Difference between -| and |- in TikZ Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: What EXACTLY does the the |- notation for arrows do?Insertion of perpendicular symbol at intersection of two perpendicular linesHow to Mark Right Angle in TikzMatrices and TikZ : arrows inside the matrixOmit the same coordinate parameters in drawing line in tikzHow to add perpendicular symbol at desired locationHelp on LateX Diagram using TikZ packageHow to fix TikZ corners in 3DTweaking behaviour of tikz trees for Feynman diagramsTikZ: how to find the intersection of two extended lines?Right Angle Symbol Alignment with TikZ/CalcWhat's the difference between path and draw in Tikz?A display indicating the definition of the distance between a point and a line (using only TikZ)How filling angle symbol?TikZ: bad line caps at the intersectionsSmoothing out angles made up of different line widthsTikZ calculate in/out-angle from nodes
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Difference between -| and |- in TikZ
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: What EXACTLY does the the |- notation for arrows do?Insertion of perpendicular symbol at intersection of two perpendicular linesHow to Mark Right Angle in TikzMatrices and TikZ : arrows inside the matrixOmit the same coordinate parameters in drawing line in tikzHow to add perpendicular symbol at desired locationHelp on LateX Diagram using TikZ packageHow to fix TikZ corners in 3DTweaking behaviour of tikz trees for Feynman diagramsTikZ: how to find the intersection of two extended lines?Right Angle Symbol Alignment with TikZ/CalcWhat's the difference between path and draw in Tikz?A display indicating the definition of the distance between a point and a line (using only TikZ)How filling angle symbol?TikZ: bad line caps at the intersectionsSmoothing out angles made up of different line widthsTikZ calculate in/out-angle from nodes
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
add a comment |
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
tikz-pgf
asked Mar 24 at 12:16
subham sonisubham soni
5,03783188
5,03783188
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
1
1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33
add a comment |
3 Answers
3
active
oldest
votes
Understand it as it looks like:
-|
is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.|-
is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
Mar 25 at 5:56
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)(A-|B)
(TikZ) =(B|A)
(PSTricks)
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Understand it as it looks like:
-|
is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.|-
is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
add a comment |
Understand it as it looks like:
-|
is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.|-
is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
add a comment |
Understand it as it looks like:
-|
is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.|-
is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
Understand it as it looks like:
-|
is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.|-
is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(4,2)$;
draw (6,0) coordinate (y) node[below] $(6,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
edited 3 hours ago
answered Mar 24 at 13:55
JouleVJouleV
14.6k22665
14.6k22665
add a comment |
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
Mar 25 at 5:56
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
Mar 25 at 5:56
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
edited Mar 25 at 5:54
answered Mar 24 at 18:14
CarLaTeXCarLaTeX
34.9k553145
34.9k553145
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
Mar 25 at 5:56
add a comment |
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
Mar 25 at 5:56
2
2
You're welcome! I edited my answer to put x and y within
$...$
.– CarLaTeX
Mar 25 at 5:56
You're welcome! I edited my answer to put x and y within
$...$
.– CarLaTeX
Mar 25 at 5:56
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)(A-|B)
(TikZ) =(B|A)
(PSTricks)
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)(A-|B)
(TikZ) =(B|A)
(PSTricks)
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)(A-|B)
(TikZ) =(B|A)
(PSTricks)
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)(A-|B)
(TikZ) =(B|A)
(PSTricks)
answered Mar 24 at 18:31
Artificial Hairless ArmpitArtificial Hairless Armpit
5,06411243
5,06411243
add a comment |
add a comment |
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1
tex.stackexchange.com/a/401429/121799
– marmot
Mar 24 at 12:33