How to make the table in the figure in LaTeX?












9















enter image description here



begin{center}
begin{tabular}{ c c c c c}
$0$ & $c_2$ & $c_3$ & ldots & $c_M$ \
$e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
$e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
$e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
vdots & vdots & vdots & $ddots$ &vdots \
$e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \
end{tabular}

end{center}


I have tried this code. But I how I can add those lines in the table?










share|improve this question




















  • 4





    welcome to tex.se! should table be rotated (as is shown in image in qeustion)?

    – Zarko
    May 10 at 13:49













  • why would any one have a table at an angle like this? It makes it hard to read, no?

    – Nasser
    May 13 at 4:08
















9















enter image description here



begin{center}
begin{tabular}{ c c c c c}
$0$ & $c_2$ & $c_3$ & ldots & $c_M$ \
$e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
$e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
$e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
vdots & vdots & vdots & $ddots$ &vdots \
$e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \
end{tabular}

end{center}


I have tried this code. But I how I can add those lines in the table?










share|improve this question




















  • 4





    welcome to tex.se! should table be rotated (as is shown in image in qeustion)?

    – Zarko
    May 10 at 13:49













  • why would any one have a table at an angle like this? It makes it hard to read, no?

    – Nasser
    May 13 at 4:08














9












9








9


3






enter image description here



begin{center}
begin{tabular}{ c c c c c}
$0$ & $c_2$ & $c_3$ & ldots & $c_M$ \
$e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
$e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
$e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
vdots & vdots & vdots & $ddots$ &vdots \
$e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \
end{tabular}

end{center}


I have tried this code. But I how I can add those lines in the table?










share|improve this question
















enter image description here



begin{center}
begin{tabular}{ c c c c c}
$0$ & $c_2$ & $c_3$ & ldots & $c_M$ \
$e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
$e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
$e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
vdots & vdots & vdots & $ddots$ &vdots \
$e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \
end{tabular}

end{center}


I have tried this code. But I how I can add those lines in the table?







tables






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited May 10 at 17:43









Money Oriented Programmer

5,88911346




5,88911346










asked May 10 at 13:38









JSNJSN

1104




1104








  • 4





    welcome to tex.se! should table be rotated (as is shown in image in qeustion)?

    – Zarko
    May 10 at 13:49













  • why would any one have a table at an angle like this? It makes it hard to read, no?

    – Nasser
    May 13 at 4:08














  • 4





    welcome to tex.se! should table be rotated (as is shown in image in qeustion)?

    – Zarko
    May 10 at 13:49













  • why would any one have a table at an angle like this? It makes it hard to read, no?

    – Nasser
    May 13 at 4:08








4




4





welcome to tex.se! should table be rotated (as is shown in image in qeustion)?

– Zarko
May 10 at 13:49







welcome to tex.se! should table be rotated (as is shown in image in qeustion)?

– Zarko
May 10 at 13:49















why would any one have a table at an angle like this? It makes it hard to read, no?

– Nasser
May 13 at 4:08





why would any one have a table at an angle like this? It makes it hard to read, no?

– Nasser
May 13 at 4:08










4 Answers
4






active

oldest

votes


















18














documentclass{article}
begin{document}
begin{center}
begin{tabular}{|c|c c c c|}
hline
$0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
$e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
$e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
$e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
vdots & vdots & vdots & $ddots$ &vdots \
$e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
end{tabular}
end{center}
end{document}


enter image description here





This is the rotated solution: just use the amazing yslant in a TikZ node :) M. Al Jumaily's solution is excellent, but there is absolutely no need of such a complicated code.



documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
node[yslant=-.1] {%
begin{tabular}{|c|c c c c|}
hline
$0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
$e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
$e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
$e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
vdots & vdots & vdots & $ddots$ &vdots \
$e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
end{tabular}};
end{tikzpicture}
end{document}


enter image description here



Perfect parallelogram: even the baselines are now slanted :)



I am sure this is a perfect parallelogram. This is a proof, which is funny for extraordinary users :)



documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
node[yslant=-1] {%
begin{tabular}{|c|c c c c|}
hline
$0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
$e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
$e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
$e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
vdots & vdots & vdots & $ddots$ &vdots \
$e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
end{tabular}};
end{tikzpicture}
end{document}


enter image description here



The plus signs almost become some slanted X's.






share|improve this answer





















  • 2





    Maybe you could use the array environment to get rid of all of the $s.

    – leandriis
    May 10 at 14:12











  • @leandriis I just add some letters to the code given by the OP. Using array or tabular is his choice; maybe he has some intentions?

    – The old JouleV
    May 10 at 14:14






  • 1





    @L.F. :(( I edited my answer. Hope I am not downvoted anymore :))

    – The old JouleV
    May 12 at 17:25








  • 1





    Wow! I didn't know about the yslant option. Well done :)

    – M. Al Jumaily
    May 12 at 19:05






  • 1





    @M.AlJumaily Thanks! Actually I also just accidentally learned it when I examined the "TikZ" and "PGF" nodes in the cover page of the manual :)) The "parallelogram-ness" of the table reminded me of those nodes.

    – The old JouleV
    May 13 at 1:56



















12














from image in your question can be concluded, that you like to have rotated table ... :-)



enter image description here



documentclass{article}
usepackage{graphicx}

usepackage{lipsum}
begin{document}
lipsum[1]
begin{center}
rotatebox[origin=c]{-15}{
$
begin{array}{|c|c c c c|}
hline
0 & c_2 & c_3 & ldots & c_M \
hline
e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
vdots & vdots & vdots & ddots & vdots \
e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
hline
end{array}
$}
end{center}
lipsum[2]
end{document}


... just for joy ...






share|improve this answer



















  • 7





    The op's table is a parallelogram. :-)

    – Money Oriented Programmer
    May 10 at 17:45






  • 2





    @ArtificialOdorlessArmpit, you might be right. i draw only simple aproximation for it. write as parallelogram is clallenge, which can be solved with some drawing program ...

    – Zarko
    May 10 at 18:11





















7














Here's a solution which employs an array environment instead of a tabular environment. Note the absence of 42 [!] $ symbols.



enter image description here



documentclass{article}
begin{document}
[
begin{array}{ |c|c c c c|}
hline
0 & c_2 & c_3 & ldots & c_M \
hline
e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
vdots & vdots & vdots & ddots & vdots \
e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
hline
end{array}
]
end{document}





share|improve this answer































    6














    Here is a Tikz solution:



    Output



    documentclass[margin=1cm, tikz]{standalone}
    usepackage{tikz}
    begin{document}
    begin{tikzpicture}
    %NOTE! Everyting is zero-based
    defourInfo{{
    {0,"$c_2$","$c_3$", "$cdots$", "$c_M$"}, % Row 0
    {"$e_2$", "$c_2+e_2$", "$c_3+e_2$", "$cdots$", "$c_M+e_2$"}, % Row 1
    {"$e_3$", "$c_2+e_3$", "$c_3+e_3$", "$cdots$", "$c_M+e_3$"}, % Row 2
    {"$e_4$", "$c_2+e_4$", "$c_3+e_4$", "$cdots$", "$c_M+e_4$"}, % Row 3
    {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 4
    {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 5
    {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 6
    {"$e_N$", "$c_2+e_N$", "$c_3+e_N$", "$cdots$", "$c_M+e_N$"}, % Row 7
    }}
    pgfmathsetmacro{length}{7}% Zero based.
    % Loop through the 2D array, get a row, iterate through its cells,
    % print them and go to the next row.
    foreach i in {0, ..., length}{% Rows
    foreach j in {0, ..., 4}{% Columns
    pgfmathsetmacro{data}{ourInfo[i][j]};% Read the cell
    node[rotate = -2, below] at (j +j/2 , -i/2 -j*0.1) {data};
    }
    }
    % Drawing the lines
    draw[thick, rotate = -4] (-0.2,0)--(6.75,0){};% Top horizontal
    draw[thick, rotate = -4] (-0.2,-0.45)--(6.78,-0.45){};% Center horizontal
    draw[thick, rotate = -4] (-0.06,-4)--(7.01,-4){};% Bottom horizontal
    draw[thick, rotate = -4] (-0.215,0.01)--(-0.05,-4){};% Left vertical
    draw[thick, rotate = -4] (0.6,0.01)--(0.75,-4){};% Center vertical
    draw[thick, rotate = -4] (6.75,0.01)--(7,-4){};% Right vertical
    end{tikzpicture}
    end{document}





    share|improve this answer
























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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      18














      documentclass{article}
      begin{document}
      begin{center}
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}
      end{center}
      end{document}


      enter image description here





      This is the rotated solution: just use the amazing yslant in a TikZ node :) M. Al Jumaily's solution is excellent, but there is absolutely no need of such a complicated code.



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-.1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      Perfect parallelogram: even the baselines are now slanted :)



      I am sure this is a perfect parallelogram. This is a proof, which is funny for extraordinary users :)



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      The plus signs almost become some slanted X's.






      share|improve this answer





















      • 2





        Maybe you could use the array environment to get rid of all of the $s.

        – leandriis
        May 10 at 14:12











      • @leandriis I just add some letters to the code given by the OP. Using array or tabular is his choice; maybe he has some intentions?

        – The old JouleV
        May 10 at 14:14






      • 1





        @L.F. :(( I edited my answer. Hope I am not downvoted anymore :))

        – The old JouleV
        May 12 at 17:25








      • 1





        Wow! I didn't know about the yslant option. Well done :)

        – M. Al Jumaily
        May 12 at 19:05






      • 1





        @M.AlJumaily Thanks! Actually I also just accidentally learned it when I examined the "TikZ" and "PGF" nodes in the cover page of the manual :)) The "parallelogram-ness" of the table reminded me of those nodes.

        – The old JouleV
        May 13 at 1:56
















      18














      documentclass{article}
      begin{document}
      begin{center}
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}
      end{center}
      end{document}


      enter image description here





      This is the rotated solution: just use the amazing yslant in a TikZ node :) M. Al Jumaily's solution is excellent, but there is absolutely no need of such a complicated code.



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-.1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      Perfect parallelogram: even the baselines are now slanted :)



      I am sure this is a perfect parallelogram. This is a proof, which is funny for extraordinary users :)



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      The plus signs almost become some slanted X's.






      share|improve this answer





















      • 2





        Maybe you could use the array environment to get rid of all of the $s.

        – leandriis
        May 10 at 14:12











      • @leandriis I just add some letters to the code given by the OP. Using array or tabular is his choice; maybe he has some intentions?

        – The old JouleV
        May 10 at 14:14






      • 1





        @L.F. :(( I edited my answer. Hope I am not downvoted anymore :))

        – The old JouleV
        May 12 at 17:25








      • 1





        Wow! I didn't know about the yslant option. Well done :)

        – M. Al Jumaily
        May 12 at 19:05






      • 1





        @M.AlJumaily Thanks! Actually I also just accidentally learned it when I examined the "TikZ" and "PGF" nodes in the cover page of the manual :)) The "parallelogram-ness" of the table reminded me of those nodes.

        – The old JouleV
        May 13 at 1:56














      18












      18








      18







      documentclass{article}
      begin{document}
      begin{center}
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}
      end{center}
      end{document}


      enter image description here





      This is the rotated solution: just use the amazing yslant in a TikZ node :) M. Al Jumaily's solution is excellent, but there is absolutely no need of such a complicated code.



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-.1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      Perfect parallelogram: even the baselines are now slanted :)



      I am sure this is a perfect parallelogram. This is a proof, which is funny for extraordinary users :)



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      The plus signs almost become some slanted X's.






      share|improve this answer















      documentclass{article}
      begin{document}
      begin{center}
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}
      end{center}
      end{document}


      enter image description here





      This is the rotated solution: just use the amazing yslant in a TikZ node :) M. Al Jumaily's solution is excellent, but there is absolutely no need of such a complicated code.



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-.1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      Perfect parallelogram: even the baselines are now slanted :)



      I am sure this is a perfect parallelogram. This is a proof, which is funny for extraordinary users :)



      documentclass[tikz]{standalone}
      begin{document}
      begin{tikzpicture}
      node[yslant=-1] {%
      begin{tabular}{|c|c c c c|}
      hline
      $0$ & $c_2$ & $c_3$ & ldots & $c_M$ \ hline
      $e_2$ & $c_2+e_2$ & $c_3+e_2$ & ldots& $c_M+e_2$ \
      $e_3$ & $c_2+e_3$ & $c_3+e_3$ & ldots& $c_M+e_3$ \
      $e_4$ & $c_2+e_4$ & $c_3+e_4$ & ldots& $c_M+e_4$ \
      vdots & vdots & vdots & $ddots$ &vdots \
      $e_N$ & $c_2+e_N$ & $c_3+e_N$ & ldots& $c_M+e_N$ \ hline
      end{tabular}};
      end{tikzpicture}
      end{document}


      enter image description here



      The plus signs almost become some slanted X's.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited May 13 at 4:03

























      answered May 10 at 13:40









      The old JouleVThe old JouleV

      19.5k43175




      19.5k43175








      • 2





        Maybe you could use the array environment to get rid of all of the $s.

        – leandriis
        May 10 at 14:12











      • @leandriis I just add some letters to the code given by the OP. Using array or tabular is his choice; maybe he has some intentions?

        – The old JouleV
        May 10 at 14:14






      • 1





        @L.F. :(( I edited my answer. Hope I am not downvoted anymore :))

        – The old JouleV
        May 12 at 17:25








      • 1





        Wow! I didn't know about the yslant option. Well done :)

        – M. Al Jumaily
        May 12 at 19:05






      • 1





        @M.AlJumaily Thanks! Actually I also just accidentally learned it when I examined the "TikZ" and "PGF" nodes in the cover page of the manual :)) The "parallelogram-ness" of the table reminded me of those nodes.

        – The old JouleV
        May 13 at 1:56














      • 2





        Maybe you could use the array environment to get rid of all of the $s.

        – leandriis
        May 10 at 14:12











      • @leandriis I just add some letters to the code given by the OP. Using array or tabular is his choice; maybe he has some intentions?

        – The old JouleV
        May 10 at 14:14






      • 1





        @L.F. :(( I edited my answer. Hope I am not downvoted anymore :))

        – The old JouleV
        May 12 at 17:25








      • 1





        Wow! I didn't know about the yslant option. Well done :)

        – M. Al Jumaily
        May 12 at 19:05






      • 1





        @M.AlJumaily Thanks! Actually I also just accidentally learned it when I examined the "TikZ" and "PGF" nodes in the cover page of the manual :)) The "parallelogram-ness" of the table reminded me of those nodes.

        – The old JouleV
        May 13 at 1:56








      2




      2





      Maybe you could use the array environment to get rid of all of the $s.

      – leandriis
      May 10 at 14:12





      Maybe you could use the array environment to get rid of all of the $s.

      – leandriis
      May 10 at 14:12













      @leandriis I just add some letters to the code given by the OP. Using array or tabular is his choice; maybe he has some intentions?

      – The old JouleV
      May 10 at 14:14





      @leandriis I just add some letters to the code given by the OP. Using array or tabular is his choice; maybe he has some intentions?

      – The old JouleV
      May 10 at 14:14




      1




      1





      @L.F. :(( I edited my answer. Hope I am not downvoted anymore :))

      – The old JouleV
      May 12 at 17:25







      @L.F. :(( I edited my answer. Hope I am not downvoted anymore :))

      – The old JouleV
      May 12 at 17:25






      1




      1





      Wow! I didn't know about the yslant option. Well done :)

      – M. Al Jumaily
      May 12 at 19:05





      Wow! I didn't know about the yslant option. Well done :)

      – M. Al Jumaily
      May 12 at 19:05




      1




      1





      @M.AlJumaily Thanks! Actually I also just accidentally learned it when I examined the "TikZ" and "PGF" nodes in the cover page of the manual :)) The "parallelogram-ness" of the table reminded me of those nodes.

      – The old JouleV
      May 13 at 1:56





      @M.AlJumaily Thanks! Actually I also just accidentally learned it when I examined the "TikZ" and "PGF" nodes in the cover page of the manual :)) The "parallelogram-ness" of the table reminded me of those nodes.

      – The old JouleV
      May 13 at 1:56











      12














      from image in your question can be concluded, that you like to have rotated table ... :-)



      enter image description here



      documentclass{article}
      usepackage{graphicx}

      usepackage{lipsum}
      begin{document}
      lipsum[1]
      begin{center}
      rotatebox[origin=c]{-15}{
      $
      begin{array}{|c|c c c c|}
      hline
      0 & c_2 & c_3 & ldots & c_M \
      hline
      e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
      e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
      e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
      vdots & vdots & vdots & ddots & vdots \
      e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
      hline
      end{array}
      $}
      end{center}
      lipsum[2]
      end{document}


      ... just for joy ...






      share|improve this answer



















      • 7





        The op's table is a parallelogram. :-)

        – Money Oriented Programmer
        May 10 at 17:45






      • 2





        @ArtificialOdorlessArmpit, you might be right. i draw only simple aproximation for it. write as parallelogram is clallenge, which can be solved with some drawing program ...

        – Zarko
        May 10 at 18:11


















      12














      from image in your question can be concluded, that you like to have rotated table ... :-)



      enter image description here



      documentclass{article}
      usepackage{graphicx}

      usepackage{lipsum}
      begin{document}
      lipsum[1]
      begin{center}
      rotatebox[origin=c]{-15}{
      $
      begin{array}{|c|c c c c|}
      hline
      0 & c_2 & c_3 & ldots & c_M \
      hline
      e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
      e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
      e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
      vdots & vdots & vdots & ddots & vdots \
      e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
      hline
      end{array}
      $}
      end{center}
      lipsum[2]
      end{document}


      ... just for joy ...






      share|improve this answer



















      • 7





        The op's table is a parallelogram. :-)

        – Money Oriented Programmer
        May 10 at 17:45






      • 2





        @ArtificialOdorlessArmpit, you might be right. i draw only simple aproximation for it. write as parallelogram is clallenge, which can be solved with some drawing program ...

        – Zarko
        May 10 at 18:11
















      12












      12








      12







      from image in your question can be concluded, that you like to have rotated table ... :-)



      enter image description here



      documentclass{article}
      usepackage{graphicx}

      usepackage{lipsum}
      begin{document}
      lipsum[1]
      begin{center}
      rotatebox[origin=c]{-15}{
      $
      begin{array}{|c|c c c c|}
      hline
      0 & c_2 & c_3 & ldots & c_M \
      hline
      e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
      e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
      e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
      vdots & vdots & vdots & ddots & vdots \
      e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
      hline
      end{array}
      $}
      end{center}
      lipsum[2]
      end{document}


      ... just for joy ...






      share|improve this answer













      from image in your question can be concluded, that you like to have rotated table ... :-)



      enter image description here



      documentclass{article}
      usepackage{graphicx}

      usepackage{lipsum}
      begin{document}
      lipsum[1]
      begin{center}
      rotatebox[origin=c]{-15}{
      $
      begin{array}{|c|c c c c|}
      hline
      0 & c_2 & c_3 & ldots & c_M \
      hline
      e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
      e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
      e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
      vdots & vdots & vdots & ddots & vdots \
      e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
      hline
      end{array}
      $}
      end{center}
      lipsum[2]
      end{document}


      ... just for joy ...







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered May 10 at 17:40









      ZarkoZarko

      136k872180




      136k872180








      • 7





        The op's table is a parallelogram. :-)

        – Money Oriented Programmer
        May 10 at 17:45






      • 2





        @ArtificialOdorlessArmpit, you might be right. i draw only simple aproximation for it. write as parallelogram is clallenge, which can be solved with some drawing program ...

        – Zarko
        May 10 at 18:11
















      • 7





        The op's table is a parallelogram. :-)

        – Money Oriented Programmer
        May 10 at 17:45






      • 2





        @ArtificialOdorlessArmpit, you might be right. i draw only simple aproximation for it. write as parallelogram is clallenge, which can be solved with some drawing program ...

        – Zarko
        May 10 at 18:11










      7




      7





      The op's table is a parallelogram. :-)

      – Money Oriented Programmer
      May 10 at 17:45





      The op's table is a parallelogram. :-)

      – Money Oriented Programmer
      May 10 at 17:45




      2




      2





      @ArtificialOdorlessArmpit, you might be right. i draw only simple aproximation for it. write as parallelogram is clallenge, which can be solved with some drawing program ...

      – Zarko
      May 10 at 18:11







      @ArtificialOdorlessArmpit, you might be right. i draw only simple aproximation for it. write as parallelogram is clallenge, which can be solved with some drawing program ...

      – Zarko
      May 10 at 18:11













      7














      Here's a solution which employs an array environment instead of a tabular environment. Note the absence of 42 [!] $ symbols.



      enter image description here



      documentclass{article}
      begin{document}
      [
      begin{array}{ |c|c c c c|}
      hline
      0 & c_2 & c_3 & ldots & c_M \
      hline
      e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
      e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
      e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
      vdots & vdots & vdots & ddots & vdots \
      e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
      hline
      end{array}
      ]
      end{document}





      share|improve this answer




























        7














        Here's a solution which employs an array environment instead of a tabular environment. Note the absence of 42 [!] $ symbols.



        enter image description here



        documentclass{article}
        begin{document}
        [
        begin{array}{ |c|c c c c|}
        hline
        0 & c_2 & c_3 & ldots & c_M \
        hline
        e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
        e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
        e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
        vdots & vdots & vdots & ddots & vdots \
        e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
        hline
        end{array}
        ]
        end{document}





        share|improve this answer


























          7












          7








          7







          Here's a solution which employs an array environment instead of a tabular environment. Note the absence of 42 [!] $ symbols.



          enter image description here



          documentclass{article}
          begin{document}
          [
          begin{array}{ |c|c c c c|}
          hline
          0 & c_2 & c_3 & ldots & c_M \
          hline
          e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
          e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
          e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
          vdots & vdots & vdots & ddots & vdots \
          e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
          hline
          end{array}
          ]
          end{document}





          share|improve this answer













          Here's a solution which employs an array environment instead of a tabular environment. Note the absence of 42 [!] $ symbols.



          enter image description here



          documentclass{article}
          begin{document}
          [
          begin{array}{ |c|c c c c|}
          hline
          0 & c_2 & c_3 & ldots & c_M \
          hline
          e_2 & c_2+e_2 & c_3+e_2 & ldots & c_M+e_2 \
          e_3 & c_2+e_3 & c_3+e_3 & ldots & c_M+e_3 \
          e_4 & c_2+e_4 & c_3+e_4 & ldots & c_M+e_4 \
          vdots & vdots & vdots & ddots & vdots \
          e_N & c_2+e_N & c_3+e_N & ldots & c_M+e_N \
          hline
          end{array}
          ]
          end{document}






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered May 10 at 18:21









          MicoMico

          292k32402791




          292k32402791























              6














              Here is a Tikz solution:



              Output



              documentclass[margin=1cm, tikz]{standalone}
              usepackage{tikz}
              begin{document}
              begin{tikzpicture}
              %NOTE! Everyting is zero-based
              defourInfo{{
              {0,"$c_2$","$c_3$", "$cdots$", "$c_M$"}, % Row 0
              {"$e_2$", "$c_2+e_2$", "$c_3+e_2$", "$cdots$", "$c_M+e_2$"}, % Row 1
              {"$e_3$", "$c_2+e_3$", "$c_3+e_3$", "$cdots$", "$c_M+e_3$"}, % Row 2
              {"$e_4$", "$c_2+e_4$", "$c_3+e_4$", "$cdots$", "$c_M+e_4$"}, % Row 3
              {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 4
              {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 5
              {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 6
              {"$e_N$", "$c_2+e_N$", "$c_3+e_N$", "$cdots$", "$c_M+e_N$"}, % Row 7
              }}
              pgfmathsetmacro{length}{7}% Zero based.
              % Loop through the 2D array, get a row, iterate through its cells,
              % print them and go to the next row.
              foreach i in {0, ..., length}{% Rows
              foreach j in {0, ..., 4}{% Columns
              pgfmathsetmacro{data}{ourInfo[i][j]};% Read the cell
              node[rotate = -2, below] at (j +j/2 , -i/2 -j*0.1) {data};
              }
              }
              % Drawing the lines
              draw[thick, rotate = -4] (-0.2,0)--(6.75,0){};% Top horizontal
              draw[thick, rotate = -4] (-0.2,-0.45)--(6.78,-0.45){};% Center horizontal
              draw[thick, rotate = -4] (-0.06,-4)--(7.01,-4){};% Bottom horizontal
              draw[thick, rotate = -4] (-0.215,0.01)--(-0.05,-4){};% Left vertical
              draw[thick, rotate = -4] (0.6,0.01)--(0.75,-4){};% Center vertical
              draw[thick, rotate = -4] (6.75,0.01)--(7,-4){};% Right vertical
              end{tikzpicture}
              end{document}





              share|improve this answer




























                6














                Here is a Tikz solution:



                Output



                documentclass[margin=1cm, tikz]{standalone}
                usepackage{tikz}
                begin{document}
                begin{tikzpicture}
                %NOTE! Everyting is zero-based
                defourInfo{{
                {0,"$c_2$","$c_3$", "$cdots$", "$c_M$"}, % Row 0
                {"$e_2$", "$c_2+e_2$", "$c_3+e_2$", "$cdots$", "$c_M+e_2$"}, % Row 1
                {"$e_3$", "$c_2+e_3$", "$c_3+e_3$", "$cdots$", "$c_M+e_3$"}, % Row 2
                {"$e_4$", "$c_2+e_4$", "$c_3+e_4$", "$cdots$", "$c_M+e_4$"}, % Row 3
                {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 4
                {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 5
                {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 6
                {"$e_N$", "$c_2+e_N$", "$c_3+e_N$", "$cdots$", "$c_M+e_N$"}, % Row 7
                }}
                pgfmathsetmacro{length}{7}% Zero based.
                % Loop through the 2D array, get a row, iterate through its cells,
                % print them and go to the next row.
                foreach i in {0, ..., length}{% Rows
                foreach j in {0, ..., 4}{% Columns
                pgfmathsetmacro{data}{ourInfo[i][j]};% Read the cell
                node[rotate = -2, below] at (j +j/2 , -i/2 -j*0.1) {data};
                }
                }
                % Drawing the lines
                draw[thick, rotate = -4] (-0.2,0)--(6.75,0){};% Top horizontal
                draw[thick, rotate = -4] (-0.2,-0.45)--(6.78,-0.45){};% Center horizontal
                draw[thick, rotate = -4] (-0.06,-4)--(7.01,-4){};% Bottom horizontal
                draw[thick, rotate = -4] (-0.215,0.01)--(-0.05,-4){};% Left vertical
                draw[thick, rotate = -4] (0.6,0.01)--(0.75,-4){};% Center vertical
                draw[thick, rotate = -4] (6.75,0.01)--(7,-4){};% Right vertical
                end{tikzpicture}
                end{document}





                share|improve this answer


























                  6












                  6








                  6







                  Here is a Tikz solution:



                  Output



                  documentclass[margin=1cm, tikz]{standalone}
                  usepackage{tikz}
                  begin{document}
                  begin{tikzpicture}
                  %NOTE! Everyting is zero-based
                  defourInfo{{
                  {0,"$c_2$","$c_3$", "$cdots$", "$c_M$"}, % Row 0
                  {"$e_2$", "$c_2+e_2$", "$c_3+e_2$", "$cdots$", "$c_M+e_2$"}, % Row 1
                  {"$e_3$", "$c_2+e_3$", "$c_3+e_3$", "$cdots$", "$c_M+e_3$"}, % Row 2
                  {"$e_4$", "$c_2+e_4$", "$c_3+e_4$", "$cdots$", "$c_M+e_4$"}, % Row 3
                  {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 4
                  {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 5
                  {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 6
                  {"$e_N$", "$c_2+e_N$", "$c_3+e_N$", "$cdots$", "$c_M+e_N$"}, % Row 7
                  }}
                  pgfmathsetmacro{length}{7}% Zero based.
                  % Loop through the 2D array, get a row, iterate through its cells,
                  % print them and go to the next row.
                  foreach i in {0, ..., length}{% Rows
                  foreach j in {0, ..., 4}{% Columns
                  pgfmathsetmacro{data}{ourInfo[i][j]};% Read the cell
                  node[rotate = -2, below] at (j +j/2 , -i/2 -j*0.1) {data};
                  }
                  }
                  % Drawing the lines
                  draw[thick, rotate = -4] (-0.2,0)--(6.75,0){};% Top horizontal
                  draw[thick, rotate = -4] (-0.2,-0.45)--(6.78,-0.45){};% Center horizontal
                  draw[thick, rotate = -4] (-0.06,-4)--(7.01,-4){};% Bottom horizontal
                  draw[thick, rotate = -4] (-0.215,0.01)--(-0.05,-4){};% Left vertical
                  draw[thick, rotate = -4] (0.6,0.01)--(0.75,-4){};% Center vertical
                  draw[thick, rotate = -4] (6.75,0.01)--(7,-4){};% Right vertical
                  end{tikzpicture}
                  end{document}





                  share|improve this answer













                  Here is a Tikz solution:



                  Output



                  documentclass[margin=1cm, tikz]{standalone}
                  usepackage{tikz}
                  begin{document}
                  begin{tikzpicture}
                  %NOTE! Everyting is zero-based
                  defourInfo{{
                  {0,"$c_2$","$c_3$", "$cdots$", "$c_M$"}, % Row 0
                  {"$e_2$", "$c_2+e_2$", "$c_3+e_2$", "$cdots$", "$c_M+e_2$"}, % Row 1
                  {"$e_3$", "$c_2+e_3$", "$c_3+e_3$", "$cdots$", "$c_M+e_3$"}, % Row 2
                  {"$e_4$", "$c_2+e_4$", "$c_3+e_4$", "$cdots$", "$c_M+e_4$"}, % Row 3
                  {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 4
                  {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 5
                  {"$cdot$", "$cdot$", "$cdot$", "$cdots$", "$cdot$"}, % Row 6
                  {"$e_N$", "$c_2+e_N$", "$c_3+e_N$", "$cdots$", "$c_M+e_N$"}, % Row 7
                  }}
                  pgfmathsetmacro{length}{7}% Zero based.
                  % Loop through the 2D array, get a row, iterate through its cells,
                  % print them and go to the next row.
                  foreach i in {0, ..., length}{% Rows
                  foreach j in {0, ..., 4}{% Columns
                  pgfmathsetmacro{data}{ourInfo[i][j]};% Read the cell
                  node[rotate = -2, below] at (j +j/2 , -i/2 -j*0.1) {data};
                  }
                  }
                  % Drawing the lines
                  draw[thick, rotate = -4] (-0.2,0)--(6.75,0){};% Top horizontal
                  draw[thick, rotate = -4] (-0.2,-0.45)--(6.78,-0.45){};% Center horizontal
                  draw[thick, rotate = -4] (-0.06,-4)--(7.01,-4){};% Bottom horizontal
                  draw[thick, rotate = -4] (-0.215,0.01)--(-0.05,-4){};% Left vertical
                  draw[thick, rotate = -4] (0.6,0.01)--(0.75,-4){};% Center vertical
                  draw[thick, rotate = -4] (6.75,0.01)--(7,-4){};% Right vertical
                  end{tikzpicture}
                  end{document}






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered May 12 at 6:07









                  M. Al JumailyM. Al Jumaily

                  1,3471212




                  1,3471212






























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