    enter image description here






                    share|improve this answer
























                    • "I would like to argue that one should use orthographic projections". Spoken like a true engineer! +1

                      – Steven B. Segletes
                      Apr 1 at 14:13














                    10












                    10








                    10







                    I would like to argue that one should use orthographic projections and write it in such a way that one can change the view angle. There are already many posts on this, perhaps most impressingly this one. The idea to use pics for the unit cubes to draw 3d cubes with some little cubes missing is also not new, it has been used here, where the cubes are rotatable in 3d. I just recycled the code to get



                    documentclass[tikz,border=3.14mm]{standalone}
                    usepackage{tikz-3dplot}
                    usetikzlibrary{calc}
                    tikzset{plane/.style n args={3}{insert path={%
                    #1 -- ++ #2 -- ++ #3 -- ++ ($-1*#2$) -- cycle}},
                    unit xy plane/.style={plane={#1}{(1,0,0)}{(0,1,0)}},
                    unit xz plane/.style={plane={#1}{(1,0,0)}{(0,0,1)}},
                    unit yz plane/.style={plane={#1}{(0,1,0)}{(0,0,1)}},
                    get projections/.style={insert path={%
                    let p1=(1,0,0),p2=(0,1,0) in
                    [/utils/exec={pgfmathtruncatemacro{xproj}{sign(x1)}xdefxproj{xproj}
                    pgfmathtruncatemacro{yproj}{sign(x2)}xdefyproj{yproj}
                    pgfmathtruncatemacro{zproj}{sign(cos(tdplotmaintheta))}xdefzproj{zproj}}]}},
                    pics/unit cube/.style={code={
                    path[get projections];
                    draw (0,0,0) -- (1,1,1);
                    ifnumzproj=-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,0)}];
                    fi
                    ifnumyproj=1
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(1,0,0)}];
                    else
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(0,0,0)}];
                    fi
                    ifnumxproj=1
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,0,0)}];
                    else
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,1,0)}];
                    fi
                    ifnumzproj>-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,1)}];
                    fi
                    }},
                    3d cube/.cd,
                    xy face/.style={fill=gray!20},
                    xz face/.style={fill=gray!50},
                    yz face/.style={fill=gray!90},
                    every face/.style={draw,very thick}
                    }
                    begin{document}
                    foreach Angle in {5,15,...,355}
                    {tdplotsetmaincoords{60}{Angle} % the first argument cannot be larger than 90
                    begin{tikzpicture}[line join=round]
                    pgfmathtruncatemacro{NumCubes}{7}
                    path[use as bounding box] (-NumCubes/2-3,-NumCubes/2-2)
                    rectangle (NumCubes/2+3,NumCubes/2+4);
                    begin{scope}[tdplot_main_coords]
                    pgfmathtruncatemacro{NextToLast}{NumCubes-1}
                    path[get projections];
                    ifnumyproj=1
                    defLstX{1,2,3}
                    else
                    defLstX{3,2,1}
                    fi
                    ifnumxproj=-1
                    defLstY{1,2,3}
                    else
                    defLstY{3,2,1}
                    fi
                    foreach X in LstX
                    {foreach Y in LstY
                    {ifnumY=3
                    pgfmathtruncatemacro{Zmax}{5-max(X,2)}
                    else
                    pgfmathtruncatemacro{Zmax}{4-X}
                    fi
                    foreach Z in {1,...,Zmax}
                    {path (X-2,Y-2,Z-1) pic{unit cube};}}
                    }
                    end{scope}
                    end{tikzpicture}}
                    end{document}


                    enter image description here






                    share|improve this answer













                    I would like to argue that one should use orthographic projections and write it in such a way that one can change the view angle. There are already many posts on this, perhaps most impressingly this one. The idea to use pics for the unit cubes to draw 3d cubes with some little cubes missing is also not new, it has been used here, where the cubes are rotatable in 3d. I just recycled the code to get



                    documentclass[tikz,border=3.14mm]{standalone}
                    usepackage{tikz-3dplot}
                    usetikzlibrary{calc}
                    tikzset{plane/.style n args={3}{insert path={%
                    #1 -- ++ #2 -- ++ #3 -- ++ ($-1*#2$) -- cycle}},
                    unit xy plane/.style={plane={#1}{(1,0,0)}{(0,1,0)}},
                    unit xz plane/.style={plane={#1}{(1,0,0)}{(0,0,1)}},
                    unit yz plane/.style={plane={#1}{(0,1,0)}{(0,0,1)}},
                    get projections/.style={insert path={%
                    let p1=(1,0,0),p2=(0,1,0) in
                    [/utils/exec={pgfmathtruncatemacro{xproj}{sign(x1)}xdefxproj{xproj}
                    pgfmathtruncatemacro{yproj}{sign(x2)}xdefyproj{yproj}
                    pgfmathtruncatemacro{zproj}{sign(cos(tdplotmaintheta))}xdefzproj{zproj}}]}},
                    pics/unit cube/.style={code={
                    path[get projections];
                    draw (0,0,0) -- (1,1,1);
                    ifnumzproj=-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,0)}];
                    fi
                    ifnumyproj=1
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(1,0,0)}];
                    else
                    path[3d cube/every face,3d cube/yz face,unit yz plane={(0,0,0)}];
                    fi
                    ifnumxproj=1
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,0,0)}];
                    else
                    path[3d cube/every face,3d cube/xz face,unit xz plane={(0,1,0)}];
                    fi
                    ifnumzproj>-1
                    path[3d cube/every face,3d cube/xy face,unit xy plane={(0,0,1)}];
                    fi
                    }},
                    3d cube/.cd,
                    xy face/.style={fill=gray!20},
                    xz face/.style={fill=gray!50},
                    yz face/.style={fill=gray!90},
                    every face/.style={draw,very thick}
                    }
                    begin{document}
                    foreach Angle in {5,15,...,355}
                    {tdplotsetmaincoords{60}{Angle} % the first argument cannot be larger than 90
                    begin{tikzpicture}[line join=round]
                    pgfmathtruncatemacro{NumCubes}{7}
                    path[use as bounding box] (-NumCubes/2-3,-NumCubes/2-2)
                    rectangle (NumCubes/2+3,NumCubes/2+4);
                    begin{scope}[tdplot_main_coords]
                    pgfmathtruncatemacro{NextToLast}{NumCubes-1}
                    path[get projections];
                    ifnumyproj=1
                    defLstX{1,2,3}
                    else
                    defLstX{3,2,1}
                    fi
                    ifnumxproj=-1
                    defLstY{1,2,3}
                    else
                    defLstY{3,2,1}
                    fi
                    foreach X in LstX
                    {foreach Y in LstY
                    {ifnumY=3
                    pgfmathtruncatemacro{Zmax}{5-max(X,2)}
                    else
                    pgfmathtruncatemacro{Zmax}{4-X}
                    fi
                    foreach Z in {1,...,Zmax}
                    {path (X-2,Y-2,Z-1) pic{unit cube};}}
                    }
                    end{scope}
                    end{tikzpicture}}
                    end{document}


                    enter image description here







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Apr 1 at 14:11









                    marmotmarmot

                    116k5146277




                    116k5146277













                    • "I would like to argue that one should use orthographic projections". Spoken like a true engineer! +1

                      – Steven B. Segletes
                      Apr 1 at 14:13



















                    • "I would like to argue that one should use orthographic projections". Spoken like a true engineer! +1

                      – Steven B. Segletes
                      Apr 1 at 14:13

















                    "I would like to argue that one should use orthographic projections". Spoken like a true engineer! +1

                    – Steven B. Segletes
                    Apr 1 at 14:13





                    "I would like to argue that one should use orthographic projections". Spoken like a true engineer! +1

                    – Steven B. Segletes
                    Apr 1 at 14:13


















                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f482561%2fincomplete-cube%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Færeyskur hestur Heimild | Tengill | Tilvísanir | LeiðsagnarvalRossið - síða um færeyska hrossið á færeyskuGott ár hjá færeyska hestinum

                    He _____ here since 1970 . Answer needed [closed]What does “since he was so high” mean?Meaning of “catch birds for”?How do I ensure “since” takes the meaning I want?“Who cares here” meaningWhat does “right round toward” mean?the time tense (had now been detected)What does the phrase “ring around the roses” mean here?Correct usage of “visited upon”Meaning of “foiled rail sabotage bid”It was the third time I had gone to Rome or It is the third time I had been to Rome

                    Bunad