On model categories where every object is bifibrantWhat is the “universal problem” that motivates the definition of homotopy limits/colimits (and more generally “derived” functors)?Do we still need model categories?Constructing a “geometric” model structure on Cat by localizing the “categorical” model structureA model category of abelian categories?On combinatorial and cellular model categories and infinity categoriesFibrant-cofibrant models of Eilenberg-MacLane spectraWhy is every object cofibrant in an excellent model category?Are strict $infty$-categories localized at weak equivalences a full subcategory of weak $infty$-categories?Is there an “injective version” of the Bergner model structure?Excellent monoidal model categories admit enriched fibrant replacement functors?

On model categories where every object is bifibrant


What is the “universal problem” that motivates the definition of homotopy limits/colimits (and more generally “derived” functors)?Do we still need model categories?Constructing a “geometric” model structure on Cat by localizing the “categorical” model structureA model category of abelian categories?On combinatorial and cellular model categories and infinity categoriesFibrant-cofibrant models of Eilenberg-MacLane spectraWhy is every object cofibrant in an excellent model category?Are strict $infty$-categories localized at weak equivalences a full subcategory of weak $infty$-categories?Is there an “injective version” of the Bergner model structure?Excellent monoidal model categories admit enriched fibrant replacement functors?













8












$begingroup$


Most model structures we use either have that every object is fibrant or that every object is cofibrant, and we have various general constructions that allow (under some assumption) to go from one situation to the other.



But there are very few examples of model categories where every object is both fibrant and cofibrant ("bifibrant").



The only example I know is when one starts with a strict 2-category with strict 2-limits and 2-colimits there are model structures on its underlying 1-category where every object is bifibrant and whose Dwyer-Kan localization is equivalent to the $2$-category itself (where one drop non-invertible 2-cells). So this typically applies to the canonical model category on Cat or on Groupoids. I'm not even sure it can be used to model things like the $2$-category of categories with finite limits.



I don't believe there are that many other examples. But I have never seen any obstruction for this. So:



Is there any example of a model category where every object is bifibrant whose localization is not a $2$-category?



Is every presentable $infty$-category represented by a model category where every object is bifibrant? If (as I expect) this is not the case, can we give an explicit 'obstruction' or an example to show it isn't the case?



Edit : The first question has been completely answered, but I havn't accepted answer so far because I'm still hoping to get an answer (positive or negative) to the second question.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Hi Simon. Just wanted to say, I haven't forgotten your email, and I do plan to reply. I've just been really busy. Sorry!
    $endgroup$
    – David White
    Mar 29 at 11:18










  • $begingroup$
    Trivial examples: any complete and cocomplete category with the isomorphisms as weak equivalences, and all morphisms are both fibrations and cofibrations.
    $endgroup$
    – Daniel Robert-Nicoud
    Mar 29 at 16:36










  • $begingroup$
    @DanielRobert-Nicoud : This one is a special case of the 2-categorical example.
    $endgroup$
    – Simon Henry
    Mar 29 at 17:15










  • $begingroup$
    I think your second question is much harder than your first one, so it might be better to ask them as separate questions.
    $endgroup$
    – Mike Shulman
    Mar 30 at 14:46















8












$begingroup$


Most model structures we use either have that every object is fibrant or that every object is cofibrant, and we have various general constructions that allow (under some assumption) to go from one situation to the other.



But there are very few examples of model categories where every object is both fibrant and cofibrant ("bifibrant").



The only example I know is when one starts with a strict 2-category with strict 2-limits and 2-colimits there are model structures on its underlying 1-category where every object is bifibrant and whose Dwyer-Kan localization is equivalent to the $2$-category itself (where one drop non-invertible 2-cells). So this typically applies to the canonical model category on Cat or on Groupoids. I'm not even sure it can be used to model things like the $2$-category of categories with finite limits.



I don't believe there are that many other examples. But I have never seen any obstruction for this. So:



Is there any example of a model category where every object is bifibrant whose localization is not a $2$-category?



Is every presentable $infty$-category represented by a model category where every object is bifibrant? If (as I expect) this is not the case, can we give an explicit 'obstruction' or an example to show it isn't the case?



Edit : The first question has been completely answered, but I havn't accepted answer so far because I'm still hoping to get an answer (positive or negative) to the second question.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Hi Simon. Just wanted to say, I haven't forgotten your email, and I do plan to reply. I've just been really busy. Sorry!
    $endgroup$
    – David White
    Mar 29 at 11:18










  • $begingroup$
    Trivial examples: any complete and cocomplete category with the isomorphisms as weak equivalences, and all morphisms are both fibrations and cofibrations.
    $endgroup$
    – Daniel Robert-Nicoud
    Mar 29 at 16:36










  • $begingroup$
    @DanielRobert-Nicoud : This one is a special case of the 2-categorical example.
    $endgroup$
    – Simon Henry
    Mar 29 at 17:15










  • $begingroup$
    I think your second question is much harder than your first one, so it might be better to ask them as separate questions.
    $endgroup$
    – Mike Shulman
    Mar 30 at 14:46













8












8








8





$begingroup$


Most model structures we use either have that every object is fibrant or that every object is cofibrant, and we have various general constructions that allow (under some assumption) to go from one situation to the other.



But there are very few examples of model categories where every object is both fibrant and cofibrant ("bifibrant").



The only example I know is when one starts with a strict 2-category with strict 2-limits and 2-colimits there are model structures on its underlying 1-category where every object is bifibrant and whose Dwyer-Kan localization is equivalent to the $2$-category itself (where one drop non-invertible 2-cells). So this typically applies to the canonical model category on Cat or on Groupoids. I'm not even sure it can be used to model things like the $2$-category of categories with finite limits.



I don't believe there are that many other examples. But I have never seen any obstruction for this. So:



Is there any example of a model category where every object is bifibrant whose localization is not a $2$-category?



Is every presentable $infty$-category represented by a model category where every object is bifibrant? If (as I expect) this is not the case, can we give an explicit 'obstruction' or an example to show it isn't the case?



Edit : The first question has been completely answered, but I havn't accepted answer so far because I'm still hoping to get an answer (positive or negative) to the second question.










share|cite|improve this question











$endgroup$




Most model structures we use either have that every object is fibrant or that every object is cofibrant, and we have various general constructions that allow (under some assumption) to go from one situation to the other.



But there are very few examples of model categories where every object is both fibrant and cofibrant ("bifibrant").



The only example I know is when one starts with a strict 2-category with strict 2-limits and 2-colimits there are model structures on its underlying 1-category where every object is bifibrant and whose Dwyer-Kan localization is equivalent to the $2$-category itself (where one drop non-invertible 2-cells). So this typically applies to the canonical model category on Cat or on Groupoids. I'm not even sure it can be used to model things like the $2$-category of categories with finite limits.



I don't believe there are that many other examples. But I have never seen any obstruction for this. So:



Is there any example of a model category where every object is bifibrant whose localization is not a $2$-category?



Is every presentable $infty$-category represented by a model category where every object is bifibrant? If (as I expect) this is not the case, can we give an explicit 'obstruction' or an example to show it isn't the case?



Edit : The first question has been completely answered, but I havn't accepted answer so far because I'm still hoping to get an answer (positive or negative) to the second question.







at.algebraic-topology ct.category-theory homotopy-theory model-categories






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 29 at 17:29







Simon Henry

















asked Mar 29 at 8:53









Simon HenrySimon Henry

16.1k15093




16.1k15093











  • $begingroup$
    Hi Simon. Just wanted to say, I haven't forgotten your email, and I do plan to reply. I've just been really busy. Sorry!
    $endgroup$
    – David White
    Mar 29 at 11:18










  • $begingroup$
    Trivial examples: any complete and cocomplete category with the isomorphisms as weak equivalences, and all morphisms are both fibrations and cofibrations.
    $endgroup$
    – Daniel Robert-Nicoud
    Mar 29 at 16:36










  • $begingroup$
    @DanielRobert-Nicoud : This one is a special case of the 2-categorical example.
    $endgroup$
    – Simon Henry
    Mar 29 at 17:15










  • $begingroup$
    I think your second question is much harder than your first one, so it might be better to ask them as separate questions.
    $endgroup$
    – Mike Shulman
    Mar 30 at 14:46
















  • $begingroup$
    Hi Simon. Just wanted to say, I haven't forgotten your email, and I do plan to reply. I've just been really busy. Sorry!
    $endgroup$
    – David White
    Mar 29 at 11:18










  • $begingroup$
    Trivial examples: any complete and cocomplete category with the isomorphisms as weak equivalences, and all morphisms are both fibrations and cofibrations.
    $endgroup$
    – Daniel Robert-Nicoud
    Mar 29 at 16:36










  • $begingroup$
    @DanielRobert-Nicoud : This one is a special case of the 2-categorical example.
    $endgroup$
    – Simon Henry
    Mar 29 at 17:15










  • $begingroup$
    I think your second question is much harder than your first one, so it might be better to ask them as separate questions.
    $endgroup$
    – Mike Shulman
    Mar 30 at 14:46















$begingroup$
Hi Simon. Just wanted to say, I haven't forgotten your email, and I do plan to reply. I've just been really busy. Sorry!
$endgroup$
– David White
Mar 29 at 11:18




$begingroup$
Hi Simon. Just wanted to say, I haven't forgotten your email, and I do plan to reply. I've just been really busy. Sorry!
$endgroup$
– David White
Mar 29 at 11:18












$begingroup$
Trivial examples: any complete and cocomplete category with the isomorphisms as weak equivalences, and all morphisms are both fibrations and cofibrations.
$endgroup$
– Daniel Robert-Nicoud
Mar 29 at 16:36




$begingroup$
Trivial examples: any complete and cocomplete category with the isomorphisms as weak equivalences, and all morphisms are both fibrations and cofibrations.
$endgroup$
– Daniel Robert-Nicoud
Mar 29 at 16:36












$begingroup$
@DanielRobert-Nicoud : This one is a special case of the 2-categorical example.
$endgroup$
– Simon Henry
Mar 29 at 17:15




$begingroup$
@DanielRobert-Nicoud : This one is a special case of the 2-categorical example.
$endgroup$
– Simon Henry
Mar 29 at 17:15












$begingroup$
I think your second question is much harder than your first one, so it might be better to ask them as separate questions.
$endgroup$
– Mike Shulman
Mar 30 at 14:46




$begingroup$
I think your second question is much harder than your first one, so it might be better to ask them as separate questions.
$endgroup$
– Mike Shulman
Mar 30 at 14:46










3 Answers
3






active

oldest

votes


















11












$begingroup$

Another example is given by Strom's model structure on topological spaces where



  • Fibrations: Hurewicz fibrations,

  • Weak equivalences : (strong) homotopy equivalences.





share|cite|improve this answer









$endgroup$




















    10












    $begingroup$

    An example of a different sort is the model structure on $R$-mod, whose homotopy category is the stable module category. A great reference is Theorem 2.2.12 in Hovey's book Model Categories. In this reference, $R$ is taken to be quasi-Frobenius. This model structure is generalized to work for any ring in the thesis of Daniel Bravo, and a resulting paper of Bravo-Gillespie-Hovey. But, you lose the property about all objects being bifibrant.



    Another example is the projective (or injective) model structure on $Ch(R)$ where $R$ is a field, and where we take chain complexes to be bounded (e.g. always non-negative degree, or you could do cochain complexes in non-positive degree). A great reference is Quillen's Rational Homotopy Theory. See also Section 2.3 of Hovey's book, but this is for the situation of unbounded chain complexes. The point is that, for the projective model structure, the fibrations are surjections, and as Lemma 2.3.6 shows, bounded below complexes of projective modules are cofibrant, and if $R$ is a field (or semi-simple ring) then all modules are projective.






    share|cite|improve this answer









    $endgroup$




















      0












      $begingroup$

      Look at this paper for some examples: Strong cofibrations and fibrations in enriched categories by R. Schwänzl and R. M. Vogt.






      share|cite|improve this answer









      $endgroup$













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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        11












        $begingroup$

        Another example is given by Strom's model structure on topological spaces where



        • Fibrations: Hurewicz fibrations,

        • Weak equivalences : (strong) homotopy equivalences.





        share|cite|improve this answer









        $endgroup$

















          11












          $begingroup$

          Another example is given by Strom's model structure on topological spaces where



          • Fibrations: Hurewicz fibrations,

          • Weak equivalences : (strong) homotopy equivalences.





          share|cite|improve this answer









          $endgroup$















            11












            11








            11





            $begingroup$

            Another example is given by Strom's model structure on topological spaces where



            • Fibrations: Hurewicz fibrations,

            • Weak equivalences : (strong) homotopy equivalences.





            share|cite|improve this answer









            $endgroup$



            Another example is given by Strom's model structure on topological spaces where



            • Fibrations: Hurewicz fibrations,

            • Weak equivalences : (strong) homotopy equivalences.






            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Mar 29 at 11:42









            David CDavid C

            7,45022142




            7,45022142





















                10












                $begingroup$

                An example of a different sort is the model structure on $R$-mod, whose homotopy category is the stable module category. A great reference is Theorem 2.2.12 in Hovey's book Model Categories. In this reference, $R$ is taken to be quasi-Frobenius. This model structure is generalized to work for any ring in the thesis of Daniel Bravo, and a resulting paper of Bravo-Gillespie-Hovey. But, you lose the property about all objects being bifibrant.



                Another example is the projective (or injective) model structure on $Ch(R)$ where $R$ is a field, and where we take chain complexes to be bounded (e.g. always non-negative degree, or you could do cochain complexes in non-positive degree). A great reference is Quillen's Rational Homotopy Theory. See also Section 2.3 of Hovey's book, but this is for the situation of unbounded chain complexes. The point is that, for the projective model structure, the fibrations are surjections, and as Lemma 2.3.6 shows, bounded below complexes of projective modules are cofibrant, and if $R$ is a field (or semi-simple ring) then all modules are projective.






                share|cite|improve this answer









                $endgroup$

















                  10












                  $begingroup$

                  An example of a different sort is the model structure on $R$-mod, whose homotopy category is the stable module category. A great reference is Theorem 2.2.12 in Hovey's book Model Categories. In this reference, $R$ is taken to be quasi-Frobenius. This model structure is generalized to work for any ring in the thesis of Daniel Bravo, and a resulting paper of Bravo-Gillespie-Hovey. But, you lose the property about all objects being bifibrant.



                  Another example is the projective (or injective) model structure on $Ch(R)$ where $R$ is a field, and where we take chain complexes to be bounded (e.g. always non-negative degree, or you could do cochain complexes in non-positive degree). A great reference is Quillen's Rational Homotopy Theory. See also Section 2.3 of Hovey's book, but this is for the situation of unbounded chain complexes. The point is that, for the projective model structure, the fibrations are surjections, and as Lemma 2.3.6 shows, bounded below complexes of projective modules are cofibrant, and if $R$ is a field (or semi-simple ring) then all modules are projective.






                  share|cite|improve this answer









                  $endgroup$















                    10












                    10








                    10





                    $begingroup$

                    An example of a different sort is the model structure on $R$-mod, whose homotopy category is the stable module category. A great reference is Theorem 2.2.12 in Hovey's book Model Categories. In this reference, $R$ is taken to be quasi-Frobenius. This model structure is generalized to work for any ring in the thesis of Daniel Bravo, and a resulting paper of Bravo-Gillespie-Hovey. But, you lose the property about all objects being bifibrant.



                    Another example is the projective (or injective) model structure on $Ch(R)$ where $R$ is a field, and where we take chain complexes to be bounded (e.g. always non-negative degree, or you could do cochain complexes in non-positive degree). A great reference is Quillen's Rational Homotopy Theory. See also Section 2.3 of Hovey's book, but this is for the situation of unbounded chain complexes. The point is that, for the projective model structure, the fibrations are surjections, and as Lemma 2.3.6 shows, bounded below complexes of projective modules are cofibrant, and if $R$ is a field (or semi-simple ring) then all modules are projective.






                    share|cite|improve this answer









                    $endgroup$



                    An example of a different sort is the model structure on $R$-mod, whose homotopy category is the stable module category. A great reference is Theorem 2.2.12 in Hovey's book Model Categories. In this reference, $R$ is taken to be quasi-Frobenius. This model structure is generalized to work for any ring in the thesis of Daniel Bravo, and a resulting paper of Bravo-Gillespie-Hovey. But, you lose the property about all objects being bifibrant.



                    Another example is the projective (or injective) model structure on $Ch(R)$ where $R$ is a field, and where we take chain complexes to be bounded (e.g. always non-negative degree, or you could do cochain complexes in non-positive degree). A great reference is Quillen's Rational Homotopy Theory. See also Section 2.3 of Hovey's book, but this is for the situation of unbounded chain complexes. The point is that, for the projective model structure, the fibrations are surjections, and as Lemma 2.3.6 shows, bounded below complexes of projective modules are cofibrant, and if $R$ is a field (or semi-simple ring) then all modules are projective.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Mar 29 at 11:18









                    David WhiteDavid White

                    13.2k465105




                    13.2k465105





















                        0












                        $begingroup$

                        Look at this paper for some examples: Strong cofibrations and fibrations in enriched categories by R. Schwänzl and R. M. Vogt.






                        share|cite|improve this answer









                        $endgroup$

















                          0












                          $begingroup$

                          Look at this paper for some examples: Strong cofibrations and fibrations in enriched categories by R. Schwänzl and R. M. Vogt.






                          share|cite|improve this answer









                          $endgroup$















                            0












                            0








                            0





                            $begingroup$

                            Look at this paper for some examples: Strong cofibrations and fibrations in enriched categories by R. Schwänzl and R. M. Vogt.






                            share|cite|improve this answer









                            $endgroup$



                            Look at this paper for some examples: Strong cofibrations and fibrations in enriched categories by R. Schwänzl and R. M. Vogt.







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered Apr 2 at 8:52









                            Philippe GaucherPhilippe Gaucher

                            1,7191020




                            1,7191020



























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Interview With Slayer Guitarist Jeff Hanneman”originalet”Thinking Out Loud: Slayer's Kerry King on hair metal, Satan and being polite””Slayer Lyrics””Slayer - Biography””Most influential artists for extreme metal music””Slayer - Reign in Blood””Slayer guitarist Jeff Hanneman dies aged 49””Slatanic Slaughter: A Tribute to Slayer””Gateway to Hell: A Tribute to Slayer””Covered In Blood””Slayer: The Origins of Thrash in San Francisco, CA.””Why They Rule - #6 Slayer”originalet”Guitar World's 100 Greatest Heavy Metal Guitarists Of All Time”originalet”The fans have spoken: Slayer comes out on top in readers' polls”originalet”Tribute to Jeff Hanneman (1964-2013)””Lamb Of God Frontman: We Sound Like A Slayer Rip-Off””BEHEMOTH Frontman Pays Tribute To SLAYER's JEFF HANNEMAN””Slayer, Hatebreed Doing Double Duty On This Year's Ozzfest””System of a Down””Lacuna Coil’s Andrea Ferro Talks Influences, Skateboarding, Band Origins + More””Slayer - Reign in Blood””Into The Lungs of Hell””Slayer rules - en utställning om fans””Slayer and Their Fans Slashed Through a No-Holds-Barred Night at Gas Monkey””Home””Slayer””Gold & Platinum - The Big 4 Live from Sofia, Bulgaria””Exclusive! Interview With Slayer Guitarist Kerry King””2008-02-23: Wiltern, Los Angeles, CA, USA””Slayer's Kerry King To Perform With Megadeth Tonight! - Oct. 21, 2010”originalet”Dave Lombardo - Biography”Slayer Case DismissedArkiveradUltimate Classic Rock: Slayer guitarist Jeff Hanneman dead at 49.”Slayer: "We could never do any thing like Some Kind Of Monster..."””Cannibal Corpse'S Pat O'Brien Will Step In As Slayer'S Guest Guitarist | The Official Slayer Site”originalet”Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Kerrang! Awards 2006 Blog: Kerrang! Hall Of Fame””Kerrang! Awards 2013: Kerrang! Legend”originalet”Metallica, Slayer, Iron Maien Among Winners At Metal Hammer Awards””Metal Hammer Golden Gods Awards””Bullet For My Valentine Booed At Metal Hammer Golden Gods Awards””Metal Storm Awards 2006””Metal Storm Awards 2015””Slayer's Concert History””Slayer - Relationships””Slayer - Releases”Slayers officiella webbplatsSlayer på MusicBrainzOfficiell webbplatsSlayerSlayerr1373445760000 0001 1540 47353068615-5086262726cb13906545x(data)6033143kn20030215029