RegEx with d doesn’t work in if-else statement with [[
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
i wrote the following script. It will be used in a build process later. My goal is to decide whether it's a pre release or a release. To archive this i compare $release to a RegEx.
If my RegEx matches it's a pre release, if not it's a release.
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
if [[ "$release" =~ d+.d+.d+[-]+.* ]];then
echo "Pre"
else
echo "Release"
fi
But as result i always end up with the following:
~$ bash releasescript.sh
1.9.2-alpha1
Release
Version:
Ubuntu 18.04.1 LTS
I used this editor to test my RegEx. I'm stuck for at least 6h, so i would appreciate some help greatly.
command-line bash scripts regex
asked May 16 at 10:13
venterventer
1384
add a comment |
i wrote the following script. It will be used in a build process later. My goal is to decide whether it's a pre release or a release. To archive this i compare $release to a RegEx.
If my RegEx matches it's a pre release, if not it's a release.
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
if [[ "$release" =~ d+.d+.d+[-]+.* ]];then
echo "Pre"
else
echo "Release"
fi
But as result i always end up with the following:
~$ bash releasescript.sh
1.9.2-alpha1
Release
Version:
Ubuntu 18.04.1 LTS
I used this editor to test my RegEx. I'm stuck for at least 6h, so i would appreciate some help greatly.
command-line bash scripts regex
asked May 16 at 10:13
venterventer
1384
add a comment |
i wrote the following script. It will be used in a build process later. My goal is to decide whether it's a pre release or a release. To archive this i compare $release to a RegEx.
If my RegEx matches it's a pre release, if not it's a release.
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
if [[ "$release" =~ d+.d+.d+[-]+.* ]];then
echo "Pre"
else
echo "Release"
fi
But as result i always end up with the following:
~$ bash releasescript.sh
1.9.2-alpha1
Release
Version:
Ubuntu 18.04.1 LTS
I used this editor to test my RegEx. I'm stuck for at least 6h, so i would appreciate some help greatly.
command-line bash scripts regex
asked May 16 at 10:13
venterventer
1384
i wrote the following script. It will be used in a build process later. My goal is to decide whether it's a pre release or a release. To archive this i compare $release to a RegEx.
If my RegEx matches it's a pre release, if not it's a release.
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
if [[ "$release" =~ d+.d+.d+[-]+.* ]];then
echo "Pre"
else
echo "Release"
fi
But as result i always end up with the following:
~$ bash releasescript.sh
1.9.2-alpha1
Release
Version:
Ubuntu 18.04.1 LTS
I used this editor to test my RegEx. I'm stuck for at least 6h, so i would appreciate some help greatly.
command-line bash scripts regex
command-line bash scripts regex
asked May 16 at 10:13
venterventer
1384
asked May 16 at 10:13
venterventer
1384
edited May 16 at 11:08
venter
asked May 16 at 10:13
venterventer
1384
asked May 16 at 10:13
venterventer
1384
asked May 16 at 10:13
venterventer
1384
1384
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
d and w don't work in POSIX regular expressions, you could use [[:digit:]] though
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
LANG=C # This needed only if script will be used in locales where digits not 0-9
if [[ "$release" =~ ^[[:digit:]]+.[[:digit:]]+.[[:digit:]]+-+ ]];then
echo "Pre"
else
echo "Release"
fi
I have tested this script, it output "Pre" for given $release
Checked out your regex builder, it works only with perl compatible and javascript regex, while you need posix, or posix extended.
By @dessert:
[0-9]is the shorter alternative to[[:digit:]]. As the beginning
of the string is to be matched, one should add^, while.*at the
end is superfluous:^[0-9]+.[0-9]+.[0-9]+-+– using a group this
can be further shortened to:^([0-9]+.){2}[0-9]+-+
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
4
Beat me to it! Also, fwiw if you'd usedshellcheckthen it has a warning "SC1001: This d will be a regular 'd' in this context.", which is quite helpful. Other answers.
– pbhj
May 16 at 10:45
2
Is [0-9] equivalent to [[:digit:]] though? I was under the impression that POSIX character classes match Unicode characters, so could very well match digits in languages that don't use 0-9.
– Fax
May 16 at 12:38
@Fax Not sure about [0-9] but [A-Z] match unicode characters, the way to change that is only set locale byLANG=C
– LeonidMew
May 16 at 12:46
1
@Fax "Is [0-9] equivalent to [[:digit:]] though?" TIL that the answer is no.
– levant pied
May 16 at 20:25
add a comment |
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d and w don't work in POSIX regular expressions, you could use [[:digit:]] though
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
LANG=C # This needed only if script will be used in locales where digits not 0-9
if [[ "$release" =~ ^[[:digit:]]+.[[:digit:]]+.[[:digit:]]+-+ ]];then
echo "Pre"
else
echo "Release"
fi
I have tested this script, it output "Pre" for given $release
Checked out your regex builder, it works only with perl compatible and javascript regex, while you need posix, or posix extended.
By @dessert:
[0-9]is the shorter alternative to[[:digit:]]. As the beginning
of the string is to be matched, one should add^, while.*at the
end is superfluous:^[0-9]+.[0-9]+.[0-9]+-+– using a group this
can be further shortened to:^([0-9]+.){2}[0-9]+-+
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
4
Beat me to it! Also, fwiw if you'd usedshellcheckthen it has a warning "SC1001: This d will be a regular 'd' in this context.", which is quite helpful. Other answers.
– pbhj
May 16 at 10:45
2
Is [0-9] equivalent to [[:digit:]] though? I was under the impression that POSIX character classes match Unicode characters, so could very well match digits in languages that don't use 0-9.
– Fax
May 16 at 12:38
@Fax Not sure about [0-9] but [A-Z] match unicode characters, the way to change that is only set locale byLANG=C
– LeonidMew
May 16 at 12:46
1
@Fax "Is [0-9] equivalent to [[:digit:]] though?" TIL that the answer is no.
– levant pied
May 16 at 20:25
add a comment |
d and w don't work in POSIX regular expressions, you could use [[:digit:]] though
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
LANG=C # This needed only if script will be used in locales where digits not 0-9
if [[ "$release" =~ ^[[:digit:]]+.[[:digit:]]+.[[:digit:]]+-+ ]];then
echo "Pre"
else
echo "Release"
fi
I have tested this script, it output "Pre" for given $release
Checked out your regex builder, it works only with perl compatible and javascript regex, while you need posix, or posix extended.
By @dessert:
[0-9]is the shorter alternative to[[:digit:]]. As the beginning
of the string is to be matched, one should add^, while.*at the
end is superfluous:^[0-9]+.[0-9]+.[0-9]+-+– using a group this
can be further shortened to:^([0-9]+.){2}[0-9]+-+
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
4
Beat me to it! Also, fwiw if you'd usedshellcheckthen it has a warning "SC1001: This d will be a regular 'd' in this context.", which is quite helpful. Other answers.
– pbhj
May 16 at 10:45
2
Is [0-9] equivalent to [[:digit:]] though? I was under the impression that POSIX character classes match Unicode characters, so could very well match digits in languages that don't use 0-9.
– Fax
May 16 at 12:38
@Fax Not sure about [0-9] but [A-Z] match unicode characters, the way to change that is only set locale byLANG=C
– LeonidMew
May 16 at 12:46
1
@Fax "Is [0-9] equivalent to [[:digit:]] though?" TIL that the answer is no.
– levant pied
May 16 at 20:25
add a comment |
d and w don't work in POSIX regular expressions, you could use [[:digit:]] though
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
LANG=C # This needed only if script will be used in locales where digits not 0-9
if [[ "$release" =~ ^[[:digit:]]+.[[:digit:]]+.[[:digit:]]+-+ ]];then
echo "Pre"
else
echo "Release"
fi
I have tested this script, it output "Pre" for given $release
Checked out your regex builder, it works only with perl compatible and javascript regex, while you need posix, or posix extended.
By @dessert:
[0-9]is the shorter alternative to[[:digit:]]. As the beginning
of the string is to be matched, one should add^, while.*at the
end is superfluous:^[0-9]+.[0-9]+.[0-9]+-+– using a group this
can be further shortened to:^([0-9]+.){2}[0-9]+-+
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
d and w don't work in POSIX regular expressions, you could use [[:digit:]] though
#/bin/bash
release="1.9.2-alpha1"
echo "$release"
LANG=C # This needed only if script will be used in locales where digits not 0-9
if [[ "$release" =~ ^[[:digit:]]+.[[:digit:]]+.[[:digit:]]+-+ ]];then
echo "Pre"
else
echo "Release"
fi
I have tested this script, it output "Pre" for given $release
Checked out your regex builder, it works only with perl compatible and javascript regex, while you need posix, or posix extended.
By @dessert:
[0-9]is the shorter alternative to[[:digit:]]. As the beginning
of the string is to be matched, one should add^, while.*at the
end is superfluous:^[0-9]+.[0-9]+.[0-9]+-+– using a group this
can be further shortened to:^([0-9]+.){2}[0-9]+-+
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
edited May 16 at 13:09
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
answered May 16 at 10:41
LeonidMewLeonidMew
1,8851127
1,8851127
4
Beat me to it! Also, fwiw if you'd usedshellcheckthen it has a warning "SC1001: This d will be a regular 'd' in this context.", which is quite helpful. Other answers.
– pbhj
May 16 at 10:45
2
Is [0-9] equivalent to [[:digit:]] though? I was under the impression that POSIX character classes match Unicode characters, so could very well match digits in languages that don't use 0-9.
– Fax
May 16 at 12:38
@Fax Not sure about [0-9] but [A-Z] match unicode characters, the way to change that is only set locale byLANG=C
– LeonidMew
May 16 at 12:46
1
@Fax "Is [0-9] equivalent to [[:digit:]] though?" TIL that the answer is no.
– levant pied
May 16 at 20:25
add a comment |
4
Beat me to it! Also, fwiw if you'd usedshellcheckthen it has a warning "SC1001: This d will be a regular 'd' in this context.", which is quite helpful. Other answers.
– pbhj
May 16 at 10:45
2
Is [0-9] equivalent to [[:digit:]] though? I was under the impression that POSIX character classes match Unicode characters, so could very well match digits in languages that don't use 0-9.
– Fax
May 16 at 12:38
@Fax Not sure about [0-9] but [A-Z] match unicode characters, the way to change that is only set locale byLANG=C
– LeonidMew
May 16 at 12:46
1
@Fax "Is [0-9] equivalent to [[:digit:]] though?" TIL that the answer is no.
– levant pied
May 16 at 20:25
4
4
Beat me to it! Also, fwiw if you'd used
shellcheck then it has a warning "SC1001: This d will be a regular 'd' in this context.", which is quite helpful. Other answers.– pbhj
May 16 at 10:45
Beat me to it! Also, fwiw if you'd used
shellcheck then it has a warning "SC1001: This d will be a regular 'd' in this context.", which is quite helpful. Other answers.– pbhj
May 16 at 10:45
2
2
Is [0-9] equivalent to [[:digit:]] though? I was under the impression that POSIX character classes match Unicode characters, so could very well match digits in languages that don't use 0-9.
– Fax
May 16 at 12:38
Is [0-9] equivalent to [[:digit:]] though? I was under the impression that POSIX character classes match Unicode characters, so could very well match digits in languages that don't use 0-9.
– Fax
May 16 at 12:38
@Fax Not sure about [0-9] but [A-Z] match unicode characters, the way to change that is only set locale by
LANG=C– LeonidMew
May 16 at 12:46
@Fax Not sure about [0-9] but [A-Z] match unicode characters, the way to change that is only set locale by
LANG=C– LeonidMew
May 16 at 12:46
1
1
@Fax "Is [0-9] equivalent to [[:digit:]] though?" TIL that the answer is no.
– levant pied
May 16 at 20:25
@Fax "Is [0-9] equivalent to [[:digit:]] though?" TIL that the answer is no.
– levant pied
May 16 at 20:25
add a comment |
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