How can I find where certain bash function is defined?
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There are many functions that can be used in Bash shell. Their definitions can be listed by set
, but how to find in which files certain user defined functions are defined?
bash functions
add a comment |
There are many functions that can be used in Bash shell. Their definitions can be listed by set
, but how to find in which files certain user defined functions are defined?
bash functions
1
Look at: askubuntu.com/questions/463462/…
– FedonKadifeli
May 26 at 9:49
add a comment |
There are many functions that can be used in Bash shell. Their definitions can be listed by set
, but how to find in which files certain user defined functions are defined?
bash functions
There are many functions that can be used in Bash shell. Their definitions can be listed by set
, but how to find in which files certain user defined functions are defined?
bash functions
bash functions
asked May 26 at 9:23
jarnojarno
2,1463 gold badges22 silver badges52 bronze badges
2,1463 gold badges22 silver badges52 bronze badges
1
Look at: askubuntu.com/questions/463462/…
– FedonKadifeli
May 26 at 9:49
add a comment |
1
Look at: askubuntu.com/questions/463462/…
– FedonKadifeli
May 26 at 9:49
1
1
Look at: askubuntu.com/questions/463462/…
– FedonKadifeli
May 26 at 9:49
Look at: askubuntu.com/questions/463462/…
– FedonKadifeli
May 26 at 9:49
add a comment |
3 Answers
3
active
oldest
votes
Turn on debugging. From the Bash manual:
extdebug
If set at shell invocation, or in a shell startup file, arrange to
execute the debugger profile before the shell starts, identical to the
--debugger
option. If set after invocation, behavior intended for
use by debuggers is enabled:
- The
-F
option to thedeclare
builtin (see Bash Builtins) displays the source file name and line number corresponding to each
function name supplied as an argument.
Example:
$ bash --debugger
$ declare -Ff quote
quote 143 /usr/share/bash-completion/bash_completion
And indeed:
$ nl -ba /usr/share/bash-completion/bash_completion | sed -n 143,150p
143 quote()
144 {
145 local quoted=${1//'/'\''}
146 printf "'%s'" "$quoted"
147 }
148
149 # @see _quote_readline_by_ref()
150 quote_readline()
This is a great and simple solution. As for your example, it is not even needed to start a new shell:shopt -s extdebug; declare -Ff quote; shopt -u extdebug
.
– jarno
May 26 at 13:36
2
@jarno ah, well, contrary to my name, I use zsh. That's why I started a new shell. :D
– bashity mcbashface
May 26 at 13:48
Is there a similar method to find alias declaration locations?
– FedonKadifeli
May 26 at 15:31
@fedon my convoluted and complicated approach below should work.
– terdon♦
May 26 at 15:58
You could make this a function like this:find_function()( shopt -s extdebug; declare -F "$@"; )
. With the parens on the function body, it gets executed in a subshell and the change to shopts doesn't affect the caller. And the-f
doesn't seem to be needed.
– wjandrea
May 27 at 18:16
add a comment |
This is actually more complicated than it appears at first. Which files are read by your shell depends on what type of shell you are currently running. Whether it is interactive or not, whether it is a login or a non-login shell and what combination of the above. To search through all the default files that can be read by the different shells, you can do (change $functionName
to the actual name of the function you are looking for):
grep "$functionName" ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
If that doesn't work, you may be calling a non-default file using .
or its alias source
. To find such cases, run:
grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases /etc/bash.bashrc
/etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
That probably needs some explanation. The -P
enables Perl Compatible Regular Expressions (PCRE) which let us use some fancier regex syntax. Specifically:
(^|s)
: match either the beginning of a line (^
) or whitespace (s
).
(.|source)s+
: match either a literal.
character (.
) or the wordsource
, but only if they are followed by one or more whitespace characters.
Here's what that gives me on my system:
$ grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases /etc/bash.bashrc
> /etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
/home/terdon/.bashrc: . /etc/bashrc
/home/terdon/.bashrc: . /etc/bash_completion
/home/terdon/.bashrc:. $HOME/scripts/git-prompt.sh
/home/terdon/.bashrc:# echo -n "$n : "; grep "^CA" $n |perl -e 'my ($a,$c)=0; while(<>){$c++;next if /cellular_component_unknown/; next if /biological_process/; $a++} print "$a Classes of $c annotated (" . $a*100/$c . ")n"'
/etc/bash.bashrc:[ -r /usr/share/bash-completion/bash_completion ] && . /usr/share/bash-completion/bash_completion
/etc/profile: test -r "$profile" && . "$profile"
/etc/profile: . /etc/bash.bashrc
/etc/profile.d/locale.sh: . "$XDG_CONFIG_HOME/locale.conf"
/etc/profile.d/locale.sh: . "$HOME/.config/locale.conf"
/etc/profile.d/locale.sh: . /etc/locale.conf
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
As you can see, however, this will print the entire matched line. What we are really interested in is the list of file names called, not the line that is calling them. You can get those with this, more complicated, regex:
grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases
/etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
The -h
flag suppresses the printing of the file names where a match was found, which grep
does by default when told to search through multiple files. The -o
means "only print the matching portion of the line". The extra stuff added to the regex are:
K
: ignore anything matched up to this point. This is a PCRE trick that lets you use a complex regex to find your match but not include that matched portion when using grep's-o
flag.
On my system, the above command will return:
$ grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases
> /etc/bash.bashrc /etc/profile
> /etc/profile.d/* /etc/environment 2> /dev/null
/etc/bashrc
/etc/bash_completion
$HOME/scripts/git-prompt.sh
$a*100/$c
")n"'
/usr/share/bash-completion/bash_completion
"$profile"
/etc/bash.bashrc
"$XDG_CONFIG_HOME/locale.conf"
"$HOME/.config/locale.conf"
/etc/locale.conf
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
Note that I happen to have a use of .
followed by a space which is not used for sourcing but that's because I have an alias that is calling another language, not bash. That's what gives the weird $a*100/$c
and ")n"'
in the output above. But that can be ignored.
Finally, here's how to put all of that together and search for a function name in all default files and all files your default files are sourcing:
grep_function(){
target="$@"
files=( ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment)
while IFS= read -r file; do
files+=( "$file" )
done < <(grep -hPo '(^|s)(.|source)s+KS+' "${files[@]}" 2>/dev/null)
for file in "${files[@]}"; do
## The tilde of ~/ can break this
file=$(sed 's|~/|'"$HOME"'/|g' <<<"$file")
if [[ -e $file ]]; then
grep -H "$target" -- "$file"
fi
done
}
Add those lines to your ~/.bashrc
and you can then run (I am using fooBar
as an example function name):
grep_function fooBar
For example, if I have this line in my ~/.bashrc
:
. ~/a
And the file ~/a
is:
$ cat ~/a
fooBar(){
echo foo
}
I should find it with:
$ grep_function fooBar
/home/terdon/a:fooBar(){
Your solution is a great educational scripting example, but I find bashity mcbashface's solution simpler.
– jarno
May 26 at 13:40
@jarno and it is much, much simpler! :)
– terdon♦
May 26 at 14:09
Arrays support+=
– D. Ben Knoble
May 27 at 15:16
@D.BenKnoble they do? You mean other thanarray+="foo"
appending the stringfoo
to the 1st element of the array?
– terdon♦
May 27 at 19:31
1
@D.BenKnoble thanks! I didn't know bash arrays supported that notation!
– terdon♦
May 28 at 12:43
|
show 1 more comment
The usual per-user dotfile bash
reads is ~/.bashrc
. However, it may very well source other files, I for instance like to keep aliases and functions in separate files called ~/.bash_aliases
and ~/.bash_functions
, which makes finding them much easier. You can search the .bashrc
for source
commands with:
grep -E '(^s*|s)(.|source)s' /home/USERNAME/.bashrc
Once you have the list of user-created files you can search them and the user’s .bashrc
with a single grep
call, e.g. for function foo
for my setup:
grep foo /home/USERNAME/.bash{rc,_aliases,_functions}
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Turn on debugging. From the Bash manual:
extdebug
If set at shell invocation, or in a shell startup file, arrange to
execute the debugger profile before the shell starts, identical to the
--debugger
option. If set after invocation, behavior intended for
use by debuggers is enabled:
- The
-F
option to thedeclare
builtin (see Bash Builtins) displays the source file name and line number corresponding to each
function name supplied as an argument.
Example:
$ bash --debugger
$ declare -Ff quote
quote 143 /usr/share/bash-completion/bash_completion
And indeed:
$ nl -ba /usr/share/bash-completion/bash_completion | sed -n 143,150p
143 quote()
144 {
145 local quoted=${1//'/'\''}
146 printf "'%s'" "$quoted"
147 }
148
149 # @see _quote_readline_by_ref()
150 quote_readline()
This is a great and simple solution. As for your example, it is not even needed to start a new shell:shopt -s extdebug; declare -Ff quote; shopt -u extdebug
.
– jarno
May 26 at 13:36
2
@jarno ah, well, contrary to my name, I use zsh. That's why I started a new shell. :D
– bashity mcbashface
May 26 at 13:48
Is there a similar method to find alias declaration locations?
– FedonKadifeli
May 26 at 15:31
@fedon my convoluted and complicated approach below should work.
– terdon♦
May 26 at 15:58
You could make this a function like this:find_function()( shopt -s extdebug; declare -F "$@"; )
. With the parens on the function body, it gets executed in a subshell and the change to shopts doesn't affect the caller. And the-f
doesn't seem to be needed.
– wjandrea
May 27 at 18:16
add a comment |
Turn on debugging. From the Bash manual:
extdebug
If set at shell invocation, or in a shell startup file, arrange to
execute the debugger profile before the shell starts, identical to the
--debugger
option. If set after invocation, behavior intended for
use by debuggers is enabled:
- The
-F
option to thedeclare
builtin (see Bash Builtins) displays the source file name and line number corresponding to each
function name supplied as an argument.
Example:
$ bash --debugger
$ declare -Ff quote
quote 143 /usr/share/bash-completion/bash_completion
And indeed:
$ nl -ba /usr/share/bash-completion/bash_completion | sed -n 143,150p
143 quote()
144 {
145 local quoted=${1//'/'\''}
146 printf "'%s'" "$quoted"
147 }
148
149 # @see _quote_readline_by_ref()
150 quote_readline()
This is a great and simple solution. As for your example, it is not even needed to start a new shell:shopt -s extdebug; declare -Ff quote; shopt -u extdebug
.
– jarno
May 26 at 13:36
2
@jarno ah, well, contrary to my name, I use zsh. That's why I started a new shell. :D
– bashity mcbashface
May 26 at 13:48
Is there a similar method to find alias declaration locations?
– FedonKadifeli
May 26 at 15:31
@fedon my convoluted and complicated approach below should work.
– terdon♦
May 26 at 15:58
You could make this a function like this:find_function()( shopt -s extdebug; declare -F "$@"; )
. With the parens on the function body, it gets executed in a subshell and the change to shopts doesn't affect the caller. And the-f
doesn't seem to be needed.
– wjandrea
May 27 at 18:16
add a comment |
Turn on debugging. From the Bash manual:
extdebug
If set at shell invocation, or in a shell startup file, arrange to
execute the debugger profile before the shell starts, identical to the
--debugger
option. If set after invocation, behavior intended for
use by debuggers is enabled:
- The
-F
option to thedeclare
builtin (see Bash Builtins) displays the source file name and line number corresponding to each
function name supplied as an argument.
Example:
$ bash --debugger
$ declare -Ff quote
quote 143 /usr/share/bash-completion/bash_completion
And indeed:
$ nl -ba /usr/share/bash-completion/bash_completion | sed -n 143,150p
143 quote()
144 {
145 local quoted=${1//'/'\''}
146 printf "'%s'" "$quoted"
147 }
148
149 # @see _quote_readline_by_ref()
150 quote_readline()
Turn on debugging. From the Bash manual:
extdebug
If set at shell invocation, or in a shell startup file, arrange to
execute the debugger profile before the shell starts, identical to the
--debugger
option. If set after invocation, behavior intended for
use by debuggers is enabled:
- The
-F
option to thedeclare
builtin (see Bash Builtins) displays the source file name and line number corresponding to each
function name supplied as an argument.
Example:
$ bash --debugger
$ declare -Ff quote
quote 143 /usr/share/bash-completion/bash_completion
And indeed:
$ nl -ba /usr/share/bash-completion/bash_completion | sed -n 143,150p
143 quote()
144 {
145 local quoted=${1//'/'\''}
146 printf "'%s'" "$quoted"
147 }
148
149 # @see _quote_readline_by_ref()
150 quote_readline()
answered May 26 at 12:53
bashity mcbashfacebashity mcbashface
3261 silver badge2 bronze badges
3261 silver badge2 bronze badges
This is a great and simple solution. As for your example, it is not even needed to start a new shell:shopt -s extdebug; declare -Ff quote; shopt -u extdebug
.
– jarno
May 26 at 13:36
2
@jarno ah, well, contrary to my name, I use zsh. That's why I started a new shell. :D
– bashity mcbashface
May 26 at 13:48
Is there a similar method to find alias declaration locations?
– FedonKadifeli
May 26 at 15:31
@fedon my convoluted and complicated approach below should work.
– terdon♦
May 26 at 15:58
You could make this a function like this:find_function()( shopt -s extdebug; declare -F "$@"; )
. With the parens on the function body, it gets executed in a subshell and the change to shopts doesn't affect the caller. And the-f
doesn't seem to be needed.
– wjandrea
May 27 at 18:16
add a comment |
This is a great and simple solution. As for your example, it is not even needed to start a new shell:shopt -s extdebug; declare -Ff quote; shopt -u extdebug
.
– jarno
May 26 at 13:36
2
@jarno ah, well, contrary to my name, I use zsh. That's why I started a new shell. :D
– bashity mcbashface
May 26 at 13:48
Is there a similar method to find alias declaration locations?
– FedonKadifeli
May 26 at 15:31
@fedon my convoluted and complicated approach below should work.
– terdon♦
May 26 at 15:58
You could make this a function like this:find_function()( shopt -s extdebug; declare -F "$@"; )
. With the parens on the function body, it gets executed in a subshell and the change to shopts doesn't affect the caller. And the-f
doesn't seem to be needed.
– wjandrea
May 27 at 18:16
This is a great and simple solution. As for your example, it is not even needed to start a new shell:
shopt -s extdebug; declare -Ff quote; shopt -u extdebug
.– jarno
May 26 at 13:36
This is a great and simple solution. As for your example, it is not even needed to start a new shell:
shopt -s extdebug; declare -Ff quote; shopt -u extdebug
.– jarno
May 26 at 13:36
2
2
@jarno ah, well, contrary to my name, I use zsh. That's why I started a new shell. :D
– bashity mcbashface
May 26 at 13:48
@jarno ah, well, contrary to my name, I use zsh. That's why I started a new shell. :D
– bashity mcbashface
May 26 at 13:48
Is there a similar method to find alias declaration locations?
– FedonKadifeli
May 26 at 15:31
Is there a similar method to find alias declaration locations?
– FedonKadifeli
May 26 at 15:31
@fedon my convoluted and complicated approach below should work.
– terdon♦
May 26 at 15:58
@fedon my convoluted and complicated approach below should work.
– terdon♦
May 26 at 15:58
You could make this a function like this:
find_function()( shopt -s extdebug; declare -F "$@"; )
. With the parens on the function body, it gets executed in a subshell and the change to shopts doesn't affect the caller. And the -f
doesn't seem to be needed.– wjandrea
May 27 at 18:16
You could make this a function like this:
find_function()( shopt -s extdebug; declare -F "$@"; )
. With the parens on the function body, it gets executed in a subshell and the change to shopts doesn't affect the caller. And the -f
doesn't seem to be needed.– wjandrea
May 27 at 18:16
add a comment |
This is actually more complicated than it appears at first. Which files are read by your shell depends on what type of shell you are currently running. Whether it is interactive or not, whether it is a login or a non-login shell and what combination of the above. To search through all the default files that can be read by the different shells, you can do (change $functionName
to the actual name of the function you are looking for):
grep "$functionName" ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
If that doesn't work, you may be calling a non-default file using .
or its alias source
. To find such cases, run:
grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases /etc/bash.bashrc
/etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
That probably needs some explanation. The -P
enables Perl Compatible Regular Expressions (PCRE) which let us use some fancier regex syntax. Specifically:
(^|s)
: match either the beginning of a line (^
) or whitespace (s
).
(.|source)s+
: match either a literal.
character (.
) or the wordsource
, but only if they are followed by one or more whitespace characters.
Here's what that gives me on my system:
$ grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases /etc/bash.bashrc
> /etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
/home/terdon/.bashrc: . /etc/bashrc
/home/terdon/.bashrc: . /etc/bash_completion
/home/terdon/.bashrc:. $HOME/scripts/git-prompt.sh
/home/terdon/.bashrc:# echo -n "$n : "; grep "^CA" $n |perl -e 'my ($a,$c)=0; while(<>){$c++;next if /cellular_component_unknown/; next if /biological_process/; $a++} print "$a Classes of $c annotated (" . $a*100/$c . ")n"'
/etc/bash.bashrc:[ -r /usr/share/bash-completion/bash_completion ] && . /usr/share/bash-completion/bash_completion
/etc/profile: test -r "$profile" && . "$profile"
/etc/profile: . /etc/bash.bashrc
/etc/profile.d/locale.sh: . "$XDG_CONFIG_HOME/locale.conf"
/etc/profile.d/locale.sh: . "$HOME/.config/locale.conf"
/etc/profile.d/locale.sh: . /etc/locale.conf
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
As you can see, however, this will print the entire matched line. What we are really interested in is the list of file names called, not the line that is calling them. You can get those with this, more complicated, regex:
grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases
/etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
The -h
flag suppresses the printing of the file names where a match was found, which grep
does by default when told to search through multiple files. The -o
means "only print the matching portion of the line". The extra stuff added to the regex are:
K
: ignore anything matched up to this point. This is a PCRE trick that lets you use a complex regex to find your match but not include that matched portion when using grep's-o
flag.
On my system, the above command will return:
$ grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases
> /etc/bash.bashrc /etc/profile
> /etc/profile.d/* /etc/environment 2> /dev/null
/etc/bashrc
/etc/bash_completion
$HOME/scripts/git-prompt.sh
$a*100/$c
")n"'
/usr/share/bash-completion/bash_completion
"$profile"
/etc/bash.bashrc
"$XDG_CONFIG_HOME/locale.conf"
"$HOME/.config/locale.conf"
/etc/locale.conf
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
Note that I happen to have a use of .
followed by a space which is not used for sourcing but that's because I have an alias that is calling another language, not bash. That's what gives the weird $a*100/$c
and ")n"'
in the output above. But that can be ignored.
Finally, here's how to put all of that together and search for a function name in all default files and all files your default files are sourcing:
grep_function(){
target="$@"
files=( ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment)
while IFS= read -r file; do
files+=( "$file" )
done < <(grep -hPo '(^|s)(.|source)s+KS+' "${files[@]}" 2>/dev/null)
for file in "${files[@]}"; do
## The tilde of ~/ can break this
file=$(sed 's|~/|'"$HOME"'/|g' <<<"$file")
if [[ -e $file ]]; then
grep -H "$target" -- "$file"
fi
done
}
Add those lines to your ~/.bashrc
and you can then run (I am using fooBar
as an example function name):
grep_function fooBar
For example, if I have this line in my ~/.bashrc
:
. ~/a
And the file ~/a
is:
$ cat ~/a
fooBar(){
echo foo
}
I should find it with:
$ grep_function fooBar
/home/terdon/a:fooBar(){
Your solution is a great educational scripting example, but I find bashity mcbashface's solution simpler.
– jarno
May 26 at 13:40
@jarno and it is much, much simpler! :)
– terdon♦
May 26 at 14:09
Arrays support+=
– D. Ben Knoble
May 27 at 15:16
@D.BenKnoble they do? You mean other thanarray+="foo"
appending the stringfoo
to the 1st element of the array?
– terdon♦
May 27 at 19:31
1
@D.BenKnoble thanks! I didn't know bash arrays supported that notation!
– terdon♦
May 28 at 12:43
|
show 1 more comment
This is actually more complicated than it appears at first. Which files are read by your shell depends on what type of shell you are currently running. Whether it is interactive or not, whether it is a login or a non-login shell and what combination of the above. To search through all the default files that can be read by the different shells, you can do (change $functionName
to the actual name of the function you are looking for):
grep "$functionName" ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
If that doesn't work, you may be calling a non-default file using .
or its alias source
. To find such cases, run:
grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases /etc/bash.bashrc
/etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
That probably needs some explanation. The -P
enables Perl Compatible Regular Expressions (PCRE) which let us use some fancier regex syntax. Specifically:
(^|s)
: match either the beginning of a line (^
) or whitespace (s
).
(.|source)s+
: match either a literal.
character (.
) or the wordsource
, but only if they are followed by one or more whitespace characters.
Here's what that gives me on my system:
$ grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases /etc/bash.bashrc
> /etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
/home/terdon/.bashrc: . /etc/bashrc
/home/terdon/.bashrc: . /etc/bash_completion
/home/terdon/.bashrc:. $HOME/scripts/git-prompt.sh
/home/terdon/.bashrc:# echo -n "$n : "; grep "^CA" $n |perl -e 'my ($a,$c)=0; while(<>){$c++;next if /cellular_component_unknown/; next if /biological_process/; $a++} print "$a Classes of $c annotated (" . $a*100/$c . ")n"'
/etc/bash.bashrc:[ -r /usr/share/bash-completion/bash_completion ] && . /usr/share/bash-completion/bash_completion
/etc/profile: test -r "$profile" && . "$profile"
/etc/profile: . /etc/bash.bashrc
/etc/profile.d/locale.sh: . "$XDG_CONFIG_HOME/locale.conf"
/etc/profile.d/locale.sh: . "$HOME/.config/locale.conf"
/etc/profile.d/locale.sh: . /etc/locale.conf
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
As you can see, however, this will print the entire matched line. What we are really interested in is the list of file names called, not the line that is calling them. You can get those with this, more complicated, regex:
grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases
/etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
The -h
flag suppresses the printing of the file names where a match was found, which grep
does by default when told to search through multiple files. The -o
means "only print the matching portion of the line". The extra stuff added to the regex are:
K
: ignore anything matched up to this point. This is a PCRE trick that lets you use a complex regex to find your match but not include that matched portion when using grep's-o
flag.
On my system, the above command will return:
$ grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases
> /etc/bash.bashrc /etc/profile
> /etc/profile.d/* /etc/environment 2> /dev/null
/etc/bashrc
/etc/bash_completion
$HOME/scripts/git-prompt.sh
$a*100/$c
")n"'
/usr/share/bash-completion/bash_completion
"$profile"
/etc/bash.bashrc
"$XDG_CONFIG_HOME/locale.conf"
"$HOME/.config/locale.conf"
/etc/locale.conf
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
Note that I happen to have a use of .
followed by a space which is not used for sourcing but that's because I have an alias that is calling another language, not bash. That's what gives the weird $a*100/$c
and ")n"'
in the output above. But that can be ignored.
Finally, here's how to put all of that together and search for a function name in all default files and all files your default files are sourcing:
grep_function(){
target="$@"
files=( ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment)
while IFS= read -r file; do
files+=( "$file" )
done < <(grep -hPo '(^|s)(.|source)s+KS+' "${files[@]}" 2>/dev/null)
for file in "${files[@]}"; do
## The tilde of ~/ can break this
file=$(sed 's|~/|'"$HOME"'/|g' <<<"$file")
if [[ -e $file ]]; then
grep -H "$target" -- "$file"
fi
done
}
Add those lines to your ~/.bashrc
and you can then run (I am using fooBar
as an example function name):
grep_function fooBar
For example, if I have this line in my ~/.bashrc
:
. ~/a
And the file ~/a
is:
$ cat ~/a
fooBar(){
echo foo
}
I should find it with:
$ grep_function fooBar
/home/terdon/a:fooBar(){
Your solution is a great educational scripting example, but I find bashity mcbashface's solution simpler.
– jarno
May 26 at 13:40
@jarno and it is much, much simpler! :)
– terdon♦
May 26 at 14:09
Arrays support+=
– D. Ben Knoble
May 27 at 15:16
@D.BenKnoble they do? You mean other thanarray+="foo"
appending the stringfoo
to the 1st element of the array?
– terdon♦
May 27 at 19:31
1
@D.BenKnoble thanks! I didn't know bash arrays supported that notation!
– terdon♦
May 28 at 12:43
|
show 1 more comment
This is actually more complicated than it appears at first. Which files are read by your shell depends on what type of shell you are currently running. Whether it is interactive or not, whether it is a login or a non-login shell and what combination of the above. To search through all the default files that can be read by the different shells, you can do (change $functionName
to the actual name of the function you are looking for):
grep "$functionName" ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
If that doesn't work, you may be calling a non-default file using .
or its alias source
. To find such cases, run:
grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases /etc/bash.bashrc
/etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
That probably needs some explanation. The -P
enables Perl Compatible Regular Expressions (PCRE) which let us use some fancier regex syntax. Specifically:
(^|s)
: match either the beginning of a line (^
) or whitespace (s
).
(.|source)s+
: match either a literal.
character (.
) or the wordsource
, but only if they are followed by one or more whitespace characters.
Here's what that gives me on my system:
$ grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases /etc/bash.bashrc
> /etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
/home/terdon/.bashrc: . /etc/bashrc
/home/terdon/.bashrc: . /etc/bash_completion
/home/terdon/.bashrc:. $HOME/scripts/git-prompt.sh
/home/terdon/.bashrc:# echo -n "$n : "; grep "^CA" $n |perl -e 'my ($a,$c)=0; while(<>){$c++;next if /cellular_component_unknown/; next if /biological_process/; $a++} print "$a Classes of $c annotated (" . $a*100/$c . ")n"'
/etc/bash.bashrc:[ -r /usr/share/bash-completion/bash_completion ] && . /usr/share/bash-completion/bash_completion
/etc/profile: test -r "$profile" && . "$profile"
/etc/profile: . /etc/bash.bashrc
/etc/profile.d/locale.sh: . "$XDG_CONFIG_HOME/locale.conf"
/etc/profile.d/locale.sh: . "$HOME/.config/locale.conf"
/etc/profile.d/locale.sh: . /etc/locale.conf
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
As you can see, however, this will print the entire matched line. What we are really interested in is the list of file names called, not the line that is calling them. You can get those with this, more complicated, regex:
grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases
/etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
The -h
flag suppresses the printing of the file names where a match was found, which grep
does by default when told to search through multiple files. The -o
means "only print the matching portion of the line". The extra stuff added to the regex are:
K
: ignore anything matched up to this point. This is a PCRE trick that lets you use a complex regex to find your match but not include that matched portion when using grep's-o
flag.
On my system, the above command will return:
$ grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases
> /etc/bash.bashrc /etc/profile
> /etc/profile.d/* /etc/environment 2> /dev/null
/etc/bashrc
/etc/bash_completion
$HOME/scripts/git-prompt.sh
$a*100/$c
")n"'
/usr/share/bash-completion/bash_completion
"$profile"
/etc/bash.bashrc
"$XDG_CONFIG_HOME/locale.conf"
"$HOME/.config/locale.conf"
/etc/locale.conf
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
Note that I happen to have a use of .
followed by a space which is not used for sourcing but that's because I have an alias that is calling another language, not bash. That's what gives the weird $a*100/$c
and ")n"'
in the output above. But that can be ignored.
Finally, here's how to put all of that together and search for a function name in all default files and all files your default files are sourcing:
grep_function(){
target="$@"
files=( ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment)
while IFS= read -r file; do
files+=( "$file" )
done < <(grep -hPo '(^|s)(.|source)s+KS+' "${files[@]}" 2>/dev/null)
for file in "${files[@]}"; do
## The tilde of ~/ can break this
file=$(sed 's|~/|'"$HOME"'/|g' <<<"$file")
if [[ -e $file ]]; then
grep -H "$target" -- "$file"
fi
done
}
Add those lines to your ~/.bashrc
and you can then run (I am using fooBar
as an example function name):
grep_function fooBar
For example, if I have this line in my ~/.bashrc
:
. ~/a
And the file ~/a
is:
$ cat ~/a
fooBar(){
echo foo
}
I should find it with:
$ grep_function fooBar
/home/terdon/a:fooBar(){
This is actually more complicated than it appears at first. Which files are read by your shell depends on what type of shell you are currently running. Whether it is interactive or not, whether it is a login or a non-login shell and what combination of the above. To search through all the default files that can be read by the different shells, you can do (change $functionName
to the actual name of the function you are looking for):
grep "$functionName" ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
If that doesn't work, you may be calling a non-default file using .
or its alias source
. To find such cases, run:
grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases /etc/bash.bashrc
/etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
That probably needs some explanation. The -P
enables Perl Compatible Regular Expressions (PCRE) which let us use some fancier regex syntax. Specifically:
(^|s)
: match either the beginning of a line (^
) or whitespace (s
).
(.|source)s+
: match either a literal.
character (.
) or the wordsource
, but only if they are followed by one or more whitespace characters.
Here's what that gives me on my system:
$ grep -P '(^|s)(.|source)s+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases /etc/bash.bashrc
> /etc/profile /etc/profile.d/* /etc/environment 2> /dev/null
/home/terdon/.bashrc: . /etc/bashrc
/home/terdon/.bashrc: . /etc/bash_completion
/home/terdon/.bashrc:. $HOME/scripts/git-prompt.sh
/home/terdon/.bashrc:# echo -n "$n : "; grep "^CA" $n |perl -e 'my ($a,$c)=0; while(<>){$c++;next if /cellular_component_unknown/; next if /biological_process/; $a++} print "$a Classes of $c annotated (" . $a*100/$c . ")n"'
/etc/bash.bashrc:[ -r /usr/share/bash-completion/bash_completion ] && . /usr/share/bash-completion/bash_completion
/etc/profile: test -r "$profile" && . "$profile"
/etc/profile: . /etc/bash.bashrc
/etc/profile.d/locale.sh: . "$XDG_CONFIG_HOME/locale.conf"
/etc/profile.d/locale.sh: . "$HOME/.config/locale.conf"
/etc/profile.d/locale.sh: . /etc/locale.conf
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
/etc/profile.d/Z97-byobu.sh: . /usr/bin/byobu-launch
As you can see, however, this will print the entire matched line. What we are really interested in is the list of file names called, not the line that is calling them. You can get those with this, more complicated, regex:
grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
~/.bash.login ~/.bash_aliases
/etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment 2> /dev/null
The -h
flag suppresses the printing of the file names where a match was found, which grep
does by default when told to search through multiple files. The -o
means "only print the matching portion of the line". The extra stuff added to the regex are:
K
: ignore anything matched up to this point. This is a PCRE trick that lets you use a complex regex to find your match but not include that matched portion when using grep's-o
flag.
On my system, the above command will return:
$ grep -hPo '(^|s)(.|source)s+KS+' ~/.bashrc ~/.profile ~/.bash_profile
> ~/.bash.login ~/.bash_aliases
> /etc/bash.bashrc /etc/profile
> /etc/profile.d/* /etc/environment 2> /dev/null
/etc/bashrc
/etc/bash_completion
$HOME/scripts/git-prompt.sh
$a*100/$c
")n"'
/usr/share/bash-completion/bash_completion
"$profile"
/etc/bash.bashrc
"$XDG_CONFIG_HOME/locale.conf"
"$HOME/.config/locale.conf"
/etc/locale.conf
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
/usr/bin/byobu-launch
Note that I happen to have a use of .
followed by a space which is not used for sourcing but that's because I have an alias that is calling another language, not bash. That's what gives the weird $a*100/$c
and ")n"'
in the output above. But that can be ignored.
Finally, here's how to put all of that together and search for a function name in all default files and all files your default files are sourcing:
grep_function(){
target="$@"
files=( ~/.bashrc ~/.profile ~/.bash_profile ~/.bash.login
~/.bash_aliases /etc/bash.bashrc /etc/profile
/etc/profile.d/* /etc/environment)
while IFS= read -r file; do
files+=( "$file" )
done < <(grep -hPo '(^|s)(.|source)s+KS+' "${files[@]}" 2>/dev/null)
for file in "${files[@]}"; do
## The tilde of ~/ can break this
file=$(sed 's|~/|'"$HOME"'/|g' <<<"$file")
if [[ -e $file ]]; then
grep -H "$target" -- "$file"
fi
done
}
Add those lines to your ~/.bashrc
and you can then run (I am using fooBar
as an example function name):
grep_function fooBar
For example, if I have this line in my ~/.bashrc
:
. ~/a
And the file ~/a
is:
$ cat ~/a
fooBar(){
echo foo
}
I should find it with:
$ grep_function fooBar
/home/terdon/a:fooBar(){
edited May 28 at 11:20
answered May 26 at 11:11
terdon♦terdon
72.9k14 gold badges149 silver badges233 bronze badges
72.9k14 gold badges149 silver badges233 bronze badges
Your solution is a great educational scripting example, but I find bashity mcbashface's solution simpler.
– jarno
May 26 at 13:40
@jarno and it is much, much simpler! :)
– terdon♦
May 26 at 14:09
Arrays support+=
– D. Ben Knoble
May 27 at 15:16
@D.BenKnoble they do? You mean other thanarray+="foo"
appending the stringfoo
to the 1st element of the array?
– terdon♦
May 27 at 19:31
1
@D.BenKnoble thanks! I didn't know bash arrays supported that notation!
– terdon♦
May 28 at 12:43
|
show 1 more comment
Your solution is a great educational scripting example, but I find bashity mcbashface's solution simpler.
– jarno
May 26 at 13:40
@jarno and it is much, much simpler! :)
– terdon♦
May 26 at 14:09
Arrays support+=
– D. Ben Knoble
May 27 at 15:16
@D.BenKnoble they do? You mean other thanarray+="foo"
appending the stringfoo
to the 1st element of the array?
– terdon♦
May 27 at 19:31
1
@D.BenKnoble thanks! I didn't know bash arrays supported that notation!
– terdon♦
May 28 at 12:43
Your solution is a great educational scripting example, but I find bashity mcbashface's solution simpler.
– jarno
May 26 at 13:40
Your solution is a great educational scripting example, but I find bashity mcbashface's solution simpler.
– jarno
May 26 at 13:40
@jarno and it is much, much simpler! :)
– terdon♦
May 26 at 14:09
@jarno and it is much, much simpler! :)
– terdon♦
May 26 at 14:09
Arrays support
+=
– D. Ben Knoble
May 27 at 15:16
Arrays support
+=
– D. Ben Knoble
May 27 at 15:16
@D.BenKnoble they do? You mean other than
array+="foo"
appending the string foo
to the 1st element of the array?– terdon♦
May 27 at 19:31
@D.BenKnoble they do? You mean other than
array+="foo"
appending the string foo
to the 1st element of the array?– terdon♦
May 27 at 19:31
1
1
@D.BenKnoble thanks! I didn't know bash arrays supported that notation!
– terdon♦
May 28 at 12:43
@D.BenKnoble thanks! I didn't know bash arrays supported that notation!
– terdon♦
May 28 at 12:43
|
show 1 more comment
The usual per-user dotfile bash
reads is ~/.bashrc
. However, it may very well source other files, I for instance like to keep aliases and functions in separate files called ~/.bash_aliases
and ~/.bash_functions
, which makes finding them much easier. You can search the .bashrc
for source
commands with:
grep -E '(^s*|s)(.|source)s' /home/USERNAME/.bashrc
Once you have the list of user-created files you can search them and the user’s .bashrc
with a single grep
call, e.g. for function foo
for my setup:
grep foo /home/USERNAME/.bash{rc,_aliases,_functions}
add a comment |
The usual per-user dotfile bash
reads is ~/.bashrc
. However, it may very well source other files, I for instance like to keep aliases and functions in separate files called ~/.bash_aliases
and ~/.bash_functions
, which makes finding them much easier. You can search the .bashrc
for source
commands with:
grep -E '(^s*|s)(.|source)s' /home/USERNAME/.bashrc
Once you have the list of user-created files you can search them and the user’s .bashrc
with a single grep
call, e.g. for function foo
for my setup:
grep foo /home/USERNAME/.bash{rc,_aliases,_functions}
add a comment |
The usual per-user dotfile bash
reads is ~/.bashrc
. However, it may very well source other files, I for instance like to keep aliases and functions in separate files called ~/.bash_aliases
and ~/.bash_functions
, which makes finding them much easier. You can search the .bashrc
for source
commands with:
grep -E '(^s*|s)(.|source)s' /home/USERNAME/.bashrc
Once you have the list of user-created files you can search them and the user’s .bashrc
with a single grep
call, e.g. for function foo
for my setup:
grep foo /home/USERNAME/.bash{rc,_aliases,_functions}
The usual per-user dotfile bash
reads is ~/.bashrc
. However, it may very well source other files, I for instance like to keep aliases and functions in separate files called ~/.bash_aliases
and ~/.bash_functions
, which makes finding them much easier. You can search the .bashrc
for source
commands with:
grep -E '(^s*|s)(.|source)s' /home/USERNAME/.bashrc
Once you have the list of user-created files you can search them and the user’s .bashrc
with a single grep
call, e.g. for function foo
for my setup:
grep foo /home/USERNAME/.bash{rc,_aliases,_functions}
edited May 26 at 15:49
answered May 26 at 10:08
dessertdessert
28.5k6 gold badges86 silver badges119 bronze badges
28.5k6 gold badges86 silver badges119 bronze badges
add a comment |
add a comment |
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Look at: askubuntu.com/questions/463462/…
– FedonKadifeli
May 26 at 9:49