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Java collections sort method for string is not working properly for case sensitive and special characters



2019 Community Moderator ElectionFastest way to determine if an integer's square root is an integerSorted collection in JavaCan I have someone verify my collections for the SCJP ExamClone a single tone objectMethod override returns nullOverriding private methods in (non-)static classesJava - Method executed prior to Default ConstructorWhen use java regular-expression pattern.matcher(), source does not match regex.But, my hope result is ,source matches regexJava collections not sorting complete stringString sort on basis of length and then on basis of case










16















I was working on sorting a list of String in Java (1.8) and came to know that it is not working as expected!



I am trying the following code for sorting:



private Set<String> getTestData() 
Set<String> compRoles = new HashSet<>();
compRoles.add("AA");
compRoles.add("Aa");
compRoles.add("aA");
compRoles.add("aa");
compRoles.add("11");
compRoles.add("117");
compRoles.add("12");
compRoles.add("21");
compRoles.add("!@");
compRoles.add("@!");
compRoles.add("@@!");
compRoles.add("BB");
compRoles.add("Bb");
compRoles.add("bb");
return compRoles;


public static void main(String args[])
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
Collections.sort(test);
System.out.println(test);



Before sort: [AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]



After sort: [!@, 11, 117, 12, 21, @!, @@!, AA, Aa, BB, Bb, aA, aa, bb]



My expectation is: [!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]



Do I need to use something else other that natural sort for this?










share|improve this question



















  • 12





    so, for you 'a' comes before 'A' .. ok. well, you'll need to write your own sorting logic, but it 'll be pretty broad. you'll actually have to compare char by char. good luck.

    – Stultuske
    12 hours ago






  • 7





    The answer is in the question. Given that the natural ordering doesn't order elements as you would like to, you need something else.

    – JB Nizet
    12 hours ago












  • This is already implemented in jQuery sort. datatables.net/examples/styling/bootstrap4 But I don't the the algo they are using! Because of this UI and back-end is not in sync. Any idea on this?

    – Prabal Srivastava
    12 hours ago






  • 1





    The unicode of ! is smaller than that of @ , unicode of @ is small than 1, unicode of 1 is smaller than A, uncicode of A is smaller than a. Hope it answers for the output that you get. Now If you need sorting as per your ordering , implement your comparator.

    – nits.kk
    11 hours ago











  • @nits.kk: I am totally agree with the answer given by jaspreet. We can solve this issue by using docs.oracle.com/javase/7/docs/api/java/text/Collator.html

    – Prabal Srivastava
    10 hours ago















16















I was working on sorting a list of String in Java (1.8) and came to know that it is not working as expected!



I am trying the following code for sorting:



private Set<String> getTestData() 
Set<String> compRoles = new HashSet<>();
compRoles.add("AA");
compRoles.add("Aa");
compRoles.add("aA");
compRoles.add("aa");
compRoles.add("11");
compRoles.add("117");
compRoles.add("12");
compRoles.add("21");
compRoles.add("!@");
compRoles.add("@!");
compRoles.add("@@!");
compRoles.add("BB");
compRoles.add("Bb");
compRoles.add("bb");
return compRoles;


public static void main(String args[])
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
Collections.sort(test);
System.out.println(test);



Before sort: [AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]



After sort: [!@, 11, 117, 12, 21, @!, @@!, AA, Aa, BB, Bb, aA, aa, bb]



My expectation is: [!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]



Do I need to use something else other that natural sort for this?










share|improve this question



















  • 12





    so, for you 'a' comes before 'A' .. ok. well, you'll need to write your own sorting logic, but it 'll be pretty broad. you'll actually have to compare char by char. good luck.

    – Stultuske
    12 hours ago






  • 7





    The answer is in the question. Given that the natural ordering doesn't order elements as you would like to, you need something else.

    – JB Nizet
    12 hours ago












  • This is already implemented in jQuery sort. datatables.net/examples/styling/bootstrap4 But I don't the the algo they are using! Because of this UI and back-end is not in sync. Any idea on this?

    – Prabal Srivastava
    12 hours ago






  • 1





    The unicode of ! is smaller than that of @ , unicode of @ is small than 1, unicode of 1 is smaller than A, uncicode of A is smaller than a. Hope it answers for the output that you get. Now If you need sorting as per your ordering , implement your comparator.

    – nits.kk
    11 hours ago











  • @nits.kk: I am totally agree with the answer given by jaspreet. We can solve this issue by using docs.oracle.com/javase/7/docs/api/java/text/Collator.html

    – Prabal Srivastava
    10 hours ago













16












16








16


4






I was working on sorting a list of String in Java (1.8) and came to know that it is not working as expected!



I am trying the following code for sorting:



private Set<String> getTestData() 
Set<String> compRoles = new HashSet<>();
compRoles.add("AA");
compRoles.add("Aa");
compRoles.add("aA");
compRoles.add("aa");
compRoles.add("11");
compRoles.add("117");
compRoles.add("12");
compRoles.add("21");
compRoles.add("!@");
compRoles.add("@!");
compRoles.add("@@!");
compRoles.add("BB");
compRoles.add("Bb");
compRoles.add("bb");
return compRoles;


public static void main(String args[])
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
Collections.sort(test);
System.out.println(test);



Before sort: [AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]



After sort: [!@, 11, 117, 12, 21, @!, @@!, AA, Aa, BB, Bb, aA, aa, bb]



My expectation is: [!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]



Do I need to use something else other that natural sort for this?










share|improve this question
















I was working on sorting a list of String in Java (1.8) and came to know that it is not working as expected!



I am trying the following code for sorting:



private Set<String> getTestData() 
Set<String> compRoles = new HashSet<>();
compRoles.add("AA");
compRoles.add("Aa");
compRoles.add("aA");
compRoles.add("aa");
compRoles.add("11");
compRoles.add("117");
compRoles.add("12");
compRoles.add("21");
compRoles.add("!@");
compRoles.add("@!");
compRoles.add("@@!");
compRoles.add("BB");
compRoles.add("Bb");
compRoles.add("bb");
return compRoles;


public static void main(String args[])
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
Collections.sort(test);
System.out.println(test);



Before sort: [AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]



After sort: [!@, 11, 117, 12, 21, @!, @@!, AA, Aa, BB, Bb, aA, aa, bb]



My expectation is: [!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]



Do I need to use something else other that natural sort for this?







java sorting collections






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 3 hours ago









Peter Mortensen

13.8k1987113




13.8k1987113










asked 12 hours ago









Prabal SrivastavaPrabal Srivastava

15319




15319







  • 12





    so, for you 'a' comes before 'A' .. ok. well, you'll need to write your own sorting logic, but it 'll be pretty broad. you'll actually have to compare char by char. good luck.

    – Stultuske
    12 hours ago






  • 7





    The answer is in the question. Given that the natural ordering doesn't order elements as you would like to, you need something else.

    – JB Nizet
    12 hours ago












  • This is already implemented in jQuery sort. datatables.net/examples/styling/bootstrap4 But I don't the the algo they are using! Because of this UI and back-end is not in sync. Any idea on this?

    – Prabal Srivastava
    12 hours ago






  • 1





    The unicode of ! is smaller than that of @ , unicode of @ is small than 1, unicode of 1 is smaller than A, uncicode of A is smaller than a. Hope it answers for the output that you get. Now If you need sorting as per your ordering , implement your comparator.

    – nits.kk
    11 hours ago











  • @nits.kk: I am totally agree with the answer given by jaspreet. We can solve this issue by using docs.oracle.com/javase/7/docs/api/java/text/Collator.html

    – Prabal Srivastava
    10 hours ago












  • 12





    so, for you 'a' comes before 'A' .. ok. well, you'll need to write your own sorting logic, but it 'll be pretty broad. you'll actually have to compare char by char. good luck.

    – Stultuske
    12 hours ago






  • 7





    The answer is in the question. Given that the natural ordering doesn't order elements as you would like to, you need something else.

    – JB Nizet
    12 hours ago












  • This is already implemented in jQuery sort. datatables.net/examples/styling/bootstrap4 But I don't the the algo they are using! Because of this UI and back-end is not in sync. Any idea on this?

    – Prabal Srivastava
    12 hours ago






  • 1





    The unicode of ! is smaller than that of @ , unicode of @ is small than 1, unicode of 1 is smaller than A, uncicode of A is smaller than a. Hope it answers for the output that you get. Now If you need sorting as per your ordering , implement your comparator.

    – nits.kk
    11 hours ago











  • @nits.kk: I am totally agree with the answer given by jaspreet. We can solve this issue by using docs.oracle.com/javase/7/docs/api/java/text/Collator.html

    – Prabal Srivastava
    10 hours ago







12




12





so, for you 'a' comes before 'A' .. ok. well, you'll need to write your own sorting logic, but it 'll be pretty broad. you'll actually have to compare char by char. good luck.

– Stultuske
12 hours ago





so, for you 'a' comes before 'A' .. ok. well, you'll need to write your own sorting logic, but it 'll be pretty broad. you'll actually have to compare char by char. good luck.

– Stultuske
12 hours ago




7




7





The answer is in the question. Given that the natural ordering doesn't order elements as you would like to, you need something else.

– JB Nizet
12 hours ago






The answer is in the question. Given that the natural ordering doesn't order elements as you would like to, you need something else.

– JB Nizet
12 hours ago














This is already implemented in jQuery sort. datatables.net/examples/styling/bootstrap4 But I don't the the algo they are using! Because of this UI and back-end is not in sync. Any idea on this?

– Prabal Srivastava
12 hours ago





This is already implemented in jQuery sort. datatables.net/examples/styling/bootstrap4 But I don't the the algo they are using! Because of this UI and back-end is not in sync. Any idea on this?

– Prabal Srivastava
12 hours ago




1




1





The unicode of ! is smaller than that of @ , unicode of @ is small than 1, unicode of 1 is smaller than A, uncicode of A is smaller than a. Hope it answers for the output that you get. Now If you need sorting as per your ordering , implement your comparator.

– nits.kk
11 hours ago





The unicode of ! is smaller than that of @ , unicode of @ is small than 1, unicode of 1 is smaller than A, uncicode of A is smaller than a. Hope it answers for the output that you get. Now If you need sorting as per your ordering , implement your comparator.

– nits.kk
11 hours ago













@nits.kk: I am totally agree with the answer given by jaspreet. We can solve this issue by using docs.oracle.com/javase/7/docs/api/java/text/Collator.html

– Prabal Srivastava
10 hours ago





@nits.kk: I am totally agree with the answer given by jaspreet. We can solve this issue by using docs.oracle.com/javase/7/docs/api/java/text/Collator.html

– Prabal Srivastava
10 hours ago












2 Answers
2






active

oldest

votes


















28














You can use the Collator class of Java.



public static void main(String[] args) 
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
test.sort(Collator.getInstance(Locale.ENGLISH));
System.out.println(test);



Output:-



[AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]
[!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]





share|improve this answer




















  • 1





    Thanks alot (y)

    – Prabal Srivastava
    11 hours ago






  • 2





    Now days the List class has its own sort method, so going through is an unnecessary step. It is a little bit clearer to write the code like this: list.sort(Collator.getInstance(Locale.ENGLISH));.

    – Lii
    8 hours ago











  • Thanks @Lii . Updated the answer. I didn't read he was working in Java 8 so answered Collections.sort instead of list.sort

    – jaspreet
    8 hours ago






  • 1





    It not always clear what Java version to target in our answers. But Java 8 has been out almost 5 years now! I think we can safely assume that that is the standard. Now days you can even declare your list like this: var test = new ArrayList<>(new Test().getTestData());

    – Lii
    7 hours ago



















3














You could create a custom comparator for your sorting logics. After this you can use it like this:



Collections.sort(yourArrayList, new YourComparator());





share|improve this answer























  • Appropriate your answer. I know the use of comparator and comparable. I am looking for the logic or algorithm used behind this.

    – Prabal Srivastava
    12 hours ago







  • 1





    Then you question should look like you need a custom comparator, and should contain question about sorting algortims. The easiest way is to have weights for each letter and compare them in your way.

    – ipave
    12 hours ago










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









28














You can use the Collator class of Java.



public static void main(String[] args) 
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
test.sort(Collator.getInstance(Locale.ENGLISH));
System.out.println(test);



Output:-



[AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]
[!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]





share|improve this answer




















  • 1





    Thanks alot (y)

    – Prabal Srivastava
    11 hours ago






  • 2





    Now days the List class has its own sort method, so going through is an unnecessary step. It is a little bit clearer to write the code like this: list.sort(Collator.getInstance(Locale.ENGLISH));.

    – Lii
    8 hours ago











  • Thanks @Lii . Updated the answer. I didn't read he was working in Java 8 so answered Collections.sort instead of list.sort

    – jaspreet
    8 hours ago






  • 1





    It not always clear what Java version to target in our answers. But Java 8 has been out almost 5 years now! I think we can safely assume that that is the standard. Now days you can even declare your list like this: var test = new ArrayList<>(new Test().getTestData());

    – Lii
    7 hours ago
















28














You can use the Collator class of Java.



public static void main(String[] args) 
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
test.sort(Collator.getInstance(Locale.ENGLISH));
System.out.println(test);



Output:-



[AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]
[!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]





share|improve this answer




















  • 1





    Thanks alot (y)

    – Prabal Srivastava
    11 hours ago






  • 2





    Now days the List class has its own sort method, so going through is an unnecessary step. It is a little bit clearer to write the code like this: list.sort(Collator.getInstance(Locale.ENGLISH));.

    – Lii
    8 hours ago











  • Thanks @Lii . Updated the answer. I didn't read he was working in Java 8 so answered Collections.sort instead of list.sort

    – jaspreet
    8 hours ago






  • 1





    It not always clear what Java version to target in our answers. But Java 8 has been out almost 5 years now! I think we can safely assume that that is the standard. Now days you can even declare your list like this: var test = new ArrayList<>(new Test().getTestData());

    – Lii
    7 hours ago














28












28








28







You can use the Collator class of Java.



public static void main(String[] args) 
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
test.sort(Collator.getInstance(Locale.ENGLISH));
System.out.println(test);



Output:-



[AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]
[!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]





share|improve this answer















You can use the Collator class of Java.



public static void main(String[] args) 
List<String> test = new ArrayList<>(new Test().getTestData());
System.out.println(test);
test.sort(Collator.getInstance(Locale.ENGLISH));
System.out.println(test);



Output:-



[AA, Aa, aA, aa, 11, BB, Bb, bb, 12, @!, @@!, 117, 21, !@]
[!@, @!, @@!, 11, 117, 12, 21, aa, aA, Aa, AA, bb, Bb, BB]






share|improve this answer














share|improve this answer



share|improve this answer








edited 8 hours ago

























answered 12 hours ago









jaspreetjaspreet

774421




774421







  • 1





    Thanks alot (y)

    – Prabal Srivastava
    11 hours ago






  • 2





    Now days the List class has its own sort method, so going through is an unnecessary step. It is a little bit clearer to write the code like this: list.sort(Collator.getInstance(Locale.ENGLISH));.

    – Lii
    8 hours ago











  • Thanks @Lii . Updated the answer. I didn't read he was working in Java 8 so answered Collections.sort instead of list.sort

    – jaspreet
    8 hours ago






  • 1





    It not always clear what Java version to target in our answers. But Java 8 has been out almost 5 years now! I think we can safely assume that that is the standard. Now days you can even declare your list like this: var test = new ArrayList<>(new Test().getTestData());

    – Lii
    7 hours ago













  • 1





    Thanks alot (y)

    – Prabal Srivastava
    11 hours ago






  • 2





    Now days the List class has its own sort method, so going through is an unnecessary step. It is a little bit clearer to write the code like this: list.sort(Collator.getInstance(Locale.ENGLISH));.

    – Lii
    8 hours ago











  • Thanks @Lii . Updated the answer. I didn't read he was working in Java 8 so answered Collections.sort instead of list.sort

    – jaspreet
    8 hours ago






  • 1





    It not always clear what Java version to target in our answers. But Java 8 has been out almost 5 years now! I think we can safely assume that that is the standard. Now days you can even declare your list like this: var test = new ArrayList<>(new Test().getTestData());

    – Lii
    7 hours ago








1




1





Thanks alot (y)

– Prabal Srivastava
11 hours ago





Thanks alot (y)

– Prabal Srivastava
11 hours ago




2




2





Now days the List class has its own sort method, so going through is an unnecessary step. It is a little bit clearer to write the code like this: list.sort(Collator.getInstance(Locale.ENGLISH));.

– Lii
8 hours ago





Now days the List class has its own sort method, so going through is an unnecessary step. It is a little bit clearer to write the code like this: list.sort(Collator.getInstance(Locale.ENGLISH));.

– Lii
8 hours ago













Thanks @Lii . Updated the answer. I didn't read he was working in Java 8 so answered Collections.sort instead of list.sort

– jaspreet
8 hours ago





Thanks @Lii . Updated the answer. I didn't read he was working in Java 8 so answered Collections.sort instead of list.sort

– jaspreet
8 hours ago




1




1





It not always clear what Java version to target in our answers. But Java 8 has been out almost 5 years now! I think we can safely assume that that is the standard. Now days you can even declare your list like this: var test = new ArrayList<>(new Test().getTestData());

– Lii
7 hours ago






It not always clear what Java version to target in our answers. But Java 8 has been out almost 5 years now! I think we can safely assume that that is the standard. Now days you can even declare your list like this: var test = new ArrayList<>(new Test().getTestData());

– Lii
7 hours ago














3














You could create a custom comparator for your sorting logics. After this you can use it like this:



Collections.sort(yourArrayList, new YourComparator());





share|improve this answer























  • Appropriate your answer. I know the use of comparator and comparable. I am looking for the logic or algorithm used behind this.

    – Prabal Srivastava
    12 hours ago







  • 1





    Then you question should look like you need a custom comparator, and should contain question about sorting algortims. The easiest way is to have weights for each letter and compare them in your way.

    – ipave
    12 hours ago















3














You could create a custom comparator for your sorting logics. After this you can use it like this:



Collections.sort(yourArrayList, new YourComparator());





share|improve this answer























  • Appropriate your answer. I know the use of comparator and comparable. I am looking for the logic or algorithm used behind this.

    – Prabal Srivastava
    12 hours ago







  • 1





    Then you question should look like you need a custom comparator, and should contain question about sorting algortims. The easiest way is to have weights for each letter and compare them in your way.

    – ipave
    12 hours ago













3












3








3







You could create a custom comparator for your sorting logics. After this you can use it like this:



Collections.sort(yourArrayList, new YourComparator());





share|improve this answer













You could create a custom comparator for your sorting logics. After this you can use it like this:



Collections.sort(yourArrayList, new YourComparator());






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answered 12 hours ago









ipaveipave

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1889












  • Appropriate your answer. I know the use of comparator and comparable. I am looking for the logic or algorithm used behind this.

    – Prabal Srivastava
    12 hours ago







  • 1





    Then you question should look like you need a custom comparator, and should contain question about sorting algortims. The easiest way is to have weights for each letter and compare them in your way.

    – ipave
    12 hours ago

















  • Appropriate your answer. I know the use of comparator and comparable. I am looking for the logic or algorithm used behind this.

    – Prabal Srivastava
    12 hours ago







  • 1





    Then you question should look like you need a custom comparator, and should contain question about sorting algortims. The easiest way is to have weights for each letter and compare them in your way.

    – ipave
    12 hours ago
















Appropriate your answer. I know the use of comparator and comparable. I am looking for the logic or algorithm used behind this.

– Prabal Srivastava
12 hours ago






Appropriate your answer. I know the use of comparator and comparable. I am looking for the logic or algorithm used behind this.

– Prabal Srivastava
12 hours ago





1




1





Then you question should look like you need a custom comparator, and should contain question about sorting algortims. The easiest way is to have weights for each letter and compare them in your way.

– ipave
12 hours ago





Then you question should look like you need a custom comparator, and should contain question about sorting algortims. The easiest way is to have weights for each letter and compare them in your way.

– ipave
12 hours ago

















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