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Why is short-wave infrared portion of electromagnetic spectrum so sensitive to fire?
Counting animals using near infrared imagery from a droneBest Landsat-5 TM band combination for detecting fire scarsWhy does Landsat 8 panchromatic band NOT include the infrared?Why are Landsat-8 derived NDVI values higher than SAVI values?Why can't get correct RGB img of Landsat 8 using np.dstackWhy Sentinel-2 bands have different spatial resolutionWhy does my rainbow airplane stripes appearing on Sentinel 2 image?Convertion of spectral indices formulas from Landsat to SentinelWhy is satellite imagery data delivered as signed 16 bit integers?InSAR processing: why can't we just compute distances directly from time delays?
After attending a remote sensing workshop and using Copernicus data to monitor natural disaster scenarios, my question could not be fully answered by the instructor. All that was said, was that is in no way associated to thermal IR.
What property does fire have, that makes is visible with shortwave infrared?
remote-sensing copernicus
add a comment |
After attending a remote sensing workshop and using Copernicus data to monitor natural disaster scenarios, my question could not be fully answered by the instructor. All that was said, was that is in no way associated to thermal IR.
What property does fire have, that makes is visible with shortwave infrared?
remote-sensing copernicus
1
This sounds like a question more on-topic at the Earth Science Stack Exchange than here.
– PolyGeo♦
2 hours ago
1
@PolyGeo this is a question about spectral signature, so it also belongs here as long as this site hosts remote sensing questions.
– radouxju
2 hours ago
add a comment |
After attending a remote sensing workshop and using Copernicus data to monitor natural disaster scenarios, my question could not be fully answered by the instructor. All that was said, was that is in no way associated to thermal IR.
What property does fire have, that makes is visible with shortwave infrared?
remote-sensing copernicus
After attending a remote sensing workshop and using Copernicus data to monitor natural disaster scenarios, my question could not be fully answered by the instructor. All that was said, was that is in no way associated to thermal IR.
What property does fire have, that makes is visible with shortwave infrared?
remote-sensing copernicus
remote-sensing copernicus
edited 2 hours ago
PolyGeo♦
53.7k1781244
53.7k1781244
asked 3 hours ago
Robert BuckleyRobert Buckley
4,8501255114
4,8501255114
1
This sounds like a question more on-topic at the Earth Science Stack Exchange than here.
– PolyGeo♦
2 hours ago
1
@PolyGeo this is a question about spectral signature, so it also belongs here as long as this site hosts remote sensing questions.
– radouxju
2 hours ago
add a comment |
1
This sounds like a question more on-topic at the Earth Science Stack Exchange than here.
– PolyGeo♦
2 hours ago
1
@PolyGeo this is a question about spectral signature, so it also belongs here as long as this site hosts remote sensing questions.
– radouxju
2 hours ago
1
1
This sounds like a question more on-topic at the Earth Science Stack Exchange than here.
– PolyGeo♦
2 hours ago
This sounds like a question more on-topic at the Earth Science Stack Exchange than here.
– PolyGeo♦
2 hours ago
1
1
@PolyGeo this is a question about spectral signature, so it also belongs here as long as this site hosts remote sensing questions.
– radouxju
2 hours ago
@PolyGeo this is a question about spectral signature, so it also belongs here as long as this site hosts remote sensing questions.
– radouxju
2 hours ago
add a comment |
1 Answer
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According to Wien's law, the wavelength of the peak emission depends on the temperature.
wavelength_of_peak = 2.898*10^(-3)/T
where T is the temperature in degree Kelvin. So the wavelength of the peak emission decrease when the temperature increases.
For the temparature of the surface of the Earth, you are around 300 K, so the peak is about 10 micrometer (the so called thermal infrared). In case of fire, the temperature is more like 1200 K, so the peak wavelength is close to 2.4, which correspond to the second SWIR band of Landsat.
add a comment |
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1 Answer
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1 Answer
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oldest
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votes
According to Wien's law, the wavelength of the peak emission depends on the temperature.
wavelength_of_peak = 2.898*10^(-3)/T
where T is the temperature in degree Kelvin. So the wavelength of the peak emission decrease when the temperature increases.
For the temparature of the surface of the Earth, you are around 300 K, so the peak is about 10 micrometer (the so called thermal infrared). In case of fire, the temperature is more like 1200 K, so the peak wavelength is close to 2.4, which correspond to the second SWIR band of Landsat.
add a comment |
According to Wien's law, the wavelength of the peak emission depends on the temperature.
wavelength_of_peak = 2.898*10^(-3)/T
where T is the temperature in degree Kelvin. So the wavelength of the peak emission decrease when the temperature increases.
For the temparature of the surface of the Earth, you are around 300 K, so the peak is about 10 micrometer (the so called thermal infrared). In case of fire, the temperature is more like 1200 K, so the peak wavelength is close to 2.4, which correspond to the second SWIR band of Landsat.
add a comment |
According to Wien's law, the wavelength of the peak emission depends on the temperature.
wavelength_of_peak = 2.898*10^(-3)/T
where T is the temperature in degree Kelvin. So the wavelength of the peak emission decrease when the temperature increases.
For the temparature of the surface of the Earth, you are around 300 K, so the peak is about 10 micrometer (the so called thermal infrared). In case of fire, the temperature is more like 1200 K, so the peak wavelength is close to 2.4, which correspond to the second SWIR band of Landsat.
According to Wien's law, the wavelength of the peak emission depends on the temperature.
wavelength_of_peak = 2.898*10^(-3)/T
where T is the temperature in degree Kelvin. So the wavelength of the peak emission decrease when the temperature increases.
For the temparature of the surface of the Earth, you are around 300 K, so the peak is about 10 micrometer (the so called thermal infrared). In case of fire, the temperature is more like 1200 K, so the peak wavelength is close to 2.4, which correspond to the second SWIR band of Landsat.
edited 2 hours ago
answered 2 hours ago
radouxjuradouxju
41.1k144120
41.1k144120
add a comment |
add a comment |
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This sounds like a question more on-topic at the Earth Science Stack Exchange than here.
– PolyGeo♦
2 hours ago
1
@PolyGeo this is a question about spectral signature, so it also belongs here as long as this site hosts remote sensing questions.
– radouxju
2 hours ago