How to merge and return new array from object in es6
11
Suppose there are two objects.
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
and the result
{
'1-1':[
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
],
'1-2':[
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
],
'2-1':[
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' },
]
}
Basically, I want to group the data.
I use includes to check if the item from b to match the id from a. Then construct the new array.
This is my attempt(fiddle):
return b.map(item => a.map(jtem => {
if(jtem.id.includes(item)){
return {
[item]: jtem
}
}
}))
For somehow, it doesn't work.
and, is there a clever way to avoid the nested for loop or map function?
javascript ecmascript-6 ecmascript-7
asked yesterday
SPGSPG
2,439103359
add a comment |
11
Suppose there are two objects.
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
and the result
{
'1-1':[
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
],
'1-2':[
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
],
'2-1':[
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' },
]
}
Basically, I want to group the data.
I use includes to check if the item from b to match the id from a. Then construct the new array.
This is my attempt(fiddle):
return b.map(item => a.map(jtem => {
if(jtem.id.includes(item)){
return {
[item]: jtem
}
}
}))
For somehow, it doesn't work.
and, is there a clever way to avoid the nested for loop or map function?
javascript ecmascript-6 ecmascript-7
asked yesterday
SPGSPG
2,439103359
Shouldn't the result be an object?
– Jack Bashford
yesterday
@JackBashford Hey man, sry, u r right, I just updated it.
– SPG
yesterday
Do you really wantincludes? I'd recommendstartsWith
– Bergi
yesterday
@Bergi thx, I thinkstartWithis better
– SPG
10 hours ago
add a comment |
11
11
11
1
Suppose there are two objects.
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
and the result
{
'1-1':[
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
],
'1-2':[
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
],
'2-1':[
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' },
]
}
Basically, I want to group the data.
I use includes to check if the item from b to match the id from a. Then construct the new array.
This is my attempt(fiddle):
return b.map(item => a.map(jtem => {
if(jtem.id.includes(item)){
return {
[item]: jtem
}
}
}))
For somehow, it doesn't work.
and, is there a clever way to avoid the nested for loop or map function?
javascript ecmascript-6 ecmascript-7
asked yesterday
SPGSPG
2,439103359
Suppose there are two objects.
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
and the result
{
'1-1':[
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
],
'1-2':[
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
],
'2-1':[
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' },
]
}
Basically, I want to group the data.
I use includes to check if the item from b to match the id from a. Then construct the new array.
This is my attempt(fiddle):
return b.map(item => a.map(jtem => {
if(jtem.id.includes(item)){
return {
[item]: jtem
}
}
}))
For somehow, it doesn't work.
and, is there a clever way to avoid the nested for loop or map function?
javascript ecmascript-6 ecmascript-7
javascript ecmascript-6 ecmascript-7
asked yesterday
SPGSPG
2,439103359
asked yesterday
SPGSPG
2,439103359
edited yesterday
SPG
asked yesterday
SPGSPG
2,439103359
asked yesterday
SPGSPG
2,439103359
asked yesterday
SPGSPG
2,439103359
2,439103359
Shouldn't the result be an object?
– Jack Bashford
yesterday
@JackBashford Hey man, sry, u r right, I just updated it.
– SPG
yesterday
Do you really wantincludes? I'd recommendstartsWith
– Bergi
yesterday
@Bergi thx, I thinkstartWithis better
– SPG
10 hours ago
add a comment |
Shouldn't the result be an object?
– Jack Bashford
yesterday
@JackBashford Hey man, sry, u r right, I just updated it.
– SPG
yesterday
Do you really wantincludes? I'd recommendstartsWith
– Bergi
yesterday
@Bergi thx, I thinkstartWithis better
– SPG
10 hours ago
Shouldn't the result be an object?
– Jack Bashford
yesterday
Shouldn't the result be an object?
– Jack Bashford
yesterday
@JackBashford Hey man, sry, u r right, I just updated it.
– SPG
yesterday
@JackBashford Hey man, sry, u r right, I just updated it.
– SPG
yesterday
Do you really want
includes? I'd recommend startsWith– Bergi
yesterday
Do you really want
includes? I'd recommend startsWith– Bergi
yesterday
@Bergi thx, I think
startWith is better– SPG
10 hours ago
@Bergi thx, I think
startWith is better– SPG
10 hours ago
add a comment |
1 Answer
1
active
oldest
votes
14
You can do that in following steps:
Apply
reduce()on the arraybDuring each iteration use
filter()on the the arraya- Get all the items from
awhich starts with item ofbusingString.prototype.startsWith()
- At last set it as property of the
acand returnac
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = b.reduce((ac,b) => {
ac[b] = a.filter(x => x.id.startsWith(b));
return ac;
},{})
console.log(res)As suggested by @Falco is the comments that It would be better to scan over the a once as its large. So here is that version.Actually its better regarding performance
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = a.reduce((ac,x) => {
let temp = b.find(y => x.id.startsWith(y))
if(!ac[temp]) ac[temp] = ;
ac[temp].push(x);
return ac;
},{})
console.log(res)Note: startsWith is not supported by I.E. So you can create polyfill using indexOf
if(!String.prototype.startWith){
String.prototype.startsWith = function(str){
return this.indexOf(str) === 0
}
}answered yesterday
Maheer AliMaheer Ali
7,501619
1
While it is specifically said in the question that the op wants to use es6, and that IE don't support es6 features, I just want to mention that startsWith() don't work in IE (while reduce, filter, and setting a property of an object is totally fine if IE > 9) and if someone wants to do the same thing that startsWith do, they can implment their own with some substring :)
– Neyt
yesterday
For bigaand smallbI would probably go witha.reduce(...)because of locality and only scan over the big array once.
– Falco
23 hours ago
@Falco Thanks for suggestion I updated.
– Maheer Ali
23 hours ago
1
@Neyt Thanks for suggestion I updated
– Maheer Ali
23 hours ago
@MaheerAli Thank you - here is a benchmark comparing the two :-) jsbench.me/dfjtoadysr/1
– Falco
23 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
14
You can do that in following steps:
Apply
reduce()on the arraybDuring each iteration use
filter()on the the arraya- Get all the items from
awhich starts with item ofbusingString.prototype.startsWith()
- At last set it as property of the
acand returnac
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = b.reduce((ac,b) => {
ac[b] = a.filter(x => x.id.startsWith(b));
return ac;
},{})
console.log(res)As suggested by @Falco is the comments that It would be better to scan over the a once as its large. So here is that version.Actually its better regarding performance
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = a.reduce((ac,x) => {
let temp = b.find(y => x.id.startsWith(y))
if(!ac[temp]) ac[temp] = ;
ac[temp].push(x);
return ac;
},{})
console.log(res)Note: startsWith is not supported by I.E. So you can create polyfill using indexOf
if(!String.prototype.startWith){
String.prototype.startsWith = function(str){
return this.indexOf(str) === 0
}
}answered yesterday
Maheer AliMaheer Ali
7,501619
1
While it is specifically said in the question that the op wants to use es6, and that IE don't support es6 features, I just want to mention that startsWith() don't work in IE (while reduce, filter, and setting a property of an object is totally fine if IE > 9) and if someone wants to do the same thing that startsWith do, they can implment their own with some substring :)
– Neyt
yesterday
For bigaand smallbI would probably go witha.reduce(...)because of locality and only scan over the big array once.
– Falco
23 hours ago
@Falco Thanks for suggestion I updated.
– Maheer Ali
23 hours ago
1
@Neyt Thanks for suggestion I updated
– Maheer Ali
23 hours ago
@MaheerAli Thank you - here is a benchmark comparing the two :-) jsbench.me/dfjtoadysr/1
– Falco
23 hours ago
add a comment |
14
You can do that in following steps:
Apply
reduce()on the arraybDuring each iteration use
filter()on the the arraya- Get all the items from
awhich starts with item ofbusingString.prototype.startsWith()
- At last set it as property of the
acand returnac
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = b.reduce((ac,b) => {
ac[b] = a.filter(x => x.id.startsWith(b));
return ac;
},{})
console.log(res)As suggested by @Falco is the comments that It would be better to scan over the a once as its large. So here is that version.Actually its better regarding performance
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = a.reduce((ac,x) => {
let temp = b.find(y => x.id.startsWith(y))
if(!ac[temp]) ac[temp] = ;
ac[temp].push(x);
return ac;
},{})
console.log(res)Note: startsWith is not supported by I.E. So you can create polyfill using indexOf
if(!String.prototype.startWith){
String.prototype.startsWith = function(str){
return this.indexOf(str) === 0
}
}answered yesterday
Maheer AliMaheer Ali
7,501619
1
While it is specifically said in the question that the op wants to use es6, and that IE don't support es6 features, I just want to mention that startsWith() don't work in IE (while reduce, filter, and setting a property of an object is totally fine if IE > 9) and if someone wants to do the same thing that startsWith do, they can implment their own with some substring :)
– Neyt
yesterday
For bigaand smallbI would probably go witha.reduce(...)because of locality and only scan over the big array once.
– Falco
23 hours ago
@Falco Thanks for suggestion I updated.
– Maheer Ali
23 hours ago
1
@Neyt Thanks for suggestion I updated
– Maheer Ali
23 hours ago
@MaheerAli Thank you - here is a benchmark comparing the two :-) jsbench.me/dfjtoadysr/1
– Falco
23 hours ago
add a comment |
14
14
14
You can do that in following steps:
Apply
reduce()on the arraybDuring each iteration use
filter()on the the arraya- Get all the items from
awhich starts with item ofbusingString.prototype.startsWith()
- At last set it as property of the
acand returnac
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = b.reduce((ac,b) => {
ac[b] = a.filter(x => x.id.startsWith(b));
return ac;
},{})
console.log(res)As suggested by @Falco is the comments that It would be better to scan over the a once as its large. So here is that version.Actually its better regarding performance
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = a.reduce((ac,x) => {
let temp = b.find(y => x.id.startsWith(y))
if(!ac[temp]) ac[temp] = ;
ac[temp].push(x);
return ac;
},{})
console.log(res)Note: startsWith is not supported by I.E. So you can create polyfill using indexOf
if(!String.prototype.startWith){
String.prototype.startsWith = function(str){
return this.indexOf(str) === 0
}
}answered yesterday
Maheer AliMaheer Ali
7,501619
You can do that in following steps:
Apply
reduce()on the arraybDuring each iteration use
filter()on the the arraya- Get all the items from
awhich starts with item ofbusingString.prototype.startsWith()
- At last set it as property of the
acand returnac
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = b.reduce((ac,b) => {
ac[b] = a.filter(x => x.id.startsWith(b));
return ac;
},{})
console.log(res)As suggested by @Falco is the comments that It would be better to scan over the a once as its large. So here is that version.Actually its better regarding performance
const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = a.reduce((ac,x) => {
let temp = b.find(y => x.id.startsWith(y))
if(!ac[temp]) ac[temp] = ;
ac[temp].push(x);
return ac;
},{})
console.log(res)Note: startsWith is not supported by I.E. So you can create polyfill using indexOf
if(!String.prototype.startWith){
String.prototype.startsWith = function(str){
return this.indexOf(str) === 0
}
}const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = b.reduce((ac,b) => {
ac[b] = a.filter(x => x.id.startsWith(b));
return ac;
},{})
console.log(res)const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = b.reduce((ac,b) => {
ac[b] = a.filter(x => x.id.startsWith(b));
return ac;
},{})
console.log(res)const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = a.reduce((ac,x) => {
let temp = b.find(y => x.id.startsWith(y))
if(!ac[temp]) ac[temp] = ;
ac[temp].push(x);
return ac;
},{})
console.log(res)const a = [
{ id: '1-1-1', name: 'a111' },
{ id: '1-1-2', name: 'a112' },
{ id: '1-2-1', name: 'a121' },
{ id: '1-2-2', name: 'a122' },
{ id: '2-1-1', name: 'a211' },
{ id: '2-1-2', name: 'a212' }
]
const b = ['1-1', '1-2', '2-1']
let res = a.reduce((ac,x) => {
let temp = b.find(y => x.id.startsWith(y))
if(!ac[temp]) ac[temp] = ;
ac[temp].push(x);
return ac;
},{})
console.log(res)if(!String.prototype.startWith){
String.prototype.startsWith = function(str){
return this.indexOf(str) === 0
}
}if(!String.prototype.startWith){
String.prototype.startsWith = function(str){
return this.indexOf(str) === 0
}
}answered yesterday
Maheer AliMaheer Ali
7,501619
edited 19 hours ago
answered yesterday
Maheer AliMaheer Ali
7,501619
answered yesterday
Maheer AliMaheer Ali
7,501619
answered yesterday
Maheer AliMaheer Ali
7,501619
7,501619
1
While it is specifically said in the question that the op wants to use es6, and that IE don't support es6 features, I just want to mention that startsWith() don't work in IE (while reduce, filter, and setting a property of an object is totally fine if IE > 9) and if someone wants to do the same thing that startsWith do, they can implment their own with some substring :)
– Neyt
yesterday
For bigaand smallbI would probably go witha.reduce(...)because of locality and only scan over the big array once.
– Falco
23 hours ago
@Falco Thanks for suggestion I updated.
– Maheer Ali
23 hours ago
1
@Neyt Thanks for suggestion I updated
– Maheer Ali
23 hours ago
@MaheerAli Thank you - here is a benchmark comparing the two :-) jsbench.me/dfjtoadysr/1
– Falco
23 hours ago
add a comment |
1
While it is specifically said in the question that the op wants to use es6, and that IE don't support es6 features, I just want to mention that startsWith() don't work in IE (while reduce, filter, and setting a property of an object is totally fine if IE > 9) and if someone wants to do the same thing that startsWith do, they can implment their own with some substring :)
– Neyt
yesterday
For bigaand smallbI would probably go witha.reduce(...)because of locality and only scan over the big array once.
– Falco
23 hours ago
@Falco Thanks for suggestion I updated.
– Maheer Ali
23 hours ago
1
@Neyt Thanks for suggestion I updated
– Maheer Ali
23 hours ago
@MaheerAli Thank you - here is a benchmark comparing the two :-) jsbench.me/dfjtoadysr/1
– Falco
23 hours ago
1
1
While it is specifically said in the question that the op wants to use es6, and that IE don't support es6 features, I just want to mention that startsWith() don't work in IE (while reduce, filter, and setting a property of an object is totally fine if IE > 9) and if someone wants to do the same thing that startsWith do, they can implment their own with some substring :)
– Neyt
yesterday
While it is specifically said in the question that the op wants to use es6, and that IE don't support es6 features, I just want to mention that startsWith() don't work in IE (while reduce, filter, and setting a property of an object is totally fine if IE > 9) and if someone wants to do the same thing that startsWith do, they can implment their own with some substring :)
– Neyt
yesterday
For big
a and small b I would probably go with a.reduce(...) because of locality and only scan over the big array once.– Falco
23 hours ago
For big
a and small b I would probably go with a.reduce(...) because of locality and only scan over the big array once.– Falco
23 hours ago
@Falco Thanks for suggestion I updated.
– Maheer Ali
23 hours ago
@Falco Thanks for suggestion I updated.
– Maheer Ali
23 hours ago
1
1
@Neyt Thanks for suggestion I updated
– Maheer Ali
23 hours ago
@Neyt Thanks for suggestion I updated
– Maheer Ali
23 hours ago
@MaheerAli Thank you - here is a benchmark comparing the two :-) jsbench.me/dfjtoadysr/1
– Falco
23 hours ago
@MaheerAli Thank you - here is a benchmark comparing the two :-) jsbench.me/dfjtoadysr/1
– Falco
23 hours ago
add a comment |
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Shouldn't the result be an object?
– Jack Bashford
yesterday
@JackBashford Hey man, sry, u r right, I just updated it.
– SPG
yesterday
Do you really want
includes? I'd recommendstartsWith– Bergi
yesterday
@Bergi thx, I think
startWithis better– SPG
10 hours ago