How to extract lower and upper bound in numeric format from a confidence interval string?
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10
Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
asked May 27 at 12:31
FatetaFateta
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10
Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
asked May 27 at 12:31
FatetaFateta
1298 bronze badges
add a comment
|
10
10
10
1
Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
asked May 27 at 12:31
FatetaFateta
1298 bronze badges
Suppose a vector including some confidence intervals as below
confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")
I want to have two new vectors one including the lower Limits in numeric format as
lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)
and othe including the upper Limits in numeric format like
upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)
r
r
asked May 27 at 12:31
FatetaFateta
1298 bronze badges
asked May 27 at 12:31
FatetaFateta
1298 bronze badges
asked May 27 at 12:31
FatetaFateta
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asked May 27 at 12:31
FatetaFateta
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asked May 27 at 12:31
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6 Answers
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12
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
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3
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
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2
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment
|
2
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
Thank you all!
answered May 27 at 13:22
FatetaFateta
1298 bronze badges
add a comment
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1
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
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1
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
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6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
12
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
25.7k9 gold badges24 silver badges46 bronze badges
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12
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
25.7k9 gold badges24 silver badges46 bronze badges
add a comment
|
12
12
12
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
25.7k9 gold badges24 silver badges46 bronze badges
A base R solution
lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))
lower
[1] 0.741 263.917 12.788 0.680 0.650 0.719
upper
[1] 2.233 402.154 17.975 2.450 1.827 2.190
answered May 27 at 12:41
G5WG5W
25.7k9 gold badges24 silver badges46 bronze badges
edited May 27 at 12:45
answered May 27 at 12:41
G5WG5W
25.7k9 gold badges24 silver badges46 bronze badges
answered May 27 at 12:41
G5WG5W
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answered May 27 at 12:41
G5WG5W
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3
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
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3
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
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3
3
3
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
2401 silver badge8 bronze badges
mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
as.numeric(gsub(mypattern, '\1', confint))
as.numeric(gsub(mypattern, '\2', confint))
answered May 27 at 12:52
pzhaopzhao
2401 silver badge8 bronze badges
answered May 27 at 12:52
pzhaopzhao
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answered May 27 at 12:52
pzhaopzhao
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answered May 27 at 12:52
pzhaopzhao
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2
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment
|
2
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment
|
2
2
2
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
A different base R possibility could be:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])
[1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
[1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"
If you need it as a numeric vector:
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
edited May 27 at 12:58
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
answered May 27 at 12:49
tmfmnktmfmnk
12.1k1 gold badge10 silver badges25 bronze badges
12.1k1 gold badge10 silver badges25 bronze badges
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment
|
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
@Ronak Shah I updated my post according some of your ideas. Thank you :)
– tmfmnk
May 27 at 12:59
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.
– Ronak Shah
May 27 at 13:21
add a comment
|
2
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
Thank you all!
answered May 27 at 13:22
FatetaFateta
1298 bronze badges
add a comment
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2
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
Thank you all!
answered May 27 at 13:22
FatetaFateta
1298 bronze badges
add a comment
|
2
2
2
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
Thank you all!
answered May 27 at 13:22
FatetaFateta
1298 bronze badges
Meanwhile, I came up with another base R solution
lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))
Thank you all!
answered May 27 at 13:22
FatetaFateta
1298 bronze badges
edited Jun 11 at 5:31
answered May 27 at 13:22
FatetaFateta
1298 bronze badges
answered May 27 at 13:22
FatetaFateta
1298 bronze badges
answered May 27 at 13:22
FatetaFateta
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1298 bronze badges
add a comment
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add a comment
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1
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,5142 gold badges7 silver badges21 bronze badges
add a comment
|
1
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,5142 gold badges7 silver badges21 bronze badges
add a comment
|
1
1
1
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,5142 gold badges7 silver badges21 bronze badges
You can use functions from the stringr library.
You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.
str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
# [1] 0.741 263.917 12.788 0.680 0.650 0.719
answered May 27 at 12:38
demarsylvaindemarsylvain
1,5142 gold badges7 silver badges21 bronze badges
edited May 27 at 12:45
answered May 27 at 12:38
demarsylvaindemarsylvain
1,5142 gold badges7 silver badges21 bronze badges
answered May 27 at 12:38
demarsylvaindemarsylvain
1,5142 gold badges7 silver badges21 bronze badges
answered May 27 at 12:38
demarsylvaindemarsylvain
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1,5142 gold badges7 silver badges21 bronze badges
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add a comment
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1
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
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add a comment
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1
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
1,2405 silver badges16 bronze badges
add a comment
|
1
1
1
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
1,2405 silver badges16 bronze badges
A tidyverse solution:
library(dplyr)
library(tidyr)
df = data.frame(confint)
df = df %>%
mutate(confint = gsub("(\[|\])","",confint)) %>%
separate(confint,c("lower","upper"),";",convert=T)
answered May 27 at 14:12
FinoFino
1,2405 silver badges16 bronze badges
answered May 27 at 14:12
FinoFino
1,2405 silver badges16 bronze badges
answered May 27 at 14:12
FinoFino
1,2405 silver badges16 bronze badges
answered May 27 at 14:12
FinoFino
1,2405 silver badges16 bronze badges
1,2405 silver badges16 bronze badges
add a comment
|
add a comment
|
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