Why isn't the circumferential light around the M87 black hole's event horizon symmetric?
$begingroup$
After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?
general-relativity black-holes astronomy event-horizon accretion-disk
$endgroup$
add a comment |
$begingroup$
After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?
general-relativity black-holes astronomy event-horizon accretion-disk
$endgroup$
13
$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago
1
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago
add a comment |
$begingroup$
After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?
general-relativity black-holes astronomy event-horizon accretion-disk
$endgroup$
After the revelation of the first black hole images, it seems there is a bias towards its south side. Is it because of measuring it from earth or is it something more fundamental in the understanding of the gravitational field?
general-relativity black-holes astronomy event-horizon accretion-disk
general-relativity black-holes astronomy event-horizon accretion-disk
edited 6 hours ago
Qmechanic♦
107k122001241
107k122001241
asked 14 hours ago
0x900x90
1,09041533
1,09041533
13
$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago
1
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago
add a comment |
13
$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago
1
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago
13
13
$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago
$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago
1
1
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.
You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:
There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.
$endgroup$
$begingroup$
This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.
The pictures below from the fifth event horizon telescope paper makes things clear.
The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.
The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.
$endgroup$
add a comment |
$begingroup$
I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.
Image from BBC News and EHT Collaboration
The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.
New contributor
$endgroup$
1
$begingroup$
I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Douglas Held
9 hours ago
$begingroup$
@DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
$endgroup$
– StudyStudy
9 hours ago
$begingroup$
This doesn't address the reason for the asymmetry in the ring at all
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
I found this animated GIF to explain this really well:
https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif
Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.
New contributor
$endgroup$
$begingroup$
Like Doppler effect?
$endgroup$
– 0x90
7 hours ago
$begingroup$
No - not like doppler effect.
$endgroup$
– Rory Alsop
6 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Draco18s
2 hours ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.
You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:
There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.
$endgroup$
$begingroup$
This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.
You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:
There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.
$endgroup$
$begingroup$
This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.
You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:
There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.
$endgroup$
This is because of the tilt of the accretion disk with respect of our line of sight. The accretion disk is "in front" of the black hole in the southern part of the image.
You can compare with this image from the 5th paper of the ApJ Letters "First M87 Event Horizon Telescope Results. V. Physical Origin of the Asymmetric Ring", which shows one of the best-fit theoretical simulations alongside the observed image:
There is a number of other effects at play, though. You see only a narrow frequency band, so once the light is shifted by the Doppler effect to a different wavelength in either direction, or when the plasma has the wrong temperature, you stop seeing it in the image. An additional general-relativistic effect is a "space-time push" the rotation of the black hole gives to co-rotating photons, which causes a slight west-east asymmetry in the image as well.
edited 13 hours ago
answered 14 hours ago
VoidVoid
11k11758
11k11758
$begingroup$
This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
$endgroup$
– Rob Jeffries
7 hours ago
$begingroup$
This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
$endgroup$
– Rob Jeffries
7 hours ago
$begingroup$
This isn't correct. The asymmetry in the disk you refer to would be in the East-West direction. The emission seen is due to continuum synchrotron radiation so there is little sense in which the radiation moves out of the sensitive frequency range
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.
The pictures below from the fifth event horizon telescope paper makes things clear.
The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.
The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.
$endgroup$
add a comment |
$begingroup$
The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.
The pictures below from the fifth event horizon telescope paper makes things clear.
The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.
The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.
$endgroup$
add a comment |
$begingroup$
The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.
The pictures below from the fifth event horizon telescope paper makes things clear.
The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.
The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.
$endgroup$
The reason is almost entirely due to Doppler beaming and boosting of radiation arising in matter travelling at relativistic speeds. This in turn is almost entirely controlled by the orientation of the black hole spin. The black hole sweeps up material and magnetic fields almost irrespective of the orientation of any accretion disk.
The pictures below from the fifth event horizon telescope paper makes things clear.
The black arrow indicates the direction of black hole spin. The blue arrow indicates the initial rotation of the accretion flow. The jet of M87 is more or less East-West (projected onto the page), but the right hand side is pointing towards the Earth. It is assumed that the spin vector of the black hole is aligned (or anti-aligned) with this.
The two left hand plots show agreement with the observations. What they have in common is that the black hole spin vector is into the page (anti-aligned with the jet). Gas is forced to rotate in the same way and results in projected relativistic motion towards us south of the black hole and away from us north of the black hole. Doppler boosting and beaming does the rest.
answered 7 hours ago
Rob JeffriesRob Jeffries
70.7k7145245
70.7k7145245
add a comment |
add a comment |
$begingroup$
I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.
Image from BBC News and EHT Collaboration
The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.
New contributor
$endgroup$
1
$begingroup$
I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Douglas Held
9 hours ago
$begingroup$
@DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
$endgroup$
– StudyStudy
9 hours ago
$begingroup$
This doesn't address the reason for the asymmetry in the ring at all
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.
Image from BBC News and EHT Collaboration
The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.
New contributor
$endgroup$
1
$begingroup$
I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Douglas Held
9 hours ago
$begingroup$
@DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
$endgroup$
– StudyStudy
9 hours ago
$begingroup$
This doesn't address the reason for the asymmetry in the ring at all
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.
Image from BBC News and EHT Collaboration
The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.
New contributor
$endgroup$
I was going to ask a similiar question, so my (niave and completely amateur) answer is based on the paper recently published in The Astrophysical Journal Letters First M87 Event Horizon Telescope Results.
Image from BBC News and EHT Collaboration
The best-known effect is that a black hole, surrounded by an optically thin luminous plasma, should exhibit a "silhouette" or "shadow" morphology: a dim central region delineated by the lensed photon orbit (Falcke et al. 2000). The apparent size of the photon orbit, described not long after Schwarzschild's initial solution was published (Hilbert 1917; von Laue 1921), defines a bright ring or crescent shape that was calculated for arbitrary spin by Bardeen (1973), first imaged through simulations by Luminet 1979, and subsequently studied extensively (Chandrasekhar 1983; Takahashi 2004; Broderick & Loeb 2006). The size and shape of the resulting shadow depends primarily on the mass of the black hole, and only very weakly on its spin and the observing orientation.
New contributor
New contributor
answered 14 hours ago
StudyStudyStudyStudy
1377
1377
New contributor
New contributor
1
$begingroup$
I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Douglas Held
9 hours ago
$begingroup$
@DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
$endgroup$
– StudyStudy
9 hours ago
$begingroup$
This doesn't address the reason for the asymmetry in the ring at all
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
1
$begingroup$
I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Douglas Held
9 hours ago
$begingroup$
@DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
$endgroup$
– StudyStudy
9 hours ago
$begingroup$
This doesn't address the reason for the asymmetry in the ring at all
$endgroup$
– Rob Jeffries
7 hours ago
1
1
$begingroup$
I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Douglas Held
9 hours ago
$begingroup$
I am afraid your answer did not explain its answer to me :) but this YouTube video explains it in a way I can grasp. youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Douglas Held
9 hours ago
$begingroup$
@DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
$endgroup$
– StudyStudy
9 hours ago
$begingroup$
@DouglasHeld What amazes me is the details that the observers expected to see, that is, the level of prediction involved. But poor old John Mitchell en.m.wikipedia.org/wiki/John_Michell hardly gets a mention in the mainstream media.
$endgroup$
– StudyStudy
9 hours ago
$begingroup$
This doesn't address the reason for the asymmetry in the ring at all
$endgroup$
– Rob Jeffries
7 hours ago
$begingroup$
This doesn't address the reason for the asymmetry in the ring at all
$endgroup$
– Rob Jeffries
7 hours ago
add a comment |
$begingroup$
I found this animated GIF to explain this really well:
https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif
Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.
New contributor
$endgroup$
$begingroup$
Like Doppler effect?
$endgroup$
– 0x90
7 hours ago
$begingroup$
No - not like doppler effect.
$endgroup$
– Rory Alsop
6 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Draco18s
2 hours ago
add a comment |
$begingroup$
I found this animated GIF to explain this really well:
https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif
Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.
New contributor
$endgroup$
$begingroup$
Like Doppler effect?
$endgroup$
– 0x90
7 hours ago
$begingroup$
No - not like doppler effect.
$endgroup$
– Rory Alsop
6 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Draco18s
2 hours ago
add a comment |
$begingroup$
I found this animated GIF to explain this really well:
https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif
Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.
New contributor
$endgroup$
I found this animated GIF to explain this really well:
https://upload.wikimedia.org/wikipedia/commons/d/d6/BlackHole_Lensing.gif
Given this, it looks like it's just relative location of the black hole to the light sources behind/around it.
New contributor
New contributor
answered 8 hours ago
zxbEPREFzxbEPREF
109
109
New contributor
New contributor
$begingroup$
Like Doppler effect?
$endgroup$
– 0x90
7 hours ago
$begingroup$
No - not like doppler effect.
$endgroup$
– Rory Alsop
6 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Draco18s
2 hours ago
add a comment |
$begingroup$
Like Doppler effect?
$endgroup$
– 0x90
7 hours ago
$begingroup$
No - not like doppler effect.
$endgroup$
– Rory Alsop
6 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Draco18s
2 hours ago
$begingroup$
Like Doppler effect?
$endgroup$
– 0x90
7 hours ago
$begingroup$
Like Doppler effect?
$endgroup$
– 0x90
7 hours ago
$begingroup$
No - not like doppler effect.
$endgroup$
– Rory Alsop
6 hours ago
$begingroup$
No - not like doppler effect.
$endgroup$
– Rory Alsop
6 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Draco18s
2 hours ago
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– Draco18s
2 hours ago
add a comment |
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13
$begingroup$
Veritasium posted a good description of what all is going on here with a moderately accurate prediction of what this photo would look like before it was published.
$endgroup$
– Paul Sinclair
12 hours ago
1
$begingroup$
youtube.com/watch?v=zUyH3XhpLTo
$endgroup$
– penguin359
5 hours ago