Populating function inputs from lists
2
$begingroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked Apr 2 at 12:24
BranBran
1365
$endgroup$
add a comment |
2
$begingroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked Apr 2 at 12:24
BranBran
1365
$endgroup$
add a comment |
2
2
2
$begingroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked Apr 2 at 12:24
BranBran
1365
$endgroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
functions procedural-programming
asked Apr 2 at 12:24
BranBran
1365
asked Apr 2 at 12:24
BranBran
1365
asked Apr 2 at 12:24
BranBran
1365
asked Apr 2 at 12:24
BranBran
1365
asked Apr 2 at 12:24
BranBran
1365
1365
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited Apr 2 at 13:55
MarcoB
38.6k557115
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
Apr 2 at 12:34
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
Apr 2 at 12:35
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
Apr 2 at 12:36
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
Apr 2 at 12:39
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
Apr 2 at 12:44
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited Apr 2 at 13:55
MarcoB
38.6k557115
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
Apr 2 at 12:34
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
Apr 2 at 12:35
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
Apr 2 at 12:36
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
Apr 2 at 12:39
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
Apr 2 at 12:44
|
show 1 more comment
7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited Apr 2 at 13:55
MarcoB
38.6k557115
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
Apr 2 at 12:34
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
Apr 2 at 12:35
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
Apr 2 at 12:36
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
Apr 2 at 12:39
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
Apr 2 at 12:44
|
show 1 more comment
7
7
7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited Apr 2 at 13:55
MarcoB
38.6k557115
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
$endgroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited Apr 2 at 13:55
MarcoB
38.6k557115
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
edited Apr 2 at 13:55
MarcoB
38.6k557115
edited Apr 2 at 13:55
MarcoB
38.6k557115
edited Apr 2 at 13:55
MarcoB
38.6k557115
38.6k557115
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
answered Apr 2 at 12:28
Slepecky MamutSlepecky Mamut
720111
720111
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
Apr 2 at 12:34
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
Apr 2 at 12:35
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
Apr 2 at 12:36
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
Apr 2 at 12:39
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
Apr 2 at 12:44
|
show 1 more comment
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
Apr 2 at 12:34
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
Apr 2 at 12:35
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
Apr 2 at 12:36
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
Apr 2 at 12:39
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
Apr 2 at 12:44
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
Apr 2 at 12:34
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
Apr 2 at 12:34
$begingroup$
@Bran it gives exactly what you asked for,
f[x1, x2, x3, y1, y2, y3]...$endgroup$
– Kuba♦
Apr 2 at 12:35
$begingroup$
@Bran it gives exactly what you asked for,
f[x1, x2, x3, y1, y2, y3]...$endgroup$
– Kuba♦
Apr 2 at 12:35
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
Apr 2 at 12:36
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
Apr 2 at 12:36
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Like
f[z1,z2,x1,x2,x3,y1,y2,y3].$endgroup$
– Bran
Apr 2 at 12:39
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Like
f[z1,z2,x1,x2,x3,y1,y2,y3].$endgroup$
– Bran
Apr 2 at 12:39
1
1
$begingroup$
@Bran
f[whatever, ##, whatever2]& @@ ...$endgroup$
– Kuba♦
Apr 2 at 12:44
$begingroup$
@Bran
f[whatever, ##, whatever2]& @@ ...$endgroup$
– Kuba♦
Apr 2 at 12:44
|
show 1 more comment
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