Difference between -| and |- in TikZ Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: What EXACTLY does the the |- notation for arrows do?Insertion of perpendicular symbol at intersection of two perpendicular linesHow to Mark Right Angle in TikzMatrices and TikZ : arrows inside the matrixOmit the same coordinate parameters in drawing line in tikzHow to add perpendicular symbol at desired locationHelp on LateX Diagram using TikZ packageHow to fix TikZ corners in 3DTweaking behaviour of tikz trees for Feynman diagramsTikZ: how to find the intersection of two extended lines?Right Angle Symbol Alignment with TikZ/CalcWhat's the difference between path and draw in Tikz?A display indicating the definition of the distance between a point and a line (using only TikZ)How filling angle symbol?TikZ: bad line caps at the intersectionsSmoothing out angles made up of different line widthsTikZ calculate in/out-angle from nodes

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Difference between -| and |- in TikZ



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: What EXACTLY does the the |- notation for arrows do?Insertion of perpendicular symbol at intersection of two perpendicular linesHow to Mark Right Angle in TikzMatrices and TikZ : arrows inside the matrixOmit the same coordinate parameters in drawing line in tikzHow to add perpendicular symbol at desired locationHelp on LateX Diagram using TikZ packageHow to fix TikZ corners in 3DTweaking behaviour of tikz trees for Feynman diagramsTikZ: how to find the intersection of two extended lines?Right Angle Symbol Alignment with TikZ/CalcWhat's the difference between path and draw in Tikz?A display indicating the definition of the distance between a point and a line (using only TikZ)How filling angle symbol?TikZ: bad line caps at the intersectionsSmoothing out angles made up of different line widthsTikZ calculate in/out-angle from nodes










12















Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.



But I wish to understand the difference between the two.



There are the following related questions:



  1. Insertion of perpendicular symbol at intersection of two perpendicular lines

  2. How to add perpendicular symbol at desired location

  3. How to Mark Right Angle in Tikz

But none of them seem to use the approach of -| and |-.










share|improve this question

















  • 1





    tex.stackexchange.com/a/401429/121799

    – marmot
    Mar 24 at 12:33















12















Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.



But I wish to understand the difference between the two.



There are the following related questions:



  1. Insertion of perpendicular symbol at intersection of two perpendicular lines

  2. How to add perpendicular symbol at desired location

  3. How to Mark Right Angle in Tikz

But none of them seem to use the approach of -| and |-.










share|improve this question

















  • 1





    tex.stackexchange.com/a/401429/121799

    – marmot
    Mar 24 at 12:33













12












12








12


0






Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.



But I wish to understand the difference between the two.



There are the following related questions:



  1. Insertion of perpendicular symbol at intersection of two perpendicular lines

  2. How to add perpendicular symbol at desired location

  3. How to Mark Right Angle in Tikz

But none of them seem to use the approach of -| and |-.










share|improve this question














Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.



But I wish to understand the difference between the two.



There are the following related questions:



  1. Insertion of perpendicular symbol at intersection of two perpendicular lines

  2. How to add perpendicular symbol at desired location

  3. How to Mark Right Angle in Tikz

But none of them seem to use the approach of -| and |-.







tikz-pgf






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 24 at 12:16









subham sonisubham soni

5,03783188




5,03783188







  • 1





    tex.stackexchange.com/a/401429/121799

    – marmot
    Mar 24 at 12:33












  • 1





    tex.stackexchange.com/a/401429/121799

    – marmot
    Mar 24 at 12:33







1




1





tex.stackexchange.com/a/401429/121799

– marmot
Mar 24 at 12:33





tex.stackexchange.com/a/401429/121799

– marmot
Mar 24 at 12:33










3 Answers
3






active

oldest

votes


















22














Understand it as it looks like:




  • -| is "horizontal line → vertical line":



    documentclass[tikz]standalone
    begindocument
    begintikzpicture
    draw (0,0) coordinate (1) node[below] $(0,0)$;
    draw (2,2) coordinate (2) node[above] $(2,2)$;
    draw (1) -| (2);
    % -------------
    draw (4,2) coordinate (x) node[above] $(4,2)$;
    draw (6,0) coordinate (y) node[below] $(6,0)$;
    draw (x) -| (y);
    endtikzpicture
    enddocument


    enter image description here



    Mathematically, (x,y) -| (a,b) and (x,y) -- (a,y) -- (a,b) are the same.




  • |- is "vertical line → horizontal line":



    documentclass[tikz]standalone
    begindocument
    begintikzpicture
    draw (0,0) coordinate (1) node[below] $(0,0)$;
    draw (2,2) coordinate (2) node[above] $(2,2)$;
    draw (1) |- (2);
    % -------------
    draw (4,2) coordinate (x) node[above] $(4,2)$;
    draw (6,0) coordinate (y) node[below] $(6,0)$;
    draw (x) |- (y);
    endtikzpicture
    enddocument


    enter image description here



    Mathematically, (x,y) |- (a,b) and (x,y) -- (x,b) -- (a,b) are the same.



They are clearly very different.






share|improve this answer
































    18














    I'd like to add to JouleV's answer another use of -| and |-.



    Given two nodes, A and B:



    • if you use (A |- B) you have a point with the x coordinate of A and the y coordinate of B

    • if you use (A -| B) you have a point with the x coordinate of B and the y coordinate of A.



    documentclassarticle
    usepackageamsmath
    usepackagetikz
    usetikzlibrarypositioning

    begindocument
    begintikzpicture
    node[draw] (A) A;
    node[draw, above right =4cm of A] (B) B;
    node[draw] at (A |- B) $x$ of A, $y$ of B;
    node[draw] at (A -| B) $x$ of B, $y$ of A;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer




















    • 2





      You're welcome! I edited my answer to put x and y within $...$.

      – CarLaTeX
      Mar 25 at 5:56


















    6














    PSTricks version for @CarLaTeX's explanation:




    • (A|-B) (TikZ) = (A|B) (PSTricks)


    • (A-|B) (TikZ) = (B|A) (PSTricks)





    share|improve this answer























      Your Answer








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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      22














      Understand it as it looks like:




      • -| is "horizontal line → vertical line":



        documentclass[tikz]standalone
        begindocument
        begintikzpicture
        draw (0,0) coordinate (1) node[below] $(0,0)$;
        draw (2,2) coordinate (2) node[above] $(2,2)$;
        draw (1) -| (2);
        % -------------
        draw (4,2) coordinate (x) node[above] $(4,2)$;
        draw (6,0) coordinate (y) node[below] $(6,0)$;
        draw (x) -| (y);
        endtikzpicture
        enddocument


        enter image description here



        Mathematically, (x,y) -| (a,b) and (x,y) -- (a,y) -- (a,b) are the same.




      • |- is "vertical line → horizontal line":



        documentclass[tikz]standalone
        begindocument
        begintikzpicture
        draw (0,0) coordinate (1) node[below] $(0,0)$;
        draw (2,2) coordinate (2) node[above] $(2,2)$;
        draw (1) |- (2);
        % -------------
        draw (4,2) coordinate (x) node[above] $(4,2)$;
        draw (6,0) coordinate (y) node[below] $(6,0)$;
        draw (x) |- (y);
        endtikzpicture
        enddocument


        enter image description here



        Mathematically, (x,y) |- (a,b) and (x,y) -- (x,b) -- (a,b) are the same.



      They are clearly very different.






      share|improve this answer





























        22














        Understand it as it looks like:




        • -| is "horizontal line → vertical line":



          documentclass[tikz]standalone
          begindocument
          begintikzpicture
          draw (0,0) coordinate (1) node[below] $(0,0)$;
          draw (2,2) coordinate (2) node[above] $(2,2)$;
          draw (1) -| (2);
          % -------------
          draw (4,2) coordinate (x) node[above] $(4,2)$;
          draw (6,0) coordinate (y) node[below] $(6,0)$;
          draw (x) -| (y);
          endtikzpicture
          enddocument


          enter image description here



          Mathematically, (x,y) -| (a,b) and (x,y) -- (a,y) -- (a,b) are the same.




        • |- is "vertical line → horizontal line":



          documentclass[tikz]standalone
          begindocument
          begintikzpicture
          draw (0,0) coordinate (1) node[below] $(0,0)$;
          draw (2,2) coordinate (2) node[above] $(2,2)$;
          draw (1) |- (2);
          % -------------
          draw (4,2) coordinate (x) node[above] $(4,2)$;
          draw (6,0) coordinate (y) node[below] $(6,0)$;
          draw (x) |- (y);
          endtikzpicture
          enddocument


          enter image description here



          Mathematically, (x,y) |- (a,b) and (x,y) -- (x,b) -- (a,b) are the same.



        They are clearly very different.






        share|improve this answer



























          22












          22








          22







          Understand it as it looks like:




          • -| is "horizontal line → vertical line":



            documentclass[tikz]standalone
            begindocument
            begintikzpicture
            draw (0,0) coordinate (1) node[below] $(0,0)$;
            draw (2,2) coordinate (2) node[above] $(2,2)$;
            draw (1) -| (2);
            % -------------
            draw (4,2) coordinate (x) node[above] $(4,2)$;
            draw (6,0) coordinate (y) node[below] $(6,0)$;
            draw (x) -| (y);
            endtikzpicture
            enddocument


            enter image description here



            Mathematically, (x,y) -| (a,b) and (x,y) -- (a,y) -- (a,b) are the same.




          • |- is "vertical line → horizontal line":



            documentclass[tikz]standalone
            begindocument
            begintikzpicture
            draw (0,0) coordinate (1) node[below] $(0,0)$;
            draw (2,2) coordinate (2) node[above] $(2,2)$;
            draw (1) |- (2);
            % -------------
            draw (4,2) coordinate (x) node[above] $(4,2)$;
            draw (6,0) coordinate (y) node[below] $(6,0)$;
            draw (x) |- (y);
            endtikzpicture
            enddocument


            enter image description here



            Mathematically, (x,y) |- (a,b) and (x,y) -- (x,b) -- (a,b) are the same.



          They are clearly very different.






          share|improve this answer















          Understand it as it looks like:




          • -| is "horizontal line → vertical line":



            documentclass[tikz]standalone
            begindocument
            begintikzpicture
            draw (0,0) coordinate (1) node[below] $(0,0)$;
            draw (2,2) coordinate (2) node[above] $(2,2)$;
            draw (1) -| (2);
            % -------------
            draw (4,2) coordinate (x) node[above] $(4,2)$;
            draw (6,0) coordinate (y) node[below] $(6,0)$;
            draw (x) -| (y);
            endtikzpicture
            enddocument


            enter image description here



            Mathematically, (x,y) -| (a,b) and (x,y) -- (a,y) -- (a,b) are the same.




          • |- is "vertical line → horizontal line":



            documentclass[tikz]standalone
            begindocument
            begintikzpicture
            draw (0,0) coordinate (1) node[below] $(0,0)$;
            draw (2,2) coordinate (2) node[above] $(2,2)$;
            draw (1) |- (2);
            % -------------
            draw (4,2) coordinate (x) node[above] $(4,2)$;
            draw (6,0) coordinate (y) node[below] $(6,0)$;
            draw (x) |- (y);
            endtikzpicture
            enddocument


            enter image description here



            Mathematically, (x,y) |- (a,b) and (x,y) -- (x,b) -- (a,b) are the same.



          They are clearly very different.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 3 hours ago

























          answered Mar 24 at 13:55









          JouleVJouleV

          14.6k22665




          14.6k22665





















              18














              I'd like to add to JouleV's answer another use of -| and |-.



              Given two nodes, A and B:



              • if you use (A |- B) you have a point with the x coordinate of A and the y coordinate of B

              • if you use (A -| B) you have a point with the x coordinate of B and the y coordinate of A.



              documentclassarticle
              usepackageamsmath
              usepackagetikz
              usetikzlibrarypositioning

              begindocument
              begintikzpicture
              node[draw] (A) A;
              node[draw, above right =4cm of A] (B) B;
              node[draw] at (A |- B) $x$ of A, $y$ of B;
              node[draw] at (A -| B) $x$ of B, $y$ of A;
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer




















              • 2





                You're welcome! I edited my answer to put x and y within $...$.

                – CarLaTeX
                Mar 25 at 5:56















              18














              I'd like to add to JouleV's answer another use of -| and |-.



              Given two nodes, A and B:



              • if you use (A |- B) you have a point with the x coordinate of A and the y coordinate of B

              • if you use (A -| B) you have a point with the x coordinate of B and the y coordinate of A.



              documentclassarticle
              usepackageamsmath
              usepackagetikz
              usetikzlibrarypositioning

              begindocument
              begintikzpicture
              node[draw] (A) A;
              node[draw, above right =4cm of A] (B) B;
              node[draw] at (A |- B) $x$ of A, $y$ of B;
              node[draw] at (A -| B) $x$ of B, $y$ of A;
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer




















              • 2





                You're welcome! I edited my answer to put x and y within $...$.

                – CarLaTeX
                Mar 25 at 5:56













              18












              18








              18







              I'd like to add to JouleV's answer another use of -| and |-.



              Given two nodes, A and B:



              • if you use (A |- B) you have a point with the x coordinate of A and the y coordinate of B

              • if you use (A -| B) you have a point with the x coordinate of B and the y coordinate of A.



              documentclassarticle
              usepackageamsmath
              usepackagetikz
              usetikzlibrarypositioning

              begindocument
              begintikzpicture
              node[draw] (A) A;
              node[draw, above right =4cm of A] (B) B;
              node[draw] at (A |- B) $x$ of A, $y$ of B;
              node[draw] at (A -| B) $x$ of B, $y$ of A;
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer















              I'd like to add to JouleV's answer another use of -| and |-.



              Given two nodes, A and B:



              • if you use (A |- B) you have a point with the x coordinate of A and the y coordinate of B

              • if you use (A -| B) you have a point with the x coordinate of B and the y coordinate of A.



              documentclassarticle
              usepackageamsmath
              usepackagetikz
              usetikzlibrarypositioning

              begindocument
              begintikzpicture
              node[draw] (A) A;
              node[draw, above right =4cm of A] (B) B;
              node[draw] at (A |- B) $x$ of A, $y$ of B;
              node[draw] at (A -| B) $x$ of B, $y$ of A;
              endtikzpicture
              enddocument


              enter image description here







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Mar 25 at 5:54

























              answered Mar 24 at 18:14









              CarLaTeXCarLaTeX

              34.9k553145




              34.9k553145







              • 2





                You're welcome! I edited my answer to put x and y within $...$.

                – CarLaTeX
                Mar 25 at 5:56












              • 2





                You're welcome! I edited my answer to put x and y within $...$.

                – CarLaTeX
                Mar 25 at 5:56







              2




              2





              You're welcome! I edited my answer to put x and y within $...$.

              – CarLaTeX
              Mar 25 at 5:56





              You're welcome! I edited my answer to put x and y within $...$.

              – CarLaTeX
              Mar 25 at 5:56











              6














              PSTricks version for @CarLaTeX's explanation:




              • (A|-B) (TikZ) = (A|B) (PSTricks)


              • (A-|B) (TikZ) = (B|A) (PSTricks)





              share|improve this answer



























                6














                PSTricks version for @CarLaTeX's explanation:




                • (A|-B) (TikZ) = (A|B) (PSTricks)


                • (A-|B) (TikZ) = (B|A) (PSTricks)





                share|improve this answer

























                  6












                  6








                  6







                  PSTricks version for @CarLaTeX's explanation:




                  • (A|-B) (TikZ) = (A|B) (PSTricks)


                  • (A-|B) (TikZ) = (B|A) (PSTricks)





                  share|improve this answer













                  PSTricks version for @CarLaTeX's explanation:




                  • (A|-B) (TikZ) = (A|B) (PSTricks)


                  • (A-|B) (TikZ) = (B|A) (PSTricks)






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 24 at 18:31









                  Artificial Hairless ArmpitArtificial Hairless Armpit

                  5,06411243




                  5,06411243



























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Hall Of Fame””Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Bullet-For My Valentine booed at Metal Hammer Golden Gods Awards””Unholy Aliance””The End Of Slayer?””Slayer: We Could Thrash Out Two More Albums If We're Fast Enough...””'The Unholy Alliance: Chapter III' UK Dates Added”originalet”Megadeth And Slayer To Co-Headline 'Canadian Carnage' Trek”originalet”World Painted Blood””Release “World Painted Blood” by Slayer””Metallica Heading To Cinemas””Slayer, Megadeth To Join Forces For 'European Carnage' Tour - Dec. 18, 2010”originalet”Slayer's Hanneman Contracts Acute Infection; Band To Bring In Guest Guitarist””Cannibal Corpse's Pat O'Brien Will Step In As Slayer's Guest Guitarist”originalet”Slayer’s Jeff Hanneman Dead at 49””Dave Lombardo Says He Made Only $67,000 In 2011 While Touring With Slayer””Slayer: We Do Not Agree With Dave Lombardo's Substance Or Timeline Of Events””Slayer Welcomes Drummer Paul Bostaph Back To The Fold””Slayer Hope to Unveil Never-Before-Heard Jeff Hanneman Material on Next Album””Slayer Debut New Song 'Implode' During Surprise Golden Gods Appearance””Release group Repentless by Slayer””Repentless - Slayer - Credits””Slayer””Metal Storm Awards 2015””Slayer - to release comic book "Repentless #1"””Slayer To Release 'Repentless' 6.66" Vinyl Box Set””BREAKING NEWS: Slayer Announce Farewell Tour””Slayer Recruit Lamb of God, Anthrax, Behemoth + Testament for Final Tour””Slayer lägger ner efter 37 år””Slayer Announces Second North American Leg Of 'Final' Tour””Final World Tour””Slayer Announces Final European Tour With Lamb of God, Anthrax And Obituary””Slayer To Tour Europe With Lamb of God, Anthrax And Obituary””Slayer To Play 'Last French Show Ever' At Next Year's Hellfst””Slayer's Final World Tour Will Extend Into 2019””Death Angel's Rob Cavestany On Slayer's 'Farewell' Tour: 'Some Of Us Could See This Coming'””Testament Has No Plans To Retire Anytime Soon, Says Chuck Billy””Anthrax's Scott Ian On Slayer's 'Farewell' Tour Plans: 'I Was Surprised And I Wasn't Surprised'””Slayer””Slayer's Morbid Schlock””Review/Rock; For Slayer, the Mania Is the Message””Slayer - Biography””Slayer - Reign In Blood”originalet”Dave Lombardo””An exclusive oral history of Slayer”originalet”Exclusive! Interview With Slayer Guitarist Jeff Hanneman”originalet”Thinking Out Loud: Slayer's Kerry King on hair metal, Satan and being polite””Slayer Lyrics””Slayer - Biography””Most influential artists for extreme metal music””Slayer - Reign in Blood””Slayer guitarist Jeff Hanneman dies aged 49””Slatanic Slaughter: A Tribute to Slayer””Gateway to Hell: A Tribute to Slayer””Covered In Blood””Slayer: The Origins of Thrash in San Francisco, CA.””Why They Rule - #6 Slayer”originalet”Guitar World's 100 Greatest Heavy Metal Guitarists Of All Time”originalet”The fans have spoken: Slayer comes out on top in readers' polls”originalet”Tribute to Jeff Hanneman (1964-2013)””Lamb Of God Frontman: We Sound Like A Slayer Rip-Off””BEHEMOTH Frontman Pays Tribute To SLAYER's JEFF HANNEMAN””Slayer, Hatebreed Doing Double Duty On This Year's Ozzfest””System of a Down””Lacuna Coil’s Andrea Ferro Talks Influences, Skateboarding, Band Origins + More””Slayer - Reign in Blood””Into The Lungs of Hell””Slayer rules - en utställning om fans””Slayer and Their Fans Slashed Through a No-Holds-Barred Night at Gas Monkey””Home””Slayer””Gold & Platinum - The Big 4 Live from Sofia, Bulgaria””Exclusive! Interview With Slayer Guitarist Kerry King””2008-02-23: Wiltern, Los Angeles, CA, USA””Slayer's Kerry King To Perform With Megadeth Tonight! - Oct. 21, 2010”originalet”Dave Lombardo - Biography”Slayer Case DismissedArkiveradUltimate Classic Rock: Slayer guitarist Jeff Hanneman dead at 49.”Slayer: "We could never do any thing like Some Kind Of Monster..."””Cannibal Corpse'S Pat O'Brien Will Step In As Slayer'S Guest Guitarist | The Official Slayer Site”originalet”Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Kerrang! Awards 2006 Blog: Kerrang! Hall Of Fame””Kerrang! Awards 2013: Kerrang! Legend”originalet”Metallica, Slayer, Iron Maien Among Winners At Metal Hammer Awards””Metal Hammer Golden Gods Awards””Bullet For My Valentine Booed At Metal Hammer Golden Gods Awards””Metal Storm Awards 2006””Metal Storm Awards 2015””Slayer's Concert History””Slayer - Relationships””Slayer - Releases”Slayers officiella webbplatsSlayer på MusicBrainzOfficiell webbplatsSlayerSlayerr1373445760000 0001 1540 47353068615-5086262726cb13906545x(data)6033143kn20030215029