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Practical application of matrices and determinants


What are the applications of matrices in real world?Understanding matrix multiplicationWhich methods are used by actuaries in practice?Matrix Multiplication - Why Rows $cdot$ Columns = Columns?What are some applications of Trigonometry?Why are orthogonal matrices generalizations of rotations and reflections?Question regarding matrices and determinants.Applications of the wave equationSimilarity classes of matricesGeometry Of Unitary TransformationsAdvice for a graduate who is considering studying a second degree in MathsWhat exactly is a matrix?













5












$begingroup$


I have learned recently about matrices and determinants and also about the geometrical interpretations, i.e, how the matrix is used for linear transformations and how determinants tell us about area/volume changes.



My school textbooks tell me that matrices and determinants can be used to solve a system of equations, but I feel that such a vast concept would have more practical applications. My question is: what are the various ways the concept of matrices and determinants is employed in science or everyday life?










share|cite|improve this question









New contributor




Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 1




    $begingroup$
    Matrices are used a lot in machine learning.
    $endgroup$
    – Bladewood
    Mar 17 at 19:00






  • 6




    $begingroup$
    With some exaggeration, all of applied mathematics boils down to solving systems of linear equations.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 17 at 19:19






  • 4




    $begingroup$
    Solving systems of equations is extremely practical. Every time someone solves a differential equation using the finite element method, or runs a linear regression, or solves an optimization problem using Newton's method, a system of linear equations is solved. There is hardly any engineering or applied math project that doesn't require solving a system of linear equations.
    $endgroup$
    – Sasho Nikolov
    Mar 17 at 19:37










  • $begingroup$
    Matrices are important to computer graphics, but not determinants.
    $endgroup$
    – immibis
    Mar 17 at 22:47










  • $begingroup$
    See this intuitive motivation for matrices.
    $endgroup$
    – user21820
    2 days ago















5












$begingroup$


I have learned recently about matrices and determinants and also about the geometrical interpretations, i.e, how the matrix is used for linear transformations and how determinants tell us about area/volume changes.



My school textbooks tell me that matrices and determinants can be used to solve a system of equations, but I feel that such a vast concept would have more practical applications. My question is: what are the various ways the concept of matrices and determinants is employed in science or everyday life?










share|cite|improve this question









New contributor




Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 1




    $begingroup$
    Matrices are used a lot in machine learning.
    $endgroup$
    – Bladewood
    Mar 17 at 19:00






  • 6




    $begingroup$
    With some exaggeration, all of applied mathematics boils down to solving systems of linear equations.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 17 at 19:19






  • 4




    $begingroup$
    Solving systems of equations is extremely practical. Every time someone solves a differential equation using the finite element method, or runs a linear regression, or solves an optimization problem using Newton's method, a system of linear equations is solved. There is hardly any engineering or applied math project that doesn't require solving a system of linear equations.
    $endgroup$
    – Sasho Nikolov
    Mar 17 at 19:37










  • $begingroup$
    Matrices are important to computer graphics, but not determinants.
    $endgroup$
    – immibis
    Mar 17 at 22:47










  • $begingroup$
    See this intuitive motivation for matrices.
    $endgroup$
    – user21820
    2 days ago













5












5








5


1



$begingroup$


I have learned recently about matrices and determinants and also about the geometrical interpretations, i.e, how the matrix is used for linear transformations and how determinants tell us about area/volume changes.



My school textbooks tell me that matrices and determinants can be used to solve a system of equations, but I feel that such a vast concept would have more practical applications. My question is: what are the various ways the concept of matrices and determinants is employed in science or everyday life?










share|cite|improve this question









New contributor




Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I have learned recently about matrices and determinants and also about the geometrical interpretations, i.e, how the matrix is used for linear transformations and how determinants tell us about area/volume changes.



My school textbooks tell me that matrices and determinants can be used to solve a system of equations, but I feel that such a vast concept would have more practical applications. My question is: what are the various ways the concept of matrices and determinants is employed in science or everyday life?







matrices soft-question determinant applications






share|cite|improve this question









New contributor




Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 2 days ago









YuiTo Cheng

2,0612637




2,0612637






New contributor




Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Mar 17 at 14:57









Vaishakh Sreekanth MenonVaishakh Sreekanth Menon

292




292




New contributor




Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Vaishakh Sreekanth Menon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 1




    $begingroup$
    Matrices are used a lot in machine learning.
    $endgroup$
    – Bladewood
    Mar 17 at 19:00






  • 6




    $begingroup$
    With some exaggeration, all of applied mathematics boils down to solving systems of linear equations.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 17 at 19:19






  • 4




    $begingroup$
    Solving systems of equations is extremely practical. Every time someone solves a differential equation using the finite element method, or runs a linear regression, or solves an optimization problem using Newton's method, a system of linear equations is solved. There is hardly any engineering or applied math project that doesn't require solving a system of linear equations.
    $endgroup$
    – Sasho Nikolov
    Mar 17 at 19:37










  • $begingroup$
    Matrices are important to computer graphics, but not determinants.
    $endgroup$
    – immibis
    Mar 17 at 22:47










  • $begingroup$
    See this intuitive motivation for matrices.
    $endgroup$
    – user21820
    2 days ago












  • 1




    $begingroup$
    Matrices are used a lot in machine learning.
    $endgroup$
    – Bladewood
    Mar 17 at 19:00






  • 6




    $begingroup$
    With some exaggeration, all of applied mathematics boils down to solving systems of linear equations.
    $endgroup$
    – Rodrigo de Azevedo
    Mar 17 at 19:19






  • 4




    $begingroup$
    Solving systems of equations is extremely practical. Every time someone solves a differential equation using the finite element method, or runs a linear regression, or solves an optimization problem using Newton's method, a system of linear equations is solved. There is hardly any engineering or applied math project that doesn't require solving a system of linear equations.
    $endgroup$
    – Sasho Nikolov
    Mar 17 at 19:37










  • $begingroup$
    Matrices are important to computer graphics, but not determinants.
    $endgroup$
    – immibis
    Mar 17 at 22:47










  • $begingroup$
    See this intuitive motivation for matrices.
    $endgroup$
    – user21820
    2 days ago







1




1




$begingroup$
Matrices are used a lot in machine learning.
$endgroup$
– Bladewood
Mar 17 at 19:00




$begingroup$
Matrices are used a lot in machine learning.
$endgroup$
– Bladewood
Mar 17 at 19:00




6




6




$begingroup$
With some exaggeration, all of applied mathematics boils down to solving systems of linear equations.
$endgroup$
– Rodrigo de Azevedo
Mar 17 at 19:19




$begingroup$
With some exaggeration, all of applied mathematics boils down to solving systems of linear equations.
$endgroup$
– Rodrigo de Azevedo
Mar 17 at 19:19




4




4




$begingroup$
Solving systems of equations is extremely practical. Every time someone solves a differential equation using the finite element method, or runs a linear regression, or solves an optimization problem using Newton's method, a system of linear equations is solved. There is hardly any engineering or applied math project that doesn't require solving a system of linear equations.
$endgroup$
– Sasho Nikolov
Mar 17 at 19:37




$begingroup$
Solving systems of equations is extremely practical. Every time someone solves a differential equation using the finite element method, or runs a linear regression, or solves an optimization problem using Newton's method, a system of linear equations is solved. There is hardly any engineering or applied math project that doesn't require solving a system of linear equations.
$endgroup$
– Sasho Nikolov
Mar 17 at 19:37












$begingroup$
Matrices are important to computer graphics, but not determinants.
$endgroup$
– immibis
Mar 17 at 22:47




$begingroup$
Matrices are important to computer graphics, but not determinants.
$endgroup$
– immibis
Mar 17 at 22:47












$begingroup$
See this intuitive motivation for matrices.
$endgroup$
– user21820
2 days ago




$begingroup$
See this intuitive motivation for matrices.
$endgroup$
– user21820
2 days ago










8 Answers
8






active

oldest

votes


















7












$begingroup$

My first brief understanding of matrices is that they offer an elegant way to deal with data (combinatorially, sort of). A classical and really concrete example would be a discrete Markov chain (don't be frightened by its name). Say you are given the following information: if today is rainy, then tomorrow has a 0.9 probability to be rainy; if today is sunny, then tomorrow has a 0.5 probability to be rainy. Then you may organize these data into a matrix:



$$A=beginpmatrix
0.9 & 0.5 \
0.1 & 0.5
endpmatrix$$



Now if you compute $A^2=beginpmatrix
0.86 & 0.7 \
0.14 & 0.3
endpmatrix$
, what do you get? 0.86 is the probability that if today is rainy then the day after tomorrow is still rainy and 0.7 is the probability that if today is sunny then the day after tomorrow is rainy. And this pattern holds for $A^n$ an arbitrary $n$.



That's the simple point: matrices are a way to calculate elegantly. In my understanding, this aligns with the spirit of mathematics. Math occurs when people try to solve practical problems. People find that if they make good definitions and use good notations, things will be a lot easier. Here comes math. And the matrix is such a good notation to make things easier.






share|cite|improve this answer









$endgroup$




















    5












    $begingroup$

    Matrices are used widely in computer graphics. If you have the coordinates of an object in 3d space, then scaling, stretching and rotating the object can all be done by considering the coordinates to be vectors and multiplying them by the appropriate matrix. When you want to display that object on-screen, the projection down to a 2D object is also a matrix multiplication.






    share|cite|improve this answer









    $endgroup$




















      5












      $begingroup$

      Determinants are of great theoretical significance in mathematics, since in general "the determinant of something $= 0$" means something very special is going on, which may be either good news of bad news depending on the situation.



      On the other hand determinants have very little practical use in numerical calculations, since evaluating a determinant of order $n$ "from first principles" involves $n!$ operations, which is prohibitively expensive unless $n$ is very small. Even Cramer's rule, which is often taught in an introductory course on determinants and matrices, is not the cheapest way to solve $n$ linear equations in $n$ variables numerically if $n>2$, which is a pretty serious limitation!



      Also, if the typical magnitude of each term in a matrix of of order $n$ is $a$, the determinant is likely to be of magnitude $a^n$, and for large $n$ (say $n > 1000$) that number will usually be too large or too small to do efficient computer calculations, unless $|a|$ is very close to $1$.



      On the other hand, almost every type of numerical calculation involves the same techniques that are used to solve equations, so the practical applications of matrices are more or less "the whole of applied mathematics, science, and engineering". Most applications involve systems of equations that are much too big to create and solve by hand, so it is hard to give realistic simple examples. In real-world numerical applications, a set of $n$ linear equations in $n$ variables would still be "small" from a practical point of view if $n = 100,000,$ and even $n = 1,000,000$ is not usually big enough to cause any real problems - the solution would only take a few seconds on a typical personal computer.






      share|cite|improve this answer









      $endgroup$












      • $begingroup$
        Why "even Cramer's rule"? That rule is so obviously inefficient that it's hardly worth mentioning, as every introductory course covers Gaussian elimination, which is clearly much more efficient.
        $endgroup$
        – Servaes
        Mar 17 at 20:19










      • $begingroup$
        Whilst it doesn't make it more efficient, the determinant calculations in Cramer's rule can be done using Gaussian elimination which means its at least in the same complexity class surely?
        $endgroup$
        – jacob1729
        Mar 17 at 23:10


















      3












      $begingroup$

      Here's an application in calculus. The multivariate generalisation of integration by substitution viz. $x=f(y)implies dx=f^prime(y)dy$ uses the determinant of a matrix called a Jacobian in place of the $f^prime$ factor. In particular, the chain rule $dx_i=sum_j J_ijdy_j,,J_ij:=fracpartial x_ipartial y_j$ for $n$-dimensional vectors $vecx,,vecy$ can be summarised as $dvecx=Jdvecy$. Then $d^nvecx=|det J|d^nvecy$.






      share|cite|improve this answer









      $endgroup$




















        3












        $begingroup$

        There are plenty of applications of determinants, but I will just mention one that applies to optimization. A totally unimodular matrix is a matrix (doesn’t have to be square) that every square submatrix has a determinant of 0, 1 or -1. It turns out that (by Cramer’s rule) that if a constraint matrix $A$ of a linear program max $c’x:: Ax leq b, x in mathbbR^n_+ $ is totally unimodular, it is guaranteed to have an integer solution if a solution exists. In other words, the polyhedron formed by $P = x:: Ax leq b$ has integer vertices in $mathbbR^n$. This has major implications in integer programming, as we solve an integer program that has a totally unimodular matrix as a linear program. This is advantageous because a linear program can me solved in polynomial time, where there is no polynomial algorithm for integer programs.






        share|cite|improve this answer









        $endgroup$




















          3












          $begingroup$

          Besides the applications already mentioned in the previous answers, just consider that matrices are the fundamental basis for Finite Elements design, today widely used in every sector of engineering.



          Actually a truss is a physical representation of a matrix: if its stiffness matrix has null determinant, it means that there can be movements without external forces, i.e. the truss will collapse.



          Also, in the continuous analysis of the deformation of bodies, stress and strain each are represented by matrices (tensors).



          The inertia of a body to rotation is a matrix.



          An electric network is described by a matrix voltages/ currents, and a null determinant denotes a short somewhere.



          And so on ...






          share|cite|improve this answer











          $endgroup$




















            2












            $begingroup$

            If the determinant of a matrix is zero, then there are no solutions to a set of equations represented by an nXn matrix set equal to a 1Xn matrix. If it is non-zero, then there are solutions and they can all be found using Cramer's Rule. They are also used in Photoshop for various visual tricks; they are used to cast 3D shapes onto a 2D surface; they are used to analyze seismic waves... and a hundred other applications where data need to be crunched in a simple manner.






            share|cite|improve this answer









            $endgroup$




















              0












              $begingroup$

              In system-theory,



              1. systems can be represented by matrices and each column represent the internal-state of the system.

              2. If a determinant of one such matrix is zero, then we can say that one of the state associated with certain dynamics is being duplicated.

              3. Based on some special matrix operations, we arrive at something called as relative-gain-array (RGA). This will give information on how much each states/output of a system interactes with each other, collectively speaking.

              However, top are just a few examples. There are much more.






              share|cite|improve this answer









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                8 Answers
                8






                active

                oldest

                votes








                8 Answers
                8






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                7












                $begingroup$

                My first brief understanding of matrices is that they offer an elegant way to deal with data (combinatorially, sort of). A classical and really concrete example would be a discrete Markov chain (don't be frightened by its name). Say you are given the following information: if today is rainy, then tomorrow has a 0.9 probability to be rainy; if today is sunny, then tomorrow has a 0.5 probability to be rainy. Then you may organize these data into a matrix:



                $$A=beginpmatrix
                0.9 & 0.5 \
                0.1 & 0.5
                endpmatrix$$



                Now if you compute $A^2=beginpmatrix
                0.86 & 0.7 \
                0.14 & 0.3
                endpmatrix$
                , what do you get? 0.86 is the probability that if today is rainy then the day after tomorrow is still rainy and 0.7 is the probability that if today is sunny then the day after tomorrow is rainy. And this pattern holds for $A^n$ an arbitrary $n$.



                That's the simple point: matrices are a way to calculate elegantly. In my understanding, this aligns with the spirit of mathematics. Math occurs when people try to solve practical problems. People find that if they make good definitions and use good notations, things will be a lot easier. Here comes math. And the matrix is such a good notation to make things easier.






                share|cite|improve this answer









                $endgroup$

















                  7












                  $begingroup$

                  My first brief understanding of matrices is that they offer an elegant way to deal with data (combinatorially, sort of). A classical and really concrete example would be a discrete Markov chain (don't be frightened by its name). Say you are given the following information: if today is rainy, then tomorrow has a 0.9 probability to be rainy; if today is sunny, then tomorrow has a 0.5 probability to be rainy. Then you may organize these data into a matrix:



                  $$A=beginpmatrix
                  0.9 & 0.5 \
                  0.1 & 0.5
                  endpmatrix$$



                  Now if you compute $A^2=beginpmatrix
                  0.86 & 0.7 \
                  0.14 & 0.3
                  endpmatrix$
                  , what do you get? 0.86 is the probability that if today is rainy then the day after tomorrow is still rainy and 0.7 is the probability that if today is sunny then the day after tomorrow is rainy. And this pattern holds for $A^n$ an arbitrary $n$.



                  That's the simple point: matrices are a way to calculate elegantly. In my understanding, this aligns with the spirit of mathematics. Math occurs when people try to solve practical problems. People find that if they make good definitions and use good notations, things will be a lot easier. Here comes math. And the matrix is such a good notation to make things easier.






                  share|cite|improve this answer









                  $endgroup$















                    7












                    7








                    7





                    $begingroup$

                    My first brief understanding of matrices is that they offer an elegant way to deal with data (combinatorially, sort of). A classical and really concrete example would be a discrete Markov chain (don't be frightened by its name). Say you are given the following information: if today is rainy, then tomorrow has a 0.9 probability to be rainy; if today is sunny, then tomorrow has a 0.5 probability to be rainy. Then you may organize these data into a matrix:



                    $$A=beginpmatrix
                    0.9 & 0.5 \
                    0.1 & 0.5
                    endpmatrix$$



                    Now if you compute $A^2=beginpmatrix
                    0.86 & 0.7 \
                    0.14 & 0.3
                    endpmatrix$
                    , what do you get? 0.86 is the probability that if today is rainy then the day after tomorrow is still rainy and 0.7 is the probability that if today is sunny then the day after tomorrow is rainy. And this pattern holds for $A^n$ an arbitrary $n$.



                    That's the simple point: matrices are a way to calculate elegantly. In my understanding, this aligns with the spirit of mathematics. Math occurs when people try to solve practical problems. People find that if they make good definitions and use good notations, things will be a lot easier. Here comes math. And the matrix is such a good notation to make things easier.






                    share|cite|improve this answer









                    $endgroup$



                    My first brief understanding of matrices is that they offer an elegant way to deal with data (combinatorially, sort of). A classical and really concrete example would be a discrete Markov chain (don't be frightened by its name). Say you are given the following information: if today is rainy, then tomorrow has a 0.9 probability to be rainy; if today is sunny, then tomorrow has a 0.5 probability to be rainy. Then you may organize these data into a matrix:



                    $$A=beginpmatrix
                    0.9 & 0.5 \
                    0.1 & 0.5
                    endpmatrix$$



                    Now if you compute $A^2=beginpmatrix
                    0.86 & 0.7 \
                    0.14 & 0.3
                    endpmatrix$
                    , what do you get? 0.86 is the probability that if today is rainy then the day after tomorrow is still rainy and 0.7 is the probability that if today is sunny then the day after tomorrow is rainy. And this pattern holds for $A^n$ an arbitrary $n$.



                    That's the simple point: matrices are a way to calculate elegantly. In my understanding, this aligns with the spirit of mathematics. Math occurs when people try to solve practical problems. People find that if they make good definitions and use good notations, things will be a lot easier. Here comes math. And the matrix is such a good notation to make things easier.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Mar 17 at 15:55









                    J. WangJ. Wang

                    1245




                    1245





















                        5












                        $begingroup$

                        Matrices are used widely in computer graphics. If you have the coordinates of an object in 3d space, then scaling, stretching and rotating the object can all be done by considering the coordinates to be vectors and multiplying them by the appropriate matrix. When you want to display that object on-screen, the projection down to a 2D object is also a matrix multiplication.






                        share|cite|improve this answer









                        $endgroup$

















                          5












                          $begingroup$

                          Matrices are used widely in computer graphics. If you have the coordinates of an object in 3d space, then scaling, stretching and rotating the object can all be done by considering the coordinates to be vectors and multiplying them by the appropriate matrix. When you want to display that object on-screen, the projection down to a 2D object is also a matrix multiplication.






                          share|cite|improve this answer









                          $endgroup$















                            5












                            5








                            5





                            $begingroup$

                            Matrices are used widely in computer graphics. If you have the coordinates of an object in 3d space, then scaling, stretching and rotating the object can all be done by considering the coordinates to be vectors and multiplying them by the appropriate matrix. When you want to display that object on-screen, the projection down to a 2D object is also a matrix multiplication.






                            share|cite|improve this answer









                            $endgroup$



                            Matrices are used widely in computer graphics. If you have the coordinates of an object in 3d space, then scaling, stretching and rotating the object can all be done by considering the coordinates to be vectors and multiplying them by the appropriate matrix. When you want to display that object on-screen, the projection down to a 2D object is also a matrix multiplication.







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered Mar 17 at 19:02









                            David RicherbyDavid Richerby

                            2,25511324




                            2,25511324





















                                5












                                $begingroup$

                                Determinants are of great theoretical significance in mathematics, since in general "the determinant of something $= 0$" means something very special is going on, which may be either good news of bad news depending on the situation.



                                On the other hand determinants have very little practical use in numerical calculations, since evaluating a determinant of order $n$ "from first principles" involves $n!$ operations, which is prohibitively expensive unless $n$ is very small. Even Cramer's rule, which is often taught in an introductory course on determinants and matrices, is not the cheapest way to solve $n$ linear equations in $n$ variables numerically if $n>2$, which is a pretty serious limitation!



                                Also, if the typical magnitude of each term in a matrix of of order $n$ is $a$, the determinant is likely to be of magnitude $a^n$, and for large $n$ (say $n > 1000$) that number will usually be too large or too small to do efficient computer calculations, unless $|a|$ is very close to $1$.



                                On the other hand, almost every type of numerical calculation involves the same techniques that are used to solve equations, so the practical applications of matrices are more or less "the whole of applied mathematics, science, and engineering". Most applications involve systems of equations that are much too big to create and solve by hand, so it is hard to give realistic simple examples. In real-world numerical applications, a set of $n$ linear equations in $n$ variables would still be "small" from a practical point of view if $n = 100,000,$ and even $n = 1,000,000$ is not usually big enough to cause any real problems - the solution would only take a few seconds on a typical personal computer.






                                share|cite|improve this answer









                                $endgroup$












                                • $begingroup$
                                  Why "even Cramer's rule"? That rule is so obviously inefficient that it's hardly worth mentioning, as every introductory course covers Gaussian elimination, which is clearly much more efficient.
                                  $endgroup$
                                  – Servaes
                                  Mar 17 at 20:19










                                • $begingroup$
                                  Whilst it doesn't make it more efficient, the determinant calculations in Cramer's rule can be done using Gaussian elimination which means its at least in the same complexity class surely?
                                  $endgroup$
                                  – jacob1729
                                  Mar 17 at 23:10















                                5












                                $begingroup$

                                Determinants are of great theoretical significance in mathematics, since in general "the determinant of something $= 0$" means something very special is going on, which may be either good news of bad news depending on the situation.



                                On the other hand determinants have very little practical use in numerical calculations, since evaluating a determinant of order $n$ "from first principles" involves $n!$ operations, which is prohibitively expensive unless $n$ is very small. Even Cramer's rule, which is often taught in an introductory course on determinants and matrices, is not the cheapest way to solve $n$ linear equations in $n$ variables numerically if $n>2$, which is a pretty serious limitation!



                                Also, if the typical magnitude of each term in a matrix of of order $n$ is $a$, the determinant is likely to be of magnitude $a^n$, and for large $n$ (say $n > 1000$) that number will usually be too large or too small to do efficient computer calculations, unless $|a|$ is very close to $1$.



                                On the other hand, almost every type of numerical calculation involves the same techniques that are used to solve equations, so the practical applications of matrices are more or less "the whole of applied mathematics, science, and engineering". Most applications involve systems of equations that are much too big to create and solve by hand, so it is hard to give realistic simple examples. In real-world numerical applications, a set of $n$ linear equations in $n$ variables would still be "small" from a practical point of view if $n = 100,000,$ and even $n = 1,000,000$ is not usually big enough to cause any real problems - the solution would only take a few seconds on a typical personal computer.






                                share|cite|improve this answer









                                $endgroup$












                                • $begingroup$
                                  Why "even Cramer's rule"? That rule is so obviously inefficient that it's hardly worth mentioning, as every introductory course covers Gaussian elimination, which is clearly much more efficient.
                                  $endgroup$
                                  – Servaes
                                  Mar 17 at 20:19










                                • $begingroup$
                                  Whilst it doesn't make it more efficient, the determinant calculations in Cramer's rule can be done using Gaussian elimination which means its at least in the same complexity class surely?
                                  $endgroup$
                                  – jacob1729
                                  Mar 17 at 23:10













                                5












                                5








                                5





                                $begingroup$

                                Determinants are of great theoretical significance in mathematics, since in general "the determinant of something $= 0$" means something very special is going on, which may be either good news of bad news depending on the situation.



                                On the other hand determinants have very little practical use in numerical calculations, since evaluating a determinant of order $n$ "from first principles" involves $n!$ operations, which is prohibitively expensive unless $n$ is very small. Even Cramer's rule, which is often taught in an introductory course on determinants and matrices, is not the cheapest way to solve $n$ linear equations in $n$ variables numerically if $n>2$, which is a pretty serious limitation!



                                Also, if the typical magnitude of each term in a matrix of of order $n$ is $a$, the determinant is likely to be of magnitude $a^n$, and for large $n$ (say $n > 1000$) that number will usually be too large or too small to do efficient computer calculations, unless $|a|$ is very close to $1$.



                                On the other hand, almost every type of numerical calculation involves the same techniques that are used to solve equations, so the practical applications of matrices are more or less "the whole of applied mathematics, science, and engineering". Most applications involve systems of equations that are much too big to create and solve by hand, so it is hard to give realistic simple examples. In real-world numerical applications, a set of $n$ linear equations in $n$ variables would still be "small" from a practical point of view if $n = 100,000,$ and even $n = 1,000,000$ is not usually big enough to cause any real problems - the solution would only take a few seconds on a typical personal computer.






                                share|cite|improve this answer









                                $endgroup$



                                Determinants are of great theoretical significance in mathematics, since in general "the determinant of something $= 0$" means something very special is going on, which may be either good news of bad news depending on the situation.



                                On the other hand determinants have very little practical use in numerical calculations, since evaluating a determinant of order $n$ "from first principles" involves $n!$ operations, which is prohibitively expensive unless $n$ is very small. Even Cramer's rule, which is often taught in an introductory course on determinants and matrices, is not the cheapest way to solve $n$ linear equations in $n$ variables numerically if $n>2$, which is a pretty serious limitation!



                                Also, if the typical magnitude of each term in a matrix of of order $n$ is $a$, the determinant is likely to be of magnitude $a^n$, and for large $n$ (say $n > 1000$) that number will usually be too large or too small to do efficient computer calculations, unless $|a|$ is very close to $1$.



                                On the other hand, almost every type of numerical calculation involves the same techniques that are used to solve equations, so the practical applications of matrices are more or less "the whole of applied mathematics, science, and engineering". Most applications involve systems of equations that are much too big to create and solve by hand, so it is hard to give realistic simple examples. In real-world numerical applications, a set of $n$ linear equations in $n$ variables would still be "small" from a practical point of view if $n = 100,000,$ and even $n = 1,000,000$ is not usually big enough to cause any real problems - the solution would only take a few seconds on a typical personal computer.







                                share|cite|improve this answer












                                share|cite|improve this answer



                                share|cite|improve this answer










                                answered Mar 17 at 19:19









                                alephzeroalephzero

                                71037




                                71037











                                • $begingroup$
                                  Why "even Cramer's rule"? That rule is so obviously inefficient that it's hardly worth mentioning, as every introductory course covers Gaussian elimination, which is clearly much more efficient.
                                  $endgroup$
                                  – Servaes
                                  Mar 17 at 20:19










                                • $begingroup$
                                  Whilst it doesn't make it more efficient, the determinant calculations in Cramer's rule can be done using Gaussian elimination which means its at least in the same complexity class surely?
                                  $endgroup$
                                  – jacob1729
                                  Mar 17 at 23:10
















                                • $begingroup$
                                  Why "even Cramer's rule"? That rule is so obviously inefficient that it's hardly worth mentioning, as every introductory course covers Gaussian elimination, which is clearly much more efficient.
                                  $endgroup$
                                  – Servaes
                                  Mar 17 at 20:19










                                • $begingroup$
                                  Whilst it doesn't make it more efficient, the determinant calculations in Cramer's rule can be done using Gaussian elimination which means its at least in the same complexity class surely?
                                  $endgroup$
                                  – jacob1729
                                  Mar 17 at 23:10















                                $begingroup$
                                Why "even Cramer's rule"? That rule is so obviously inefficient that it's hardly worth mentioning, as every introductory course covers Gaussian elimination, which is clearly much more efficient.
                                $endgroup$
                                – Servaes
                                Mar 17 at 20:19




                                $begingroup$
                                Why "even Cramer's rule"? That rule is so obviously inefficient that it's hardly worth mentioning, as every introductory course covers Gaussian elimination, which is clearly much more efficient.
                                $endgroup$
                                – Servaes
                                Mar 17 at 20:19












                                $begingroup$
                                Whilst it doesn't make it more efficient, the determinant calculations in Cramer's rule can be done using Gaussian elimination which means its at least in the same complexity class surely?
                                $endgroup$
                                – jacob1729
                                Mar 17 at 23:10




                                $begingroup$
                                Whilst it doesn't make it more efficient, the determinant calculations in Cramer's rule can be done using Gaussian elimination which means its at least in the same complexity class surely?
                                $endgroup$
                                – jacob1729
                                Mar 17 at 23:10











                                3












                                $begingroup$

                                Here's an application in calculus. The multivariate generalisation of integration by substitution viz. $x=f(y)implies dx=f^prime(y)dy$ uses the determinant of a matrix called a Jacobian in place of the $f^prime$ factor. In particular, the chain rule $dx_i=sum_j J_ijdy_j,,J_ij:=fracpartial x_ipartial y_j$ for $n$-dimensional vectors $vecx,,vecy$ can be summarised as $dvecx=Jdvecy$. Then $d^nvecx=|det J|d^nvecy$.






                                share|cite|improve this answer









                                $endgroup$

















                                  3












                                  $begingroup$

                                  Here's an application in calculus. The multivariate generalisation of integration by substitution viz. $x=f(y)implies dx=f^prime(y)dy$ uses the determinant of a matrix called a Jacobian in place of the $f^prime$ factor. In particular, the chain rule $dx_i=sum_j J_ijdy_j,,J_ij:=fracpartial x_ipartial y_j$ for $n$-dimensional vectors $vecx,,vecy$ can be summarised as $dvecx=Jdvecy$. Then $d^nvecx=|det J|d^nvecy$.






                                  share|cite|improve this answer









                                  $endgroup$















                                    3












                                    3








                                    3





                                    $begingroup$

                                    Here's an application in calculus. The multivariate generalisation of integration by substitution viz. $x=f(y)implies dx=f^prime(y)dy$ uses the determinant of a matrix called a Jacobian in place of the $f^prime$ factor. In particular, the chain rule $dx_i=sum_j J_ijdy_j,,J_ij:=fracpartial x_ipartial y_j$ for $n$-dimensional vectors $vecx,,vecy$ can be summarised as $dvecx=Jdvecy$. Then $d^nvecx=|det J|d^nvecy$.






                                    share|cite|improve this answer









                                    $endgroup$



                                    Here's an application in calculus. The multivariate generalisation of integration by substitution viz. $x=f(y)implies dx=f^prime(y)dy$ uses the determinant of a matrix called a Jacobian in place of the $f^prime$ factor. In particular, the chain rule $dx_i=sum_j J_ijdy_j,,J_ij:=fracpartial x_ipartial y_j$ for $n$-dimensional vectors $vecx,,vecy$ can be summarised as $dvecx=Jdvecy$. Then $d^nvecx=|det J|d^nvecy$.







                                    share|cite|improve this answer












                                    share|cite|improve this answer



                                    share|cite|improve this answer










                                    answered Mar 17 at 15:27









                                    J.G.J.G.

                                    30.9k23149




                                    30.9k23149





















                                        3












                                        $begingroup$

                                        There are plenty of applications of determinants, but I will just mention one that applies to optimization. A totally unimodular matrix is a matrix (doesn’t have to be square) that every square submatrix has a determinant of 0, 1 or -1. It turns out that (by Cramer’s rule) that if a constraint matrix $A$ of a linear program max $c’x:: Ax leq b, x in mathbbR^n_+ $ is totally unimodular, it is guaranteed to have an integer solution if a solution exists. In other words, the polyhedron formed by $P = x:: Ax leq b$ has integer vertices in $mathbbR^n$. This has major implications in integer programming, as we solve an integer program that has a totally unimodular matrix as a linear program. This is advantageous because a linear program can me solved in polynomial time, where there is no polynomial algorithm for integer programs.






                                        share|cite|improve this answer









                                        $endgroup$

















                                          3












                                          $begingroup$

                                          There are plenty of applications of determinants, but I will just mention one that applies to optimization. A totally unimodular matrix is a matrix (doesn’t have to be square) that every square submatrix has a determinant of 0, 1 or -1. It turns out that (by Cramer’s rule) that if a constraint matrix $A$ of a linear program max $c’x:: Ax leq b, x in mathbbR^n_+ $ is totally unimodular, it is guaranteed to have an integer solution if a solution exists. In other words, the polyhedron formed by $P = x:: Ax leq b$ has integer vertices in $mathbbR^n$. This has major implications in integer programming, as we solve an integer program that has a totally unimodular matrix as a linear program. This is advantageous because a linear program can me solved in polynomial time, where there is no polynomial algorithm for integer programs.






                                          share|cite|improve this answer









                                          $endgroup$















                                            3












                                            3








                                            3





                                            $begingroup$

                                            There are plenty of applications of determinants, but I will just mention one that applies to optimization. A totally unimodular matrix is a matrix (doesn’t have to be square) that every square submatrix has a determinant of 0, 1 or -1. It turns out that (by Cramer’s rule) that if a constraint matrix $A$ of a linear program max $c’x:: Ax leq b, x in mathbbR^n_+ $ is totally unimodular, it is guaranteed to have an integer solution if a solution exists. In other words, the polyhedron formed by $P = x:: Ax leq b$ has integer vertices in $mathbbR^n$. This has major implications in integer programming, as we solve an integer program that has a totally unimodular matrix as a linear program. This is advantageous because a linear program can me solved in polynomial time, where there is no polynomial algorithm for integer programs.






                                            share|cite|improve this answer









                                            $endgroup$



                                            There are plenty of applications of determinants, but I will just mention one that applies to optimization. A totally unimodular matrix is a matrix (doesn’t have to be square) that every square submatrix has a determinant of 0, 1 or -1. It turns out that (by Cramer’s rule) that if a constraint matrix $A$ of a linear program max $c’x:: Ax leq b, x in mathbbR^n_+ $ is totally unimodular, it is guaranteed to have an integer solution if a solution exists. In other words, the polyhedron formed by $P = x:: Ax leq b$ has integer vertices in $mathbbR^n$. This has major implications in integer programming, as we solve an integer program that has a totally unimodular matrix as a linear program. This is advantageous because a linear program can me solved in polynomial time, where there is no polynomial algorithm for integer programs.







                                            share|cite|improve this answer












                                            share|cite|improve this answer



                                            share|cite|improve this answer










                                            answered Mar 17 at 15:36









                                            JBLJBL

                                            483210




                                            483210





















                                                3












                                                $begingroup$

                                                Besides the applications already mentioned in the previous answers, just consider that matrices are the fundamental basis for Finite Elements design, today widely used in every sector of engineering.



                                                Actually a truss is a physical representation of a matrix: if its stiffness matrix has null determinant, it means that there can be movements without external forces, i.e. the truss will collapse.



                                                Also, in the continuous analysis of the deformation of bodies, stress and strain each are represented by matrices (tensors).



                                                The inertia of a body to rotation is a matrix.



                                                An electric network is described by a matrix voltages/ currents, and a null determinant denotes a short somewhere.



                                                And so on ...






                                                share|cite|improve this answer











                                                $endgroup$

















                                                  3












                                                  $begingroup$

                                                  Besides the applications already mentioned in the previous answers, just consider that matrices are the fundamental basis for Finite Elements design, today widely used in every sector of engineering.



                                                  Actually a truss is a physical representation of a matrix: if its stiffness matrix has null determinant, it means that there can be movements without external forces, i.e. the truss will collapse.



                                                  Also, in the continuous analysis of the deformation of bodies, stress and strain each are represented by matrices (tensors).



                                                  The inertia of a body to rotation is a matrix.



                                                  An electric network is described by a matrix voltages/ currents, and a null determinant denotes a short somewhere.



                                                  And so on ...






                                                  share|cite|improve this answer











                                                  $endgroup$















                                                    3












                                                    3








                                                    3





                                                    $begingroup$

                                                    Besides the applications already mentioned in the previous answers, just consider that matrices are the fundamental basis for Finite Elements design, today widely used in every sector of engineering.



                                                    Actually a truss is a physical representation of a matrix: if its stiffness matrix has null determinant, it means that there can be movements without external forces, i.e. the truss will collapse.



                                                    Also, in the continuous analysis of the deformation of bodies, stress and strain each are represented by matrices (tensors).



                                                    The inertia of a body to rotation is a matrix.



                                                    An electric network is described by a matrix voltages/ currents, and a null determinant denotes a short somewhere.



                                                    And so on ...






                                                    share|cite|improve this answer











                                                    $endgroup$



                                                    Besides the applications already mentioned in the previous answers, just consider that matrices are the fundamental basis for Finite Elements design, today widely used in every sector of engineering.



                                                    Actually a truss is a physical representation of a matrix: if its stiffness matrix has null determinant, it means that there can be movements without external forces, i.e. the truss will collapse.



                                                    Also, in the continuous analysis of the deformation of bodies, stress and strain each are represented by matrices (tensors).



                                                    The inertia of a body to rotation is a matrix.



                                                    An electric network is described by a matrix voltages/ currents, and a null determinant denotes a short somewhere.



                                                    And so on ...







                                                    share|cite|improve this answer














                                                    share|cite|improve this answer



                                                    share|cite|improve this answer








                                                    edited 2 days ago

























                                                    answered Mar 17 at 20:18









                                                    G CabG Cab

                                                    20.4k31341




                                                    20.4k31341





















                                                        2












                                                        $begingroup$

                                                        If the determinant of a matrix is zero, then there are no solutions to a set of equations represented by an nXn matrix set equal to a 1Xn matrix. If it is non-zero, then there are solutions and they can all be found using Cramer's Rule. They are also used in Photoshop for various visual tricks; they are used to cast 3D shapes onto a 2D surface; they are used to analyze seismic waves... and a hundred other applications where data need to be crunched in a simple manner.






                                                        share|cite|improve this answer









                                                        $endgroup$

















                                                          2












                                                          $begingroup$

                                                          If the determinant of a matrix is zero, then there are no solutions to a set of equations represented by an nXn matrix set equal to a 1Xn matrix. If it is non-zero, then there are solutions and they can all be found using Cramer's Rule. They are also used in Photoshop for various visual tricks; they are used to cast 3D shapes onto a 2D surface; they are used to analyze seismic waves... and a hundred other applications where data need to be crunched in a simple manner.






                                                          share|cite|improve this answer









                                                          $endgroup$















                                                            2












                                                            2








                                                            2





                                                            $begingroup$

                                                            If the determinant of a matrix is zero, then there are no solutions to a set of equations represented by an nXn matrix set equal to a 1Xn matrix. If it is non-zero, then there are solutions and they can all be found using Cramer's Rule. They are also used in Photoshop for various visual tricks; they are used to cast 3D shapes onto a 2D surface; they are used to analyze seismic waves... and a hundred other applications where data need to be crunched in a simple manner.






                                                            share|cite|improve this answer









                                                            $endgroup$



                                                            If the determinant of a matrix is zero, then there are no solutions to a set of equations represented by an nXn matrix set equal to a 1Xn matrix. If it is non-zero, then there are solutions and they can all be found using Cramer's Rule. They are also used in Photoshop for various visual tricks; they are used to cast 3D shapes onto a 2D surface; they are used to analyze seismic waves... and a hundred other applications where data need to be crunched in a simple manner.







                                                            share|cite|improve this answer












                                                            share|cite|improve this answer



                                                            share|cite|improve this answer










                                                            answered Mar 17 at 15:20









                                                            poetasispoetasis

                                                            420217




                                                            420217





















                                                                0












                                                                $begingroup$

                                                                In system-theory,



                                                                1. systems can be represented by matrices and each column represent the internal-state of the system.

                                                                2. If a determinant of one such matrix is zero, then we can say that one of the state associated with certain dynamics is being duplicated.

                                                                3. Based on some special matrix operations, we arrive at something called as relative-gain-array (RGA). This will give information on how much each states/output of a system interactes with each other, collectively speaking.

                                                                However, top are just a few examples. There are much more.






                                                                share|cite|improve this answer









                                                                $endgroup$

















                                                                  0












                                                                  $begingroup$

                                                                  In system-theory,



                                                                  1. systems can be represented by matrices and each column represent the internal-state of the system.

                                                                  2. If a determinant of one such matrix is zero, then we can say that one of the state associated with certain dynamics is being duplicated.

                                                                  3. Based on some special matrix operations, we arrive at something called as relative-gain-array (RGA). This will give information on how much each states/output of a system interactes with each other, collectively speaking.

                                                                  However, top are just a few examples. There are much more.






                                                                  share|cite|improve this answer









                                                                  $endgroup$















                                                                    0












                                                                    0








                                                                    0





                                                                    $begingroup$

                                                                    In system-theory,



                                                                    1. systems can be represented by matrices and each column represent the internal-state of the system.

                                                                    2. If a determinant of one such matrix is zero, then we can say that one of the state associated with certain dynamics is being duplicated.

                                                                    3. Based on some special matrix operations, we arrive at something called as relative-gain-array (RGA). This will give information on how much each states/output of a system interactes with each other, collectively speaking.

                                                                    However, top are just a few examples. There are much more.






                                                                    share|cite|improve this answer









                                                                    $endgroup$



                                                                    In system-theory,



                                                                    1. systems can be represented by matrices and each column represent the internal-state of the system.

                                                                    2. If a determinant of one such matrix is zero, then we can say that one of the state associated with certain dynamics is being duplicated.

                                                                    3. Based on some special matrix operations, we arrive at something called as relative-gain-array (RGA). This will give information on how much each states/output of a system interactes with each other, collectively speaking.

                                                                    However, top are just a few examples. There are much more.







                                                                    share|cite|improve this answer












                                                                    share|cite|improve this answer



                                                                    share|cite|improve this answer










                                                                    answered 2 days ago









                                                                    RaajaRaaja

                                                                    208312




                                                                    208312




















                                                                        Vaishakh Sreekanth Menon is a new contributor. Be nice, and check out our Code of Conduct.









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                                                                        Vaishakh Sreekanth Menon is a new contributor. Be nice, and check out our Code of Conduct.












                                                                        Vaishakh Sreekanth Menon is a new contributor. Be nice, and check out our Code of Conduct.











                                                                        Vaishakh Sreekanth Menon is a new contributor. Be nice, and check out our Code of Conduct.














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Hall Of Fame””Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Bullet-For My Valentine booed at Metal Hammer Golden Gods Awards””Unholy Aliance””The End Of Slayer?””Slayer: We Could Thrash Out Two More Albums If We're Fast Enough...””'The Unholy Alliance: Chapter III' UK Dates Added”originalet”Megadeth And Slayer To Co-Headline 'Canadian Carnage' Trek”originalet”World Painted Blood””Release “World Painted Blood” by Slayer””Metallica Heading To Cinemas””Slayer, Megadeth To Join Forces For 'European Carnage' Tour - Dec. 18, 2010”originalet”Slayer's Hanneman Contracts Acute Infection; Band To Bring In Guest Guitarist””Cannibal Corpse's Pat O'Brien Will Step In As Slayer's Guest Guitarist”originalet”Slayer’s Jeff Hanneman Dead at 49””Dave Lombardo Says He Made Only $67,000 In 2011 While Touring With Slayer””Slayer: We Do Not Agree With Dave Lombardo's Substance Or Timeline Of Events””Slayer Welcomes Drummer Paul Bostaph Back To The Fold””Slayer Hope to Unveil Never-Before-Heard Jeff Hanneman Material on Next Album””Slayer Debut New Song 'Implode' During Surprise Golden Gods Appearance””Release group Repentless by Slayer””Repentless - Slayer - Credits””Slayer””Metal Storm Awards 2015””Slayer - to release comic book "Repentless #1"””Slayer To Release 'Repentless' 6.66" Vinyl Box Set””BREAKING NEWS: Slayer Announce Farewell Tour””Slayer Recruit Lamb of God, Anthrax, Behemoth + Testament for Final Tour””Slayer lägger ner efter 37 år””Slayer Announces Second North American Leg Of 'Final' Tour””Final World Tour””Slayer Announces Final European Tour With Lamb of God, Anthrax And Obituary””Slayer To Tour Europe With Lamb of God, Anthrax And Obituary””Slayer To Play 'Last French Show Ever' At Next Year's Hellfst””Slayer's Final World Tour Will Extend Into 2019””Death Angel's Rob Cavestany On Slayer's 'Farewell' Tour: 'Some Of Us Could See This Coming'””Testament Has No Plans To Retire Anytime Soon, Says Chuck Billy””Anthrax's Scott Ian On Slayer's 'Farewell' Tour Plans: 'I Was Surprised And I Wasn't Surprised'””Slayer””Slayer's Morbid Schlock””Review/Rock; For Slayer, the Mania Is the Message””Slayer - Biography””Slayer - Reign In Blood”originalet”Dave Lombardo””An exclusive oral history of Slayer”originalet”Exclusive! Interview With Slayer Guitarist Jeff Hanneman”originalet”Thinking Out Loud: Slayer's Kerry King on hair metal, Satan and being polite””Slayer Lyrics””Slayer - Biography””Most influential artists for extreme metal music””Slayer - Reign in Blood””Slayer guitarist Jeff Hanneman dies aged 49””Slatanic Slaughter: A Tribute to Slayer””Gateway to Hell: A Tribute to Slayer””Covered In Blood””Slayer: The Origins of Thrash in San Francisco, CA.””Why They Rule - #6 Slayer”originalet”Guitar World's 100 Greatest Heavy Metal Guitarists Of All Time”originalet”The fans have spoken: Slayer comes out on top in readers' polls”originalet”Tribute to Jeff Hanneman (1964-2013)””Lamb Of God Frontman: We Sound Like A Slayer Rip-Off””BEHEMOTH Frontman Pays Tribute To SLAYER's JEFF HANNEMAN””Slayer, Hatebreed Doing Double Duty On This Year's Ozzfest””System of a Down””Lacuna Coil’s Andrea Ferro Talks Influences, Skateboarding, Band Origins + More””Slayer - Reign in Blood””Into The Lungs of Hell””Slayer rules - en utställning om fans””Slayer and Their Fans Slashed Through a No-Holds-Barred Night at Gas Monkey””Home””Slayer””Gold & Platinum - The Big 4 Live from Sofia, Bulgaria””Exclusive! Interview With Slayer Guitarist Kerry King””2008-02-23: Wiltern, Los Angeles, CA, USA””Slayer's Kerry King To Perform With Megadeth Tonight! - Oct. 21, 2010”originalet”Dave Lombardo - Biography”Slayer Case DismissedArkiveradUltimate Classic Rock: Slayer guitarist Jeff Hanneman dead at 49.”Slayer: "We could never do any thing like Some Kind Of Monster..."””Cannibal Corpse'S Pat O'Brien Will Step In As Slayer'S Guest Guitarist | The Official Slayer Site”originalet”Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Kerrang! Awards 2006 Blog: Kerrang! Hall Of Fame””Kerrang! Awards 2013: Kerrang! Legend”originalet”Metallica, Slayer, Iron Maien Among Winners At Metal Hammer Awards””Metal Hammer Golden Gods Awards””Bullet For My Valentine Booed At Metal Hammer Golden Gods Awards””Metal Storm Awards 2006””Metal Storm Awards 2015””Slayer's Concert History””Slayer - Relationships””Slayer - Releases”Slayers officiella webbplatsSlayer på MusicBrainzOfficiell webbplatsSlayerSlayerr1373445760000 0001 1540 47353068615-5086262726cb13906545x(data)6033143kn20030215029