How to color a curve
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
$endgroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
plotting
plotting
edited yesterday
J. M. is slightly pensive♦
98.5k10308466
98.5k10308466
asked yesterday
Sara yaqobSara yaqob
234
234
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
yesterday
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
1
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Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
yesterday
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@Sara, You are welcome!
$endgroup$
– mjw
yesterday
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
yesterday
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
yesterday
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
yesterday
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
$endgroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
answered yesterday
XminerXminer
33818
33818
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
yesterday
add a comment |
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
yesterday
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
yesterday
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
yesterday
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
yesterday
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
yesterday
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
yesterday
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
yesterday
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
yesterday
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
yesterday
add a comment |
$begingroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
$endgroup$
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
edited yesterday
answered yesterday
mjwmjw
1,02510
1,02510
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
yesterday
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
yesterday
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
yesterday
add a comment |
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
yesterday
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
yesterday
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
yesterday
1
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
yesterday
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
yesterday
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
yesterday
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
yesterday
2
2
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
yesterday
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
yesterday
add a comment |
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