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What is the adequate fee for a reveal operation?


How does Tezos manage its mempool?What elliptic curves are used by Tezos?What is the difference between implicit vs originated accounts?How does tezos-client compute a transaction fee?Why a reveal operation?How to manage rewards for small delegators?how to transaction from a KT1 address to another KT1 address?When setting up a contract, what do the fields mean?













4















When transferring funds to a non-revealed Tezos account, one must pay a "reveal fee".



  • What is the optimal value to use for this fee?

  • Or is this a fixed amount?

  • What would be the adequate fee for a reveal operation?









share|improve this question




























    4















    When transferring funds to a non-revealed Tezos account, one must pay a "reveal fee".



    • What is the optimal value to use for this fee?

    • Or is this a fixed amount?

    • What would be the adequate fee for a reveal operation?









    share|improve this question


























      4












      4








      4


      1






      When transferring funds to a non-revealed Tezos account, one must pay a "reveal fee".



      • What is the optimal value to use for this fee?

      • Or is this a fixed amount?

      • What would be the adequate fee for a reveal operation?









      share|improve this question
















      When transferring funds to a non-revealed Tezos account, one must pay a "reveal fee".



      • What is the optimal value to use for this fee?

      • Or is this a fixed amount?

      • What would be the adequate fee for a reveal operation?






      account transfer reveal fee






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 24 mins ago









      Ezy

      2,703630




      2,703630










      asked 23 hours ago









      Luiz MilfontLuiz Milfont

      1175




      1175




















          2 Answers
          2






          active

          oldest

          votes


















          6














          The question as stated confuses different things.



          A "reveal" operation is an operation that writes on the chain the public key associated with a public key hash for an implicit account. The fee associated with this operation is up for the sender to decide, though most bakers implement default minimum fees (in this case it is currently 1267µꜩ).



          The creation of a new account by sending tokens to an implicit address is not a "reveal" operation as the public key needs not be known in this operation. However, it does trigger the creation of an implicit account on the chain. Storage cost has to be paid, and it is not a part of the transaction fee. It is deducted directly from the account making the transaction, though it is subject to a cap specified by the sender. The default value for the storage cost incurred is indeed 0.257 XTZ.






          share|improve this answer




















          • 1





            Thank you both. My intention is, indeed, specify a fee to cover the costs of a creation of a new account when sending tokens to it.

            – Luiz Milfont
            21 hours ago


















          2














          The fee for adding a new account to the global state (--burn-cap with tezos-client) is 0.257 XTZ.



          The origination burn is calculated as Tez_repr.(cost_per_byte *? (Int64.of_int origination_size)).



          cost_per_byte is 0.001 XTZ. It is 1000 mutez and 1,000,000 mutez == 1 tez.



          origination_size is 257.



          Due to that the resulting cost for an origination of a completely new account is 257,000 mutez or 0.257 tez.



          This is defined in proto_alpha/lib_protocol/fee_storage.ml, proto_alpha/lib_protocol/constants_repr.ml, and proto_alpha/lib_protocol/qty_repr.ml






          share|improve this answer




















          • 1





            That's incorrect, the origination burn is not part of the transaction fee.

            – Arthur B
            21 hours ago











          • Yes, you are correct. I have edited the above answer to clarify that the fee that I describe there is for adding a new account to the state.

            – adrian
            21 hours ago






          • 2





            I suggest keeping the terminology separate: "Fee" means paid to the baker. "Burn" means destroyed.

            – Tom
            17 hours ago










          Your Answer








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          2 Answers
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          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          6














          The question as stated confuses different things.



          A "reveal" operation is an operation that writes on the chain the public key associated with a public key hash for an implicit account. The fee associated with this operation is up for the sender to decide, though most bakers implement default minimum fees (in this case it is currently 1267µꜩ).



          The creation of a new account by sending tokens to an implicit address is not a "reveal" operation as the public key needs not be known in this operation. However, it does trigger the creation of an implicit account on the chain. Storage cost has to be paid, and it is not a part of the transaction fee. It is deducted directly from the account making the transaction, though it is subject to a cap specified by the sender. The default value for the storage cost incurred is indeed 0.257 XTZ.






          share|improve this answer




















          • 1





            Thank you both. My intention is, indeed, specify a fee to cover the costs of a creation of a new account when sending tokens to it.

            – Luiz Milfont
            21 hours ago















          6














          The question as stated confuses different things.



          A "reveal" operation is an operation that writes on the chain the public key associated with a public key hash for an implicit account. The fee associated with this operation is up for the sender to decide, though most bakers implement default minimum fees (in this case it is currently 1267µꜩ).



          The creation of a new account by sending tokens to an implicit address is not a "reveal" operation as the public key needs not be known in this operation. However, it does trigger the creation of an implicit account on the chain. Storage cost has to be paid, and it is not a part of the transaction fee. It is deducted directly from the account making the transaction, though it is subject to a cap specified by the sender. The default value for the storage cost incurred is indeed 0.257 XTZ.






          share|improve this answer




















          • 1





            Thank you both. My intention is, indeed, specify a fee to cover the costs of a creation of a new account when sending tokens to it.

            – Luiz Milfont
            21 hours ago













          6












          6








          6







          The question as stated confuses different things.



          A "reveal" operation is an operation that writes on the chain the public key associated with a public key hash for an implicit account. The fee associated with this operation is up for the sender to decide, though most bakers implement default minimum fees (in this case it is currently 1267µꜩ).



          The creation of a new account by sending tokens to an implicit address is not a "reveal" operation as the public key needs not be known in this operation. However, it does trigger the creation of an implicit account on the chain. Storage cost has to be paid, and it is not a part of the transaction fee. It is deducted directly from the account making the transaction, though it is subject to a cap specified by the sender. The default value for the storage cost incurred is indeed 0.257 XTZ.






          share|improve this answer















          The question as stated confuses different things.



          A "reveal" operation is an operation that writes on the chain the public key associated with a public key hash for an implicit account. The fee associated with this operation is up for the sender to decide, though most bakers implement default minimum fees (in this case it is currently 1267µꜩ).



          The creation of a new account by sending tokens to an implicit address is not a "reveal" operation as the public key needs not be known in this operation. However, it does trigger the creation of an implicit account on the chain. Storage cost has to be paid, and it is not a part of the transaction fee. It is deducted directly from the account making the transaction, though it is subject to a cap specified by the sender. The default value for the storage cost incurred is indeed 0.257 XTZ.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 20 hours ago

























          answered 21 hours ago









          Arthur BArthur B

          2,386517




          2,386517







          • 1





            Thank you both. My intention is, indeed, specify a fee to cover the costs of a creation of a new account when sending tokens to it.

            – Luiz Milfont
            21 hours ago












          • 1





            Thank you both. My intention is, indeed, specify a fee to cover the costs of a creation of a new account when sending tokens to it.

            – Luiz Milfont
            21 hours ago







          1




          1





          Thank you both. My intention is, indeed, specify a fee to cover the costs of a creation of a new account when sending tokens to it.

          – Luiz Milfont
          21 hours ago





          Thank you both. My intention is, indeed, specify a fee to cover the costs of a creation of a new account when sending tokens to it.

          – Luiz Milfont
          21 hours ago











          2














          The fee for adding a new account to the global state (--burn-cap with tezos-client) is 0.257 XTZ.



          The origination burn is calculated as Tez_repr.(cost_per_byte *? (Int64.of_int origination_size)).



          cost_per_byte is 0.001 XTZ. It is 1000 mutez and 1,000,000 mutez == 1 tez.



          origination_size is 257.



          Due to that the resulting cost for an origination of a completely new account is 257,000 mutez or 0.257 tez.



          This is defined in proto_alpha/lib_protocol/fee_storage.ml, proto_alpha/lib_protocol/constants_repr.ml, and proto_alpha/lib_protocol/qty_repr.ml






          share|improve this answer




















          • 1





            That's incorrect, the origination burn is not part of the transaction fee.

            – Arthur B
            21 hours ago











          • Yes, you are correct. I have edited the above answer to clarify that the fee that I describe there is for adding a new account to the state.

            – adrian
            21 hours ago






          • 2





            I suggest keeping the terminology separate: "Fee" means paid to the baker. "Burn" means destroyed.

            – Tom
            17 hours ago















          2














          The fee for adding a new account to the global state (--burn-cap with tezos-client) is 0.257 XTZ.



          The origination burn is calculated as Tez_repr.(cost_per_byte *? (Int64.of_int origination_size)).



          cost_per_byte is 0.001 XTZ. It is 1000 mutez and 1,000,000 mutez == 1 tez.



          origination_size is 257.



          Due to that the resulting cost for an origination of a completely new account is 257,000 mutez or 0.257 tez.



          This is defined in proto_alpha/lib_protocol/fee_storage.ml, proto_alpha/lib_protocol/constants_repr.ml, and proto_alpha/lib_protocol/qty_repr.ml






          share|improve this answer




















          • 1





            That's incorrect, the origination burn is not part of the transaction fee.

            – Arthur B
            21 hours ago











          • Yes, you are correct. I have edited the above answer to clarify that the fee that I describe there is for adding a new account to the state.

            – adrian
            21 hours ago






          • 2





            I suggest keeping the terminology separate: "Fee" means paid to the baker. "Burn" means destroyed.

            – Tom
            17 hours ago













          2












          2








          2







          The fee for adding a new account to the global state (--burn-cap with tezos-client) is 0.257 XTZ.



          The origination burn is calculated as Tez_repr.(cost_per_byte *? (Int64.of_int origination_size)).



          cost_per_byte is 0.001 XTZ. It is 1000 mutez and 1,000,000 mutez == 1 tez.



          origination_size is 257.



          Due to that the resulting cost for an origination of a completely new account is 257,000 mutez or 0.257 tez.



          This is defined in proto_alpha/lib_protocol/fee_storage.ml, proto_alpha/lib_protocol/constants_repr.ml, and proto_alpha/lib_protocol/qty_repr.ml






          share|improve this answer















          The fee for adding a new account to the global state (--burn-cap with tezos-client) is 0.257 XTZ.



          The origination burn is calculated as Tez_repr.(cost_per_byte *? (Int64.of_int origination_size)).



          cost_per_byte is 0.001 XTZ. It is 1000 mutez and 1,000,000 mutez == 1 tez.



          origination_size is 257.



          Due to that the resulting cost for an origination of a completely new account is 257,000 mutez or 0.257 tez.



          This is defined in proto_alpha/lib_protocol/fee_storage.ml, proto_alpha/lib_protocol/constants_repr.ml, and proto_alpha/lib_protocol/qty_repr.ml







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 21 hours ago

























          answered 22 hours ago









          adrianadrian

          5917




          5917







          • 1





            That's incorrect, the origination burn is not part of the transaction fee.

            – Arthur B
            21 hours ago











          • Yes, you are correct. I have edited the above answer to clarify that the fee that I describe there is for adding a new account to the state.

            – adrian
            21 hours ago






          • 2





            I suggest keeping the terminology separate: "Fee" means paid to the baker. "Burn" means destroyed.

            – Tom
            17 hours ago












          • 1





            That's incorrect, the origination burn is not part of the transaction fee.

            – Arthur B
            21 hours ago











          • Yes, you are correct. I have edited the above answer to clarify that the fee that I describe there is for adding a new account to the state.

            – adrian
            21 hours ago






          • 2





            I suggest keeping the terminology separate: "Fee" means paid to the baker. "Burn" means destroyed.

            – Tom
            17 hours ago







          1




          1





          That's incorrect, the origination burn is not part of the transaction fee.

          – Arthur B
          21 hours ago





          That's incorrect, the origination burn is not part of the transaction fee.

          – Arthur B
          21 hours ago













          Yes, you are correct. I have edited the above answer to clarify that the fee that I describe there is for adding a new account to the state.

          – adrian
          21 hours ago





          Yes, you are correct. I have edited the above answer to clarify that the fee that I describe there is for adding a new account to the state.

          – adrian
          21 hours ago




          2




          2





          I suggest keeping the terminology separate: "Fee" means paid to the baker. "Burn" means destroyed.

          – Tom
          17 hours ago





          I suggest keeping the terminology separate: "Fee" means paid to the baker. "Burn" means destroyed.

          – Tom
          17 hours ago

















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