For which distribution same pdf is generated for given random variable





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{
margin-bottom:0;
}
.everyonelovesstackoverflow{position:absolute;height:1px;width:1px;opacity:0;top:0;left:0;pointer-events:none;}








1












$begingroup$



For which of the distribution same pdf is generated for random variable X and 1/X.
Is it F(2,2)







statistics







share|cite|improve this question











$endgroup$










  • 5




    $begingroup$
    It is unclear from what you are actually asking.
    $endgroup$
    – 1123581321
    May 27 at 8:10






  • 1




    $begingroup$
    @1123581321 Suppose $X$ had density function $f(x)$ and $Y=frac1X$ with density function $g(y)$. The question wants to consider cases where $g(y) = f(y)$
    $endgroup$
    – Henry
    May 27 at 9:03


















1












$begingroup$



For which of the distribution same pdf is generated for random variable X and 1/X.
Is it F(2,2)







statistics







share|cite|improve this question











$endgroup$










  • 5




    $begingroup$
    It is unclear from what you are actually asking.
    $endgroup$
    – 1123581321
    May 27 at 8:10






  • 1




    $begingroup$
    @1123581321 Suppose $X$ had density function $f(x)$ and $Y=frac1X$ with density function $g(y)$. The question wants to consider cases where $g(y) = f(y)$
    $endgroup$
    – Henry
    May 27 at 9:03














1












1








1





$begingroup$



For which of the distribution same pdf is generated for random variable X and 1/X.
Is it F(2,2)







statistics







share|cite|improve this question











$endgroup$





For which of the distribution same pdf is generated for random variable X and 1/X.
Is it F(2,2)







statistics




statistics






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited May 27 at 8:13







ten do

















asked May 27 at 8:08









ten doten do

415 bronze badges




415 bronze badges











  • 5




    $begingroup$
    It is unclear from what you are actually asking.
    $endgroup$
    – 1123581321
    May 27 at 8:10






  • 1




    $begingroup$
    @1123581321 Suppose $X$ had density function $f(x)$ and $Y=frac1X$ with density function $g(y)$. The question wants to consider cases where $g(y) = f(y)$
    $endgroup$
    – Henry
    May 27 at 9:03














  • 5




    $begingroup$
    It is unclear from what you are actually asking.
    $endgroup$
    – 1123581321
    May 27 at 8:10






  • 1




    $begingroup$
    @1123581321 Suppose $X$ had density function $f(x)$ and $Y=frac1X$ with density function $g(y)$. The question wants to consider cases where $g(y) = f(y)$
    $endgroup$
    – Henry
    May 27 at 9:03








5




5




$begingroup$
It is unclear from what you are actually asking.
$endgroup$
– 1123581321
May 27 at 8:10




$begingroup$
It is unclear from what you are actually asking.
$endgroup$
– 1123581321
May 27 at 8:10




1




1




$begingroup$
@1123581321 Suppose $X$ had density function $f(x)$ and $Y=frac1X$ with density function $g(y)$. The question wants to consider cases where $g(y) = f(y)$
$endgroup$
– Henry
May 27 at 9:03




$begingroup$
@1123581321 Suppose $X$ had density function $f(x)$ and $Y=frac1X$ with density function $g(y)$. The question wants to consider cases where $g(y) = f(y)$
$endgroup$
– Henry
May 27 at 9:03










2 Answers
2






active

oldest

votes


















5














$begingroup$

Let $U,V$ be iid random variables with $P(U=0)=0$.



Then if $X$ is defined as $frac{U}{V}$ it will have the same distribution as $frac1{X}=frac{V}{U}$.



If moreover $X$ has a PDF then $frac1{X}$ will also have the same PDF.



Special case: $U$ has chi-squared distribution. Then $X$ has $F$-distribution.






share|cite|improve this answer









$endgroup$















  • $begingroup$
    It would be interesting if all solutions could be decomposed into a ratio like this
    $endgroup$
    – Henry
    May 27 at 9:23










  • $begingroup$
    @Henry Indeed. Uptil now I did not manage to prove that.
    $endgroup$
    – drhab
    May 27 at 9:30










  • $begingroup$
    @Rahul : Ah. Slow about an obvious. <sigh> Thanks.
    $endgroup$
    – Eric Towers
    May 27 at 17:33



















5














$begingroup$

You are looking for a solution to $f(x) = dfrac{f(1/x)}{x^2}$



So take any non-negative function $g(x)$ on $[-1,1]$ where $k= intlimits_{-1}^{1} g(x), dx$ is positive and finite



then a solution will be




  • $f(x) = dfrac{g(x)}{2k} text { when } -1 le x le 1$

  • $f(x) = dfrac{g(1/x)}{2kx^2} text { when } x lt -1 text{ or } x gt 1$


and I think all solutions will essentially be of this form



One solution is $f(x)=dfrac{1}{(1+x)^2}$ for $x gt 0$ and this is indeed an $F(2,2)$ distribution



but there are many others, including the Cauchy density $f(x)=dfrac{1}{pi(1+x^2)}$ on $x in mathbb R$



Another simple illustration, with $g(x)=1$ and so $k=2$, has $f(x)=frac14$ when $x in [-1,1]$ and $f(x)=frac1{4x^2}$ otherwise.






share|cite|improve this answer











$endgroup$

















    Your Answer








    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "69"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/4.0/"u003ecc by-sa 4.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });















    draft saved

    draft discarded
















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3241232%2ffor-which-distribution-same-pdf-is-generated-for-given-random-variable%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    5














    $begingroup$

    Let $U,V$ be iid random variables with $P(U=0)=0$.



    Then if $X$ is defined as $frac{U}{V}$ it will have the same distribution as $frac1{X}=frac{V}{U}$.



    If moreover $X$ has a PDF then $frac1{X}$ will also have the same PDF.



    Special case: $U$ has chi-squared distribution. Then $X$ has $F$-distribution.






    share|cite|improve this answer









    $endgroup$















    • $begingroup$
      It would be interesting if all solutions could be decomposed into a ratio like this
      $endgroup$
      – Henry
      May 27 at 9:23










    • $begingroup$
      @Henry Indeed. Uptil now I did not manage to prove that.
      $endgroup$
      – drhab
      May 27 at 9:30










    • $begingroup$
      @Rahul : Ah. Slow about an obvious. <sigh> Thanks.
      $endgroup$
      – Eric Towers
      May 27 at 17:33
















    5














    $begingroup$

    Let $U,V$ be iid random variables with $P(U=0)=0$.



    Then if $X$ is defined as $frac{U}{V}$ it will have the same distribution as $frac1{X}=frac{V}{U}$.



    If moreover $X$ has a PDF then $frac1{X}$ will also have the same PDF.



    Special case: $U$ has chi-squared distribution. Then $X$ has $F$-distribution.






    share|cite|improve this answer









    $endgroup$















    • $begingroup$
      It would be interesting if all solutions could be decomposed into a ratio like this
      $endgroup$
      – Henry
      May 27 at 9:23










    • $begingroup$
      @Henry Indeed. Uptil now I did not manage to prove that.
      $endgroup$
      – drhab
      May 27 at 9:30










    • $begingroup$
      @Rahul : Ah. Slow about an obvious. <sigh> Thanks.
      $endgroup$
      – Eric Towers
      May 27 at 17:33














    5














    5










    5







    $begingroup$

    Let $U,V$ be iid random variables with $P(U=0)=0$.



    Then if $X$ is defined as $frac{U}{V}$ it will have the same distribution as $frac1{X}=frac{V}{U}$.



    If moreover $X$ has a PDF then $frac1{X}$ will also have the same PDF.



    Special case: $U$ has chi-squared distribution. Then $X$ has $F$-distribution.






    share|cite|improve this answer









    $endgroup$



    Let $U,V$ be iid random variables with $P(U=0)=0$.



    Then if $X$ is defined as $frac{U}{V}$ it will have the same distribution as $frac1{X}=frac{V}{U}$.



    If moreover $X$ has a PDF then $frac1{X}$ will also have the same PDF.



    Special case: $U$ has chi-squared distribution. Then $X$ has $F$-distribution.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered May 27 at 9:00









    drhabdrhab

    114k5 gold badges51 silver badges143 bronze badges




    114k5 gold badges51 silver badges143 bronze badges















    • $begingroup$
      It would be interesting if all solutions could be decomposed into a ratio like this
      $endgroup$
      – Henry
      May 27 at 9:23










    • $begingroup$
      @Henry Indeed. Uptil now I did not manage to prove that.
      $endgroup$
      – drhab
      May 27 at 9:30










    • $begingroup$
      @Rahul : Ah. Slow about an obvious. <sigh> Thanks.
      $endgroup$
      – Eric Towers
      May 27 at 17:33


















    • $begingroup$
      It would be interesting if all solutions could be decomposed into a ratio like this
      $endgroup$
      – Henry
      May 27 at 9:23










    • $begingroup$
      @Henry Indeed. Uptil now I did not manage to prove that.
      $endgroup$
      – drhab
      May 27 at 9:30










    • $begingroup$
      @Rahul : Ah. Slow about an obvious. <sigh> Thanks.
      $endgroup$
      – Eric Towers
      May 27 at 17:33
















    $begingroup$
    It would be interesting if all solutions could be decomposed into a ratio like this
    $endgroup$
    – Henry
    May 27 at 9:23




    $begingroup$
    It would be interesting if all solutions could be decomposed into a ratio like this
    $endgroup$
    – Henry
    May 27 at 9:23












    $begingroup$
    @Henry Indeed. Uptil now I did not manage to prove that.
    $endgroup$
    – drhab
    May 27 at 9:30




    $begingroup$
    @Henry Indeed. Uptil now I did not manage to prove that.
    $endgroup$
    – drhab
    May 27 at 9:30












    $begingroup$
    @Rahul : Ah. Slow about an obvious. <sigh> Thanks.
    $endgroup$
    – Eric Towers
    May 27 at 17:33




    $begingroup$
    @Rahul : Ah. Slow about an obvious. <sigh> Thanks.
    $endgroup$
    – Eric Towers
    May 27 at 17:33













    5














    $begingroup$

    You are looking for a solution to $f(x) = dfrac{f(1/x)}{x^2}$



    So take any non-negative function $g(x)$ on $[-1,1]$ where $k= intlimits_{-1}^{1} g(x), dx$ is positive and finite



    then a solution will be




    • $f(x) = dfrac{g(x)}{2k} text { when } -1 le x le 1$

    • $f(x) = dfrac{g(1/x)}{2kx^2} text { when } x lt -1 text{ or } x gt 1$


    and I think all solutions will essentially be of this form



    One solution is $f(x)=dfrac{1}{(1+x)^2}$ for $x gt 0$ and this is indeed an $F(2,2)$ distribution



    but there are many others, including the Cauchy density $f(x)=dfrac{1}{pi(1+x^2)}$ on $x in mathbb R$



    Another simple illustration, with $g(x)=1$ and so $k=2$, has $f(x)=frac14$ when $x in [-1,1]$ and $f(x)=frac1{4x^2}$ otherwise.






    share|cite|improve this answer











    $endgroup$




















      5














      $begingroup$

      You are looking for a solution to $f(x) = dfrac{f(1/x)}{x^2}$



      So take any non-negative function $g(x)$ on $[-1,1]$ where $k= intlimits_{-1}^{1} g(x), dx$ is positive and finite



      then a solution will be




      • $f(x) = dfrac{g(x)}{2k} text { when } -1 le x le 1$

      • $f(x) = dfrac{g(1/x)}{2kx^2} text { when } x lt -1 text{ or } x gt 1$


      and I think all solutions will essentially be of this form



      One solution is $f(x)=dfrac{1}{(1+x)^2}$ for $x gt 0$ and this is indeed an $F(2,2)$ distribution



      but there are many others, including the Cauchy density $f(x)=dfrac{1}{pi(1+x^2)}$ on $x in mathbb R$



      Another simple illustration, with $g(x)=1$ and so $k=2$, has $f(x)=frac14$ when $x in [-1,1]$ and $f(x)=frac1{4x^2}$ otherwise.






      share|cite|improve this answer











      $endgroup$


















        5














        5










        5







        $begingroup$

        You are looking for a solution to $f(x) = dfrac{f(1/x)}{x^2}$



        So take any non-negative function $g(x)$ on $[-1,1]$ where $k= intlimits_{-1}^{1} g(x), dx$ is positive and finite



        then a solution will be




        • $f(x) = dfrac{g(x)}{2k} text { when } -1 le x le 1$

        • $f(x) = dfrac{g(1/x)}{2kx^2} text { when } x lt -1 text{ or } x gt 1$


        and I think all solutions will essentially be of this form



        One solution is $f(x)=dfrac{1}{(1+x)^2}$ for $x gt 0$ and this is indeed an $F(2,2)$ distribution



        but there are many others, including the Cauchy density $f(x)=dfrac{1}{pi(1+x^2)}$ on $x in mathbb R$



        Another simple illustration, with $g(x)=1$ and so $k=2$, has $f(x)=frac14$ when $x in [-1,1]$ and $f(x)=frac1{4x^2}$ otherwise.






        share|cite|improve this answer











        $endgroup$



        You are looking for a solution to $f(x) = dfrac{f(1/x)}{x^2}$



        So take any non-negative function $g(x)$ on $[-1,1]$ where $k= intlimits_{-1}^{1} g(x), dx$ is positive and finite



        then a solution will be




        • $f(x) = dfrac{g(x)}{2k} text { when } -1 le x le 1$

        • $f(x) = dfrac{g(1/x)}{2kx^2} text { when } x lt -1 text{ or } x gt 1$


        and I think all solutions will essentially be of this form



        One solution is $f(x)=dfrac{1}{(1+x)^2}$ for $x gt 0$ and this is indeed an $F(2,2)$ distribution



        but there are many others, including the Cauchy density $f(x)=dfrac{1}{pi(1+x^2)}$ on $x in mathbb R$



        Another simple illustration, with $g(x)=1$ and so $k=2$, has $f(x)=frac14$ when $x in [-1,1]$ and $f(x)=frac1{4x^2}$ otherwise.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited May 27 at 18:05

























        answered May 27 at 8:59









        HenryHenry

        107k4 gold badges86 silver badges177 bronze badges




        107k4 gold badges86 silver badges177 bronze badges


































            draft saved

            draft discarded



















































            Thanks for contributing an answer to Mathematics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid …



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3241232%2ffor-which-distribution-same-pdf-is-generated-for-given-random-variable%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -

            Popular posts from this blog

            Færeyskur hestur Heimild | Tengill | Tilvísanir | LeiðsagnarvalRossið - síða um færeyska hrossið á færeyskuGott ár hjá færeyska hestinum

            Image
            FæreyjarHestar færeyskahjaltlandshestinumíslenski hesturinnBretlandskolanámumenskuWikipediafæreyskuWikipediaRossið - síða um færeyska hrossið á færeysku Færeyskur hestur Úr Wikipediu, frjálsa alfræðiritinu Jump to navigation Jump to search Rani og Grani. Grani í vetrarfeldi. Færeyski hesturinn (færeyska: Føroyska rossið ) er hestur sem hefur lifað í Færeyjum í hundruði ára. Hann er smágerður, 120-132 cm á hæð, og helst skyldur hjaltlandshestinum. Hlutverk hans var að draga vagna og plóg og bera klyfjar. Hann hefur fjórar gangtegundir eins og íslenski hesturinn (þar með talið tölt) og er með fjölda litaafbrigði. Nú til dags er hann notaður til frístunda. Í lok 19. aldar voru til um 800 hross. Mö...
            Read more

            He _____ here since 1970 . Answer needed [closed]What does “since he was so high” mean?Meaning of “catch birds for”?How do I ensure “since” takes the meaning I want?“Who cares here” meaningWhat does “right round toward” mean?the time tense (had now been detected)What does the phrase “ring around the roses” mean here?Correct usage of “visited upon”Meaning of “foiled rail sabotage bid”It was the third time I had gone to Rome or It is the third time I had been to Rome

            Image
            Engineer refusing to file/disclose patents Extending the spectral theorem for bounded self adjoint operators to bounded normal operators Do varchar(max), nvarchar(max) and varbinary(max) columns affect select queries? Why is it that I can sometimes guess the next note? What linear sensor for a keyboard? Why don’t women say שלא עשני גויה and שפחה, according to Ashkenazim? Did arcade monitors have same pixel aspect ratio as TV sets? anything or something to eat Query about absorption line spectra Can I use my Chinese passport to enter China after I acquired another citizenship? Fuse symbol on toroidal transformer Create all possible words using a set or letters Does the Mind Blank spell prevent the target from being frightened? Can I sign legal documents with a smiley face? When quoting, must I also copy hyphens used to divide words that continue on the next line? ...
            Read more

            Slayer Innehåll Historia | Stil, komposition och lyrik | Bandets betydelse och framgångar | Sidoprojekt och samarbeten | Kontroverser | Medlemmar | Utmärkelser och nomineringar | Turnéer och festivaler | Diskografi | Referenser | Externa länkar | Navigeringsmenywww.slayer.net”Metal Massacre vol. 1””Metal Massacre vol. 3””Metal Massacre Volume III””Show No Mercy””Haunting the Chapel””Live Undead””Hell Awaits””Reign in Blood””Reign in Blood””Gold & Platinum – Reign in Blood””Golden Gods Awards Winners”originalet”Kerrang! Hall Of Fame””Slayer Looks Back On 37-Year Career In New Video Series: Part Two””South of Heaven””Gold & Platinum – South of Heaven””Seasons in the Abyss””Gold & Platinum - Seasons in the Abyss””Divine Intervention””Divine Intervention - Release group by Slayer””Gold & Platinum - Divine Intervention””Live Intrusion””Undisputed Attitude””Abolish Government/Superficial Love””Release “Slatanic Slaughter: A Tribute to Slayer” by Various Artists””Diabolus in Musica””Soundtrack to the Apocalypse””God Hates Us All””Systematic - Relationships””War at the Warfield””Gold & Platinum - War at the Warfield””Soundtrack to the Apocalypse””Gold & Platinum - Still Reigning””Metallica, Slayer, Iron Mauden Among Winners At Metal Hammer Awards””Eternal Pyre””Eternal Pyre - Slayer release group””Eternal Pyre””Metal Storm Awards 2006””Kerrang! Hall Of Fame””Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Bullet-For My Valentine booed at Metal Hammer Golden Gods Awards””Unholy Aliance””The End Of Slayer?””Slayer: We Could Thrash Out Two More Albums If We're Fast Enough...””'The Unholy Alliance: Chapter III' UK Dates Added”originalet”Megadeth And Slayer To Co-Headline 'Canadian Carnage' Trek”originalet”World Painted Blood””Release “World Painted Blood” by Slayer””Metallica Heading To Cinemas””Slayer, Megadeth To Join Forces For 'European Carnage' Tour - Dec. 18, 2010”originalet”Slayer's Hanneman Contracts Acute Infection; Band To Bring In Guest Guitarist””Cannibal Corpse's Pat O'Brien Will Step In As Slayer's Guest Guitarist”originalet”Slayer’s Jeff Hanneman Dead at 49””Dave Lombardo Says He Made Only $67,000 In 2011 While Touring With Slayer””Slayer: We Do Not Agree With Dave Lombardo's Substance Or Timeline Of Events””Slayer Welcomes Drummer Paul Bostaph Back To The Fold””Slayer Hope to Unveil Never-Before-Heard Jeff Hanneman Material on Next Album””Slayer Debut New Song 'Implode' During Surprise Golden Gods Appearance””Release group Repentless by Slayer””Repentless - Slayer - Credits””Slayer””Metal Storm Awards 2015””Slayer - to release comic book "Repentless #1"””Slayer To Release 'Repentless' 6.66" Vinyl Box Set””BREAKING NEWS: Slayer Announce Farewell Tour””Slayer Recruit Lamb of God, Anthrax, Behemoth + Testament for Final Tour””Slayer lägger ner efter 37 år””Slayer Announces Second North American Leg Of 'Final' Tour””Final World Tour””Slayer Announces Final European Tour With Lamb of God, Anthrax And Obituary””Slayer To Tour Europe With Lamb of God, Anthrax And Obituary””Slayer To Play 'Last French Show Ever' At Next Year's Hellfst””Slayer's Final World Tour Will Extend Into 2019””Death Angel's Rob Cavestany On Slayer's 'Farewell' Tour: 'Some Of Us Could See This Coming'””Testament Has No Plans To Retire Anytime Soon, Says Chuck Billy””Anthrax's Scott Ian On Slayer's 'Farewell' Tour Plans: 'I Was Surprised And I Wasn't Surprised'””Slayer””Slayer's Morbid Schlock””Review/Rock; For Slayer, the Mania Is the Message””Slayer - Biography””Slayer - Reign In Blood”originalet”Dave Lombardo””An exclusive oral history of Slayer”originalet”Exclusive! Interview With Slayer Guitarist Jeff Hanneman”originalet”Thinking Out Loud: Slayer's Kerry King on hair metal, Satan and being polite””Slayer Lyrics””Slayer - Biography””Most influential artists for extreme metal music””Slayer - Reign in Blood””Slayer guitarist Jeff Hanneman dies aged 49””Slatanic Slaughter: A Tribute to Slayer””Gateway to Hell: A Tribute to Slayer””Covered In Blood””Slayer: The Origins of Thrash in San Francisco, CA.””Why They Rule - #6 Slayer”originalet”Guitar World's 100 Greatest Heavy Metal Guitarists Of All Time”originalet”The fans have spoken: Slayer comes out on top in readers' polls”originalet”Tribute to Jeff Hanneman (1964-2013)””Lamb Of God Frontman: We Sound Like A Slayer Rip-Off””BEHEMOTH Frontman Pays Tribute To SLAYER's JEFF HANNEMAN””Slayer, Hatebreed Doing Double Duty On This Year's Ozzfest””System of a Down””Lacuna Coil’s Andrea Ferro Talks Influences, Skateboarding, Band Origins + More””Slayer - Reign in Blood””Into The Lungs of Hell””Slayer rules - en utställning om fans””Slayer and Their Fans Slashed Through a No-Holds-Barred Night at Gas Monkey””Home””Slayer””Gold & Platinum - The Big 4 Live from Sofia, Bulgaria””Exclusive! Interview With Slayer Guitarist Kerry King””2008-02-23: Wiltern, Los Angeles, CA, USA””Slayer's Kerry King To Perform With Megadeth Tonight! - Oct. 21, 2010”originalet”Dave Lombardo - Biography”Slayer Case DismissedArkiveradUltimate Classic Rock: Slayer guitarist Jeff Hanneman dead at 49.”Slayer: "We could never do any thing like Some Kind Of Monster..."””Cannibal Corpse'S Pat O'Brien Will Step In As Slayer'S Guest Guitarist | The Official Slayer Site”originalet”Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Kerrang! Awards 2006 Blog: Kerrang! Hall Of Fame””Kerrang! Awards 2013: Kerrang! Legend”originalet”Metallica, Slayer, Iron Maien Among Winners At Metal Hammer Awards””Metal Hammer Golden Gods Awards””Bullet For My Valentine Booed At Metal Hammer Golden Gods Awards””Metal Storm Awards 2006””Metal Storm Awards 2015””Slayer's Concert History””Slayer - Relationships””Slayer - Releases”Slayers officiella webbplatsSlayer på MusicBrainzOfficiell webbplatsSlayerSlayerr1373445760000 0001 1540 47353068615-5086262726cb13906545x(data)6033143kn20030215029

            Image
            SlayerMusikgrupper bildade 1981Amerikanska thrash metal-grupper amerikansktthrash metalHuntington Park1981gitarristernaJeff HannemanKerry KingbasistenTom ArayatrummisenDave LombardoGary HoltPaul Bostaphcertifierats med guldMetallicaAnthraxMegadeththrash metal1986extrema metalgenrerdeath metal22 januari2018USAKanadaEuropaHuntington ParkKalifornien1981gitarristernaJeff HannemanKerry KingbassångDave Lombardoheavy metalbrittiskaIron MaidenJudas PriestthrashMetallicaRattSteeler1982demoundergroundMetal Blade1983high schoolGene HoglanDeathStrapping Young Ladkassettvinyl1984LondonMarquee Club1984Eldorado StudiosTrack Record StudiosLos Angelesmastrade1985CDCombat Recordsextreme metalVenomExodusStudio 54 club1985VHSCombat RecordsBelgienUFORick RubinDef Jam Recordship hoprockakterThe Black CrowesRun–D.M.C.LL Cool JBeastie BoysthrashbpmAngel of DeathRaining BloodAndy WallaceHowie Weinberg1986bildskivaBillboard 200RIAAMetal HammerKerrang!Angela Gossowdeath metalArch Enemythrash metalOverk...
            Read more