Which one is the true statement? [closed]Is the dog dead or alive?The dark side of the moonWho is the horse thief?Make the statement true!Statements that the deities True and False cannot sayA false and a true statement in the blue-eyed puzzleDetermine which statements are True, and which statements are False5x5 statement tableKnights, Knaves and Normals - the tough oneTrue or Faulse?
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Which one is the true statement? [closed]
Is the dog dead or alive?The dark side of the moonWho is the horse thief?Make the statement true!Statements that the deities True and False cannot sayA false and a true statement in the blue-eyed puzzleDetermine which statements are True, and which statements are False5x5 statement tableKnights, Knaves and Normals - the tough oneTrue or Faulse?
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- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
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closed as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel Apr 1 at 5:53
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This looks like a puzzle you found elsewhere. For content you did not create yourself, proper attribution is required. If you have permission to repost this, please edit to include (at minimum) where it came from, then vote to reopen. Posts which use someone else's content without attribution are generally deleted." – Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel
|
show 3 more comments
$begingroup$
- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
$endgroup$
closed as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel Apr 1 at 5:53
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This looks like a puzzle you found elsewhere. For content you did not create yourself, proper attribution is required. If you have permission to repost this, please edit to include (at minimum) where it came from, then vote to reopen. Posts which use someone else's content without attribution are generally deleted." – Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel
1
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Ha! Great puzzle! $(+1),colororangebigstar$
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– Mr Pie
Mar 31 at 5:40
3
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Is this an original puzzle?
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– Dr Xorile
Mar 31 at 15:04
3
$begingroup$
brainly.in/question/8878122
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– Paul Evans
Mar 31 at 22:26
5
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@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
Apr 1 at 0:36
3
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@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
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– Paul Evans
Apr 1 at 12:14
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show 3 more comments
$begingroup$
- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
$endgroup$
- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
logical-deduction
edited Mar 30 at 16:44
Deusovi♦
63.4k6217273
63.4k6217273
asked Mar 30 at 13:50
giorgi rcheulishviligiorgi rcheulishvili
1216
1216
closed as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel Apr 1 at 5:53
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This looks like a puzzle you found elsewhere. For content you did not create yourself, proper attribution is required. If you have permission to repost this, please edit to include (at minimum) where it came from, then vote to reopen. Posts which use someone else's content without attribution are generally deleted." – Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel
closed as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel Apr 1 at 5:53
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This looks like a puzzle you found elsewhere. For content you did not create yourself, proper attribution is required. If you have permission to repost this, please edit to include (at minimum) where it came from, then vote to reopen. Posts which use someone else's content without attribution are generally deleted." – Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel
1
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
$endgroup$
– Mr Pie
Mar 31 at 5:40
3
$begingroup$
Is this an original puzzle?
$endgroup$
– Dr Xorile
Mar 31 at 15:04
3
$begingroup$
brainly.in/question/8878122
$endgroup$
– Paul Evans
Mar 31 at 22:26
5
$begingroup$
@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
$endgroup$
– Dr Xorile
Apr 1 at 0:36
3
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
$endgroup$
– Paul Evans
Apr 1 at 12:14
|
show 3 more comments
1
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
$endgroup$
– Mr Pie
Mar 31 at 5:40
3
$begingroup$
Is this an original puzzle?
$endgroup$
– Dr Xorile
Mar 31 at 15:04
3
$begingroup$
brainly.in/question/8878122
$endgroup$
– Paul Evans
Mar 31 at 22:26
5
$begingroup$
@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
$endgroup$
– Dr Xorile
Apr 1 at 0:36
3
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
$endgroup$
– Paul Evans
Apr 1 at 12:14
1
1
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
$endgroup$
– Mr Pie
Mar 31 at 5:40
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
$endgroup$
– Mr Pie
Mar 31 at 5:40
3
3
$begingroup$
Is this an original puzzle?
$endgroup$
– Dr Xorile
Mar 31 at 15:04
$begingroup$
Is this an original puzzle?
$endgroup$
– Dr Xorile
Mar 31 at 15:04
3
3
$begingroup$
brainly.in/question/8878122
$endgroup$
– Paul Evans
Mar 31 at 22:26
$begingroup$
brainly.in/question/8878122
$endgroup$
– Paul Evans
Mar 31 at 22:26
5
5
$begingroup$
@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
$endgroup$
– Dr Xorile
Apr 1 at 0:36
$begingroup$
@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
$endgroup$
– Dr Xorile
Apr 1 at 0:36
3
3
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
$endgroup$
– Paul Evans
Apr 1 at 12:14
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
$endgroup$
– Paul Evans
Apr 1 at 12:14
|
show 3 more comments
8 Answers
8
active
oldest
votes
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This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
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add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
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1
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(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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– Rubio♦
Mar 30 at 21:07
add a comment |
$begingroup$
Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
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Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
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– aschepler
Mar 31 at 18:40
add a comment |
$begingroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
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add a comment |
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Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
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add a comment |
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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add a comment |
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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1
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Welcome to Puzzling SE!
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– SteveV
Mar 31 at 23:55
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Very formal! A superb answer!
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– Mr Pie
Apr 2 at 1:27
add a comment |
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
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add a comment |
8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
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add a comment |
$begingroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
$endgroup$
add a comment |
$begingroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
$endgroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
edited Mar 30 at 14:45
answered Mar 30 at 14:40
dr01dr01
646926
646926
add a comment |
add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
$endgroup$
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
$endgroup$
– Rubio♦
Mar 30 at 21:07
add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
$endgroup$
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
$endgroup$
– Rubio♦
Mar 30 at 21:07
add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
$endgroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
edited Mar 31 at 1:44
answered Mar 30 at 14:26
TojrahTojrah
3666
3666
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
$endgroup$
– Rubio♦
Mar 30 at 21:07
add a comment |
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
$endgroup$
– Rubio♦
Mar 30 at 21:07
1
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
$endgroup$
– Rubio♦
Mar 30 at 21:07
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
$endgroup$
– Rubio♦
Mar 30 at 21:07
add a comment |
$begingroup$
Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
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$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
Mar 31 at 18:40
add a comment |
$begingroup$
Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
$endgroup$
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
Mar 31 at 18:40
add a comment |
$begingroup$
Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
$endgroup$
Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
answered Mar 30 at 16:54
Rand al'ThorRand al'Thor
71.3k14237475
71.3k14237475
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
Mar 31 at 18:40
add a comment |
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
Mar 31 at 18:40
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
Mar 31 at 18:40
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
Mar 31 at 18:40
add a comment |
$begingroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
$endgroup$
add a comment |
$begingroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
$endgroup$
add a comment |
$begingroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
$endgroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
answered Mar 30 at 14:24
Krad CigolKrad Cigol
1,056210
1,056210
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Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
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Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
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Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
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Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
answered Mar 31 at 15:51
StilezStilez
1,414212
1,414212
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
edited Mar 31 at 19:39
answered Mar 31 at 14:56
KRAKRA
113
113
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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1
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Welcome to Puzzling SE!
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– SteveV
Mar 31 at 23:55
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Very formal! A superb answer!
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– Mr Pie
Apr 2 at 1:27
add a comment |
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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1
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Welcome to Puzzling SE!
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– SteveV
Mar 31 at 23:55
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Very formal! A superb answer!
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– Mr Pie
Apr 2 at 1:27
add a comment |
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
answered Mar 31 at 23:36
Theophile DanoTheophile Dano
1112
1112
1
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Welcome to Puzzling SE!
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– SteveV
Mar 31 at 23:55
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Very formal! A superb answer!
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– Mr Pie
Apr 2 at 1:27
add a comment |
1
$begingroup$
Welcome to Puzzling SE!
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– SteveV
Mar 31 at 23:55
$begingroup$
Very formal! A superb answer!
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– Mr Pie
Apr 2 at 1:27
1
1
$begingroup$
Welcome to Puzzling SE!
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– SteveV
Mar 31 at 23:55
$begingroup$
Welcome to Puzzling SE!
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– SteveV
Mar 31 at 23:55
$begingroup$
Very formal! A superb answer!
$endgroup$
– Mr Pie
Apr 2 at 1:27
$begingroup$
Very formal! A superb answer!
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– Mr Pie
Apr 2 at 1:27
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
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add a comment |
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
answered Apr 1 at 3:19
Brandon_JBrandon_J
3,930447
3,930447
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1
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Ha! Great puzzle! $(+1),colororangebigstar$
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– Mr Pie
Mar 31 at 5:40
3
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Is this an original puzzle?
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– Dr Xorile
Mar 31 at 15:04
3
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brainly.in/question/8878122
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– Paul Evans
Mar 31 at 22:26
5
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@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
Apr 1 at 0:36
3
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@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
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– Paul Evans
Apr 1 at 12:14