Test whether all array elements are factors of a number





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







7















I have the following question:




Write a function that returns true if all integers in an array are factors of a number, and false otherwise.




I tried the code below:






function checkFactors(factors, num) {

for (let i=0; i<factors.length; i++){
let element = factors[i];
console.log(element)

if (num % element !== 0){
return false
}
else {
return true
}
}
}

console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false





My solution returns true which is wrong. I know it's the else statement that's messing it up. But I want to understand why the else statement can't go there.










share|improve this question




















  • 2





    You should get the return true out of the loop ;) and leave the return false inside the loop :) The reason for it is that otherwise your loop really stops after the first checking, returning either true or false, and you want it to return false as soon as something is not a factor. The return true outside of the loop would then indicate that all numbers supplied where factors of the number argument

    – Icepickle
    2 days ago








  • 2





    FYI, it's not just you, this is one of the most common errors people make when they first start out with programming and loops. :-)

    – T.J. Crowder
    2 days ago






  • 1





    @t.j.crowder yet we don't have a good dupetarget for it.

    – Jonas Wilms
    2 days ago






  • 2





    @JonasWilms - Yeah, I bookmarked this one on the basis that there isn't a lot of extraneous stuff, it really is just the earlier return thing. :-)

    – T.J. Crowder
    2 days ago











  • @T.J.Crowder stackoverflow.com/questions/42913798/… is the general dupe I wrote for this class of problems.

    – Barmar
    2 days ago




















7















I have the following question:




Write a function that returns true if all integers in an array are factors of a number, and false otherwise.




I tried the code below:






function checkFactors(factors, num) {

for (let i=0; i<factors.length; i++){
let element = factors[i];
console.log(element)

if (num % element !== 0){
return false
}
else {
return true
}
}
}

console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false





My solution returns true which is wrong. I know it's the else statement that's messing it up. But I want to understand why the else statement can't go there.










share|improve this question




















  • 2





    You should get the return true out of the loop ;) and leave the return false inside the loop :) The reason for it is that otherwise your loop really stops after the first checking, returning either true or false, and you want it to return false as soon as something is not a factor. The return true outside of the loop would then indicate that all numbers supplied where factors of the number argument

    – Icepickle
    2 days ago








  • 2





    FYI, it's not just you, this is one of the most common errors people make when they first start out with programming and loops. :-)

    – T.J. Crowder
    2 days ago






  • 1





    @t.j.crowder yet we don't have a good dupetarget for it.

    – Jonas Wilms
    2 days ago






  • 2





    @JonasWilms - Yeah, I bookmarked this one on the basis that there isn't a lot of extraneous stuff, it really is just the earlier return thing. :-)

    – T.J. Crowder
    2 days ago











  • @T.J.Crowder stackoverflow.com/questions/42913798/… is the general dupe I wrote for this class of problems.

    – Barmar
    2 days ago
















7












7








7


1






I have the following question:




Write a function that returns true if all integers in an array are factors of a number, and false otherwise.




I tried the code below:






function checkFactors(factors, num) {

for (let i=0; i<factors.length; i++){
let element = factors[i];
console.log(element)

if (num % element !== 0){
return false
}
else {
return true
}
}
}

console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false





My solution returns true which is wrong. I know it's the else statement that's messing it up. But I want to understand why the else statement can't go there.










share|improve this question
















I have the following question:




Write a function that returns true if all integers in an array are factors of a number, and false otherwise.




I tried the code below:






function checkFactors(factors, num) {

for (let i=0; i<factors.length; i++){
let element = factors[i];
console.log(element)

if (num % element !== 0){
return false
}
else {
return true
}
}
}

console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false





My solution returns true which is wrong. I know it's the else statement that's messing it up. But I want to understand why the else statement can't go there.






function checkFactors(factors, num) {

for (let i=0; i<factors.length; i++){
let element = factors[i];
console.log(element)

if (num % element !== 0){
return false
}
else {
return true
}
}
}

console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false





function checkFactors(factors, num) {

for (let i=0; i<factors.length; i++){
let element = factors[i];
console.log(element)

if (num % element !== 0){
return false
}
else {
return true
}
}
}

console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false






javascript arrays loops if-statement






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago









isanae

2,53711437




2,53711437










asked 2 days ago









PineNuts0PineNuts0

87631432




87631432








  • 2





    You should get the return true out of the loop ;) and leave the return false inside the loop :) The reason for it is that otherwise your loop really stops after the first checking, returning either true or false, and you want it to return false as soon as something is not a factor. The return true outside of the loop would then indicate that all numbers supplied where factors of the number argument

    – Icepickle
    2 days ago








  • 2





    FYI, it's not just you, this is one of the most common errors people make when they first start out with programming and loops. :-)

    – T.J. Crowder
    2 days ago






  • 1





    @t.j.crowder yet we don't have a good dupetarget for it.

    – Jonas Wilms
    2 days ago






  • 2





    @JonasWilms - Yeah, I bookmarked this one on the basis that there isn't a lot of extraneous stuff, it really is just the earlier return thing. :-)

    – T.J. Crowder
    2 days ago











  • @T.J.Crowder stackoverflow.com/questions/42913798/… is the general dupe I wrote for this class of problems.

    – Barmar
    2 days ago
















  • 2





    You should get the return true out of the loop ;) and leave the return false inside the loop :) The reason for it is that otherwise your loop really stops after the first checking, returning either true or false, and you want it to return false as soon as something is not a factor. The return true outside of the loop would then indicate that all numbers supplied where factors of the number argument

    – Icepickle
    2 days ago








  • 2





    FYI, it's not just you, this is one of the most common errors people make when they first start out with programming and loops. :-)

    – T.J. Crowder
    2 days ago






  • 1





    @t.j.crowder yet we don't have a good dupetarget for it.

    – Jonas Wilms
    2 days ago






  • 2





    @JonasWilms - Yeah, I bookmarked this one on the basis that there isn't a lot of extraneous stuff, it really is just the earlier return thing. :-)

    – T.J. Crowder
    2 days ago











  • @T.J.Crowder stackoverflow.com/questions/42913798/… is the general dupe I wrote for this class of problems.

    – Barmar
    2 days ago










2




2





You should get the return true out of the loop ;) and leave the return false inside the loop :) The reason for it is that otherwise your loop really stops after the first checking, returning either true or false, and you want it to return false as soon as something is not a factor. The return true outside of the loop would then indicate that all numbers supplied where factors of the number argument

– Icepickle
2 days ago







You should get the return true out of the loop ;) and leave the return false inside the loop :) The reason for it is that otherwise your loop really stops after the first checking, returning either true or false, and you want it to return false as soon as something is not a factor. The return true outside of the loop would then indicate that all numbers supplied where factors of the number argument

– Icepickle
2 days ago






2




2





FYI, it's not just you, this is one of the most common errors people make when they first start out with programming and loops. :-)

– T.J. Crowder
2 days ago





FYI, it's not just you, this is one of the most common errors people make when they first start out with programming and loops. :-)

– T.J. Crowder
2 days ago




1




1





@t.j.crowder yet we don't have a good dupetarget for it.

– Jonas Wilms
2 days ago





@t.j.crowder yet we don't have a good dupetarget for it.

– Jonas Wilms
2 days ago




2




2





@JonasWilms - Yeah, I bookmarked this one on the basis that there isn't a lot of extraneous stuff, it really is just the earlier return thing. :-)

– T.J. Crowder
2 days ago





@JonasWilms - Yeah, I bookmarked this one on the basis that there isn't a lot of extraneous stuff, it really is just the earlier return thing. :-)

– T.J. Crowder
2 days ago













@T.J.Crowder stackoverflow.com/questions/42913798/… is the general dupe I wrote for this class of problems.

– Barmar
2 days ago







@T.J.Crowder stackoverflow.com/questions/42913798/… is the general dupe I wrote for this class of problems.

– Barmar
2 days ago














5 Answers
5






active

oldest

votes


















5














Just place return true out of for loop,



If you keep return true in else part as soon as any of value which does not satisfies num % element !== 0 your code will return true which should not happen in this case as you're checking for all the values in array should be factor of given number




Let's understand by 1st example





  • On first element in array 1 it will check if condition num % element !== 0 which turns out false, so it will go to else condition and return true from function and will not check for rest of values.

  • So you need to keep return true at the end so if any of the value in loop doesn't satisfy the if condition than only control will go to return true





function checkFactors(factors, num) {

for (let i=0; i<factors.length; i++){
let element = factors[i];
if (num % element !== 0){
return false
}
}
return true
}



console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false
console.log(checkFactors([1, 2], 2))






In short - In such case where you want all of them must match a condition as a thumb rule you can consider it like





  1. keep the failing case return value inside for loop

  2. keep the passing case return value at the end of function


JS have a inbuilt method Array.every for such cases






function checkFactors(factors, num) {
return factors.every(element => num % element === 0);
}
console.log(checkFactors([1, 2, 3, 8], 12));
console.log(checkFactors([1, 2], 2));








share|improve this answer

































    7














    You are working in a chocolate store, and your boss tells you to check wether all chocolates (there are chili chocolate, caramel chocolate and coffee chocolate) are delicious. He tells you the following:



    Go through all chocolates, and for each chocolate, taste it, if it is fine, tell me that everything is fine, otherwise tell me that something is wrong¹



    You start with the first chocolate, which is chili chocolate, it tastes delucious, you go to your boss and tell him that everything is fine. Your boss yells at you because you haven't tasted the caramel chocolate and the coffee chocolate yet.



    You realize that your boss actually wanted you to do:



    Go through the chocolates, for each chocolate, taste it, if it doesnt taste well tell, tell me immeadiately, otherwise continue until you tasted them all, then return to me and tell me that everything is fine.²



    Or in code:



     // ¹
    function checkChocolates(chocolates) {
    for(const chocolate of chocolates) {
    if(isTasty(chocolate)) {
    return true;
    } else {
    return false;
    }
    }
    }

    // ²
    function checkChocolates(chocolates) {
    for(const chocolate of chocolates) {
    if(isTasty(chocolate)) {
    continue; // this could be omitted, as a loop keeps looping nevertheless
    } else {
    return false;
    }
    }
    return true;
    }


    As this is a very common task in programming, there is already a shorter way to express this:



     if(chocolates.every(isTasty)) {
    alert("all chocolates are fine");
    } else {
    alert("Oh, that doesnt taste good");
    }


    whereas isTasty is a function taking a chocolate and returning either true or false.





    If you didn't grasp it yet, just try it out! Buy some chocolate, and taste it! If someone tells you "eating choclate isn't learning", respond with "I'm doing rubber duck debugging" and no one can complain :)






    share|improve this answer





















    • 1





      A tiny quibble - it's "chocolate", not "choclate".

      – Wai Ha Lee
      2 days ago






    • 1





      @waiHaLee oh, pronounciation tricked me ...

      – Jonas Wilms
      2 days ago



















    1














    Inside the loop the input num was was tested for divisibility, if the num was divisible the control was going in the else block from where the function returned true.



    The loop was not checking for all numbers of the input array it was returning true when the first number was divisible.



    Just use a flag variable to see if all of the elements are divisible by the input number num, if any one is not divisible the flag will set to false and then we can break out of the loop and return it as there is no point to check the other numbers.






    function checkFactors(factors, num) {
    let flag = true;
    for (let i=0; i<factors.length; i++){
    let element = factors[i];
    if (num % element !== 0){
    flag = false;
    break;
    }
    }
    return flag;
    }

    console.log(checkFactors([1, 2, 3, 8], 12));
    console.log(checkFactors([1, 2], 2));
    console.log(checkFactors([2, 4, 3, 6, 9], 12));
    console.log(checkFactors([3, 5, 2, 6, 9], 15));
    console.log(checkFactors([4, 2, 8, 1], 16));





    You can also use Array.every to check the same in a concise way:






    function checkFactors(factors, num) {
    return factors.every(element => num % element === 0);
    }
    console.log(checkFactors([1, 2, 3, 8], 12));
    console.log(checkFactors([1, 2], 2));
    console.log(checkFactors([2, 4, 3, 6, 9], 12));
    console.log(checkFactors([3, 5, 2, 6, 9], 15));
    console.log(checkFactors([4, 2, 8, 1], 16));








    share|improve this answer

































      0














      Yes, "else" causing the issue. I removed it and added "return true" outside of for loop.



      function checkFactors(factors, num) {

      for (let i=0; i<factors.length; i++){
      let element = factors[i];
      console.log(element)

      if (num % element !== 0){
      return false
      }
      }
      return true;
      }





      share|improve this answer



















      • 1





        He is looking for an explanation as well though

        – Icepickle
        2 days ago











      • I see Icepickle has explained in the question comments nicely! Jonas Wilms's answer too.

        – javapedia.net
        2 days ago





















      0














      Your code's logic is wrong. You should check all the array's Elements, if all elements satisfy the condition, return true, but if one of them not satisfy the condition, return false immediately. The else means one item satisfy the condition, but not all elements. That's where the problem is.






      share|improve this answer








      New contributor




      W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





















        Your Answer






        StackExchange.ifUsing("editor", function () {
        StackExchange.using("externalEditor", function () {
        StackExchange.using("snippets", function () {
        StackExchange.snippets.init();
        });
        });
        }, "code-snippets");

        StackExchange.ready(function() {
        var channelOptions = {
        tags: "".split(" "),
        id: "1"
        };
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function() {
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled) {
        StackExchange.using("snippets", function() {
        createEditor();
        });
        }
        else {
        createEditor();
        }
        });

        function createEditor() {
        StackExchange.prepareEditor({
        heartbeatType: 'answer',
        autoActivateHeartbeat: false,
        convertImagesToLinks: true,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: 10,
        bindNavPrevention: true,
        postfix: "",
        imageUploader: {
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        },
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        });


        }
        });














        draft saved

        draft discarded


















        StackExchange.ready(
        function () {
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55549338%2ftest-whether-all-array-elements-are-factors-of-a-number%23new-answer', 'question_page');
        }
        );

        Post as a guest















        Required, but never shown

























        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        5














        Just place return true out of for loop,



        If you keep return true in else part as soon as any of value which does not satisfies num % element !== 0 your code will return true which should not happen in this case as you're checking for all the values in array should be factor of given number




        Let's understand by 1st example





        • On first element in array 1 it will check if condition num % element !== 0 which turns out false, so it will go to else condition and return true from function and will not check for rest of values.

        • So you need to keep return true at the end so if any of the value in loop doesn't satisfy the if condition than only control will go to return true





        function checkFactors(factors, num) {

        for (let i=0; i<factors.length; i++){
        let element = factors[i];
        if (num % element !== 0){
        return false
        }
        }
        return true
        }



        console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false
        console.log(checkFactors([1, 2], 2))






        In short - In such case where you want all of them must match a condition as a thumb rule you can consider it like





        1. keep the failing case return value inside for loop

        2. keep the passing case return value at the end of function


        JS have a inbuilt method Array.every for such cases






        function checkFactors(factors, num) {
        return factors.every(element => num % element === 0);
        }
        console.log(checkFactors([1, 2, 3, 8], 12));
        console.log(checkFactors([1, 2], 2));








        share|improve this answer






























          5














          Just place return true out of for loop,



          If you keep return true in else part as soon as any of value which does not satisfies num % element !== 0 your code will return true which should not happen in this case as you're checking for all the values in array should be factor of given number




          Let's understand by 1st example





          • On first element in array 1 it will check if condition num % element !== 0 which turns out false, so it will go to else condition and return true from function and will not check for rest of values.

          • So you need to keep return true at the end so if any of the value in loop doesn't satisfy the if condition than only control will go to return true





          function checkFactors(factors, num) {

          for (let i=0; i<factors.length; i++){
          let element = factors[i];
          if (num % element !== 0){
          return false
          }
          }
          return true
          }



          console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false
          console.log(checkFactors([1, 2], 2))






          In short - In such case where you want all of them must match a condition as a thumb rule you can consider it like





          1. keep the failing case return value inside for loop

          2. keep the passing case return value at the end of function


          JS have a inbuilt method Array.every for such cases






          function checkFactors(factors, num) {
          return factors.every(element => num % element === 0);
          }
          console.log(checkFactors([1, 2, 3, 8], 12));
          console.log(checkFactors([1, 2], 2));








          share|improve this answer




























            5












            5








            5







            Just place return true out of for loop,



            If you keep return true in else part as soon as any of value which does not satisfies num % element !== 0 your code will return true which should not happen in this case as you're checking for all the values in array should be factor of given number




            Let's understand by 1st example





            • On first element in array 1 it will check if condition num % element !== 0 which turns out false, so it will go to else condition and return true from function and will not check for rest of values.

            • So you need to keep return true at the end so if any of the value in loop doesn't satisfy the if condition than only control will go to return true





            function checkFactors(factors, num) {

            for (let i=0; i<factors.length; i++){
            let element = factors[i];
            if (num % element !== 0){
            return false
            }
            }
            return true
            }



            console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false
            console.log(checkFactors([1, 2], 2))






            In short - In such case where you want all of them must match a condition as a thumb rule you can consider it like





            1. keep the failing case return value inside for loop

            2. keep the passing case return value at the end of function


            JS have a inbuilt method Array.every for such cases






            function checkFactors(factors, num) {
            return factors.every(element => num % element === 0);
            }
            console.log(checkFactors([1, 2, 3, 8], 12));
            console.log(checkFactors([1, 2], 2));








            share|improve this answer















            Just place return true out of for loop,



            If you keep return true in else part as soon as any of value which does not satisfies num % element !== 0 your code will return true which should not happen in this case as you're checking for all the values in array should be factor of given number




            Let's understand by 1st example





            • On first element in array 1 it will check if condition num % element !== 0 which turns out false, so it will go to else condition and return true from function and will not check for rest of values.

            • So you need to keep return true at the end so if any of the value in loop doesn't satisfy the if condition than only control will go to return true





            function checkFactors(factors, num) {

            for (let i=0; i<factors.length; i++){
            let element = factors[i];
            if (num % element !== 0){
            return false
            }
            }
            return true
            }



            console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false
            console.log(checkFactors([1, 2], 2))






            In short - In such case where you want all of them must match a condition as a thumb rule you can consider it like





            1. keep the failing case return value inside for loop

            2. keep the passing case return value at the end of function


            JS have a inbuilt method Array.every for such cases






            function checkFactors(factors, num) {
            return factors.every(element => num % element === 0);
            }
            console.log(checkFactors([1, 2, 3, 8], 12));
            console.log(checkFactors([1, 2], 2));








            function checkFactors(factors, num) {

            for (let i=0; i<factors.length; i++){
            let element = factors[i];
            if (num % element !== 0){
            return false
            }
            }
            return true
            }



            console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false
            console.log(checkFactors([1, 2], 2))





            function checkFactors(factors, num) {

            for (let i=0; i<factors.length; i++){
            let element = factors[i];
            if (num % element !== 0){
            return false
            }
            }
            return true
            }



            console.log(checkFactors([1, 2, 3, 8], 12)) //➞ false
            console.log(checkFactors([1, 2], 2))





            function checkFactors(factors, num) {
            return factors.every(element => num % element === 0);
            }
            console.log(checkFactors([1, 2, 3, 8], 12));
            console.log(checkFactors([1, 2], 2));





            function checkFactors(factors, num) {
            return factors.every(element => num % element === 0);
            }
            console.log(checkFactors([1, 2, 3, 8], 12));
            console.log(checkFactors([1, 2], 2));






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 days ago

























            answered 2 days ago









            Code ManiacCode Maniac

            11.8k2834




            11.8k2834

























                7














                You are working in a chocolate store, and your boss tells you to check wether all chocolates (there are chili chocolate, caramel chocolate and coffee chocolate) are delicious. He tells you the following:



                Go through all chocolates, and for each chocolate, taste it, if it is fine, tell me that everything is fine, otherwise tell me that something is wrong¹



                You start with the first chocolate, which is chili chocolate, it tastes delucious, you go to your boss and tell him that everything is fine. Your boss yells at you because you haven't tasted the caramel chocolate and the coffee chocolate yet.



                You realize that your boss actually wanted you to do:



                Go through the chocolates, for each chocolate, taste it, if it doesnt taste well tell, tell me immeadiately, otherwise continue until you tasted them all, then return to me and tell me that everything is fine.²



                Or in code:



                 // ¹
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                return true;
                } else {
                return false;
                }
                }
                }

                // ²
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                continue; // this could be omitted, as a loop keeps looping nevertheless
                } else {
                return false;
                }
                }
                return true;
                }


                As this is a very common task in programming, there is already a shorter way to express this:



                 if(chocolates.every(isTasty)) {
                alert("all chocolates are fine");
                } else {
                alert("Oh, that doesnt taste good");
                }


                whereas isTasty is a function taking a chocolate and returning either true or false.





                If you didn't grasp it yet, just try it out! Buy some chocolate, and taste it! If someone tells you "eating choclate isn't learning", respond with "I'm doing rubber duck debugging" and no one can complain :)






                share|improve this answer





















                • 1





                  A tiny quibble - it's "chocolate", not "choclate".

                  – Wai Ha Lee
                  2 days ago






                • 1





                  @waiHaLee oh, pronounciation tricked me ...

                  – Jonas Wilms
                  2 days ago
















                7














                You are working in a chocolate store, and your boss tells you to check wether all chocolates (there are chili chocolate, caramel chocolate and coffee chocolate) are delicious. He tells you the following:



                Go through all chocolates, and for each chocolate, taste it, if it is fine, tell me that everything is fine, otherwise tell me that something is wrong¹



                You start with the first chocolate, which is chili chocolate, it tastes delucious, you go to your boss and tell him that everything is fine. Your boss yells at you because you haven't tasted the caramel chocolate and the coffee chocolate yet.



                You realize that your boss actually wanted you to do:



                Go through the chocolates, for each chocolate, taste it, if it doesnt taste well tell, tell me immeadiately, otherwise continue until you tasted them all, then return to me and tell me that everything is fine.²



                Or in code:



                 // ¹
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                return true;
                } else {
                return false;
                }
                }
                }

                // ²
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                continue; // this could be omitted, as a loop keeps looping nevertheless
                } else {
                return false;
                }
                }
                return true;
                }


                As this is a very common task in programming, there is already a shorter way to express this:



                 if(chocolates.every(isTasty)) {
                alert("all chocolates are fine");
                } else {
                alert("Oh, that doesnt taste good");
                }


                whereas isTasty is a function taking a chocolate and returning either true or false.





                If you didn't grasp it yet, just try it out! Buy some chocolate, and taste it! If someone tells you "eating choclate isn't learning", respond with "I'm doing rubber duck debugging" and no one can complain :)






                share|improve this answer





















                • 1





                  A tiny quibble - it's "chocolate", not "choclate".

                  – Wai Ha Lee
                  2 days ago






                • 1





                  @waiHaLee oh, pronounciation tricked me ...

                  – Jonas Wilms
                  2 days ago














                7












                7








                7







                You are working in a chocolate store, and your boss tells you to check wether all chocolates (there are chili chocolate, caramel chocolate and coffee chocolate) are delicious. He tells you the following:



                Go through all chocolates, and for each chocolate, taste it, if it is fine, tell me that everything is fine, otherwise tell me that something is wrong¹



                You start with the first chocolate, which is chili chocolate, it tastes delucious, you go to your boss and tell him that everything is fine. Your boss yells at you because you haven't tasted the caramel chocolate and the coffee chocolate yet.



                You realize that your boss actually wanted you to do:



                Go through the chocolates, for each chocolate, taste it, if it doesnt taste well tell, tell me immeadiately, otherwise continue until you tasted them all, then return to me and tell me that everything is fine.²



                Or in code:



                 // ¹
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                return true;
                } else {
                return false;
                }
                }
                }

                // ²
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                continue; // this could be omitted, as a loop keeps looping nevertheless
                } else {
                return false;
                }
                }
                return true;
                }


                As this is a very common task in programming, there is already a shorter way to express this:



                 if(chocolates.every(isTasty)) {
                alert("all chocolates are fine");
                } else {
                alert("Oh, that doesnt taste good");
                }


                whereas isTasty is a function taking a chocolate and returning either true or false.





                If you didn't grasp it yet, just try it out! Buy some chocolate, and taste it! If someone tells you "eating choclate isn't learning", respond with "I'm doing rubber duck debugging" and no one can complain :)






                share|improve this answer















                You are working in a chocolate store, and your boss tells you to check wether all chocolates (there are chili chocolate, caramel chocolate and coffee chocolate) are delicious. He tells you the following:



                Go through all chocolates, and for each chocolate, taste it, if it is fine, tell me that everything is fine, otherwise tell me that something is wrong¹



                You start with the first chocolate, which is chili chocolate, it tastes delucious, you go to your boss and tell him that everything is fine. Your boss yells at you because you haven't tasted the caramel chocolate and the coffee chocolate yet.



                You realize that your boss actually wanted you to do:



                Go through the chocolates, for each chocolate, taste it, if it doesnt taste well tell, tell me immeadiately, otherwise continue until you tasted them all, then return to me and tell me that everything is fine.²



                Or in code:



                 // ¹
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                return true;
                } else {
                return false;
                }
                }
                }

                // ²
                function checkChocolates(chocolates) {
                for(const chocolate of chocolates) {
                if(isTasty(chocolate)) {
                continue; // this could be omitted, as a loop keeps looping nevertheless
                } else {
                return false;
                }
                }
                return true;
                }


                As this is a very common task in programming, there is already a shorter way to express this:



                 if(chocolates.every(isTasty)) {
                alert("all chocolates are fine");
                } else {
                alert("Oh, that doesnt taste good");
                }


                whereas isTasty is a function taking a chocolate and returning either true or false.





                If you didn't grasp it yet, just try it out! Buy some chocolate, and taste it! If someone tells you "eating choclate isn't learning", respond with "I'm doing rubber duck debugging" and no one can complain :)







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 days ago

























                answered 2 days ago









                Jonas WilmsJonas Wilms

                65.5k53660




                65.5k53660








                • 1





                  A tiny quibble - it's "chocolate", not "choclate".

                  – Wai Ha Lee
                  2 days ago






                • 1





                  @waiHaLee oh, pronounciation tricked me ...

                  – Jonas Wilms
                  2 days ago














                • 1





                  A tiny quibble - it's "chocolate", not "choclate".

                  – Wai Ha Lee
                  2 days ago






                • 1





                  @waiHaLee oh, pronounciation tricked me ...

                  – Jonas Wilms
                  2 days ago








                1




                1





                A tiny quibble - it's "chocolate", not "choclate".

                – Wai Ha Lee
                2 days ago





                A tiny quibble - it's "chocolate", not "choclate".

                – Wai Ha Lee
                2 days ago




                1




                1





                @waiHaLee oh, pronounciation tricked me ...

                – Jonas Wilms
                2 days ago





                @waiHaLee oh, pronounciation tricked me ...

                – Jonas Wilms
                2 days ago











                1














                Inside the loop the input num was was tested for divisibility, if the num was divisible the control was going in the else block from where the function returned true.



                The loop was not checking for all numbers of the input array it was returning true when the first number was divisible.



                Just use a flag variable to see if all of the elements are divisible by the input number num, if any one is not divisible the flag will set to false and then we can break out of the loop and return it as there is no point to check the other numbers.






                function checkFactors(factors, num) {
                let flag = true;
                for (let i=0; i<factors.length; i++){
                let element = factors[i];
                if (num % element !== 0){
                flag = false;
                break;
                }
                }
                return flag;
                }

                console.log(checkFactors([1, 2, 3, 8], 12));
                console.log(checkFactors([1, 2], 2));
                console.log(checkFactors([2, 4, 3, 6, 9], 12));
                console.log(checkFactors([3, 5, 2, 6, 9], 15));
                console.log(checkFactors([4, 2, 8, 1], 16));





                You can also use Array.every to check the same in a concise way:






                function checkFactors(factors, num) {
                return factors.every(element => num % element === 0);
                }
                console.log(checkFactors([1, 2, 3, 8], 12));
                console.log(checkFactors([1, 2], 2));
                console.log(checkFactors([2, 4, 3, 6, 9], 12));
                console.log(checkFactors([3, 5, 2, 6, 9], 15));
                console.log(checkFactors([4, 2, 8, 1], 16));








                share|improve this answer






























                  1














                  Inside the loop the input num was was tested for divisibility, if the num was divisible the control was going in the else block from where the function returned true.



                  The loop was not checking for all numbers of the input array it was returning true when the first number was divisible.



                  Just use a flag variable to see if all of the elements are divisible by the input number num, if any one is not divisible the flag will set to false and then we can break out of the loop and return it as there is no point to check the other numbers.






                  function checkFactors(factors, num) {
                  let flag = true;
                  for (let i=0; i<factors.length; i++){
                  let element = factors[i];
                  if (num % element !== 0){
                  flag = false;
                  break;
                  }
                  }
                  return flag;
                  }

                  console.log(checkFactors([1, 2, 3, 8], 12));
                  console.log(checkFactors([1, 2], 2));
                  console.log(checkFactors([2, 4, 3, 6, 9], 12));
                  console.log(checkFactors([3, 5, 2, 6, 9], 15));
                  console.log(checkFactors([4, 2, 8, 1], 16));





                  You can also use Array.every to check the same in a concise way:






                  function checkFactors(factors, num) {
                  return factors.every(element => num % element === 0);
                  }
                  console.log(checkFactors([1, 2, 3, 8], 12));
                  console.log(checkFactors([1, 2], 2));
                  console.log(checkFactors([2, 4, 3, 6, 9], 12));
                  console.log(checkFactors([3, 5, 2, 6, 9], 15));
                  console.log(checkFactors([4, 2, 8, 1], 16));








                  share|improve this answer




























                    1












                    1








                    1







                    Inside the loop the input num was was tested for divisibility, if the num was divisible the control was going in the else block from where the function returned true.



                    The loop was not checking for all numbers of the input array it was returning true when the first number was divisible.



                    Just use a flag variable to see if all of the elements are divisible by the input number num, if any one is not divisible the flag will set to false and then we can break out of the loop and return it as there is no point to check the other numbers.






                    function checkFactors(factors, num) {
                    let flag = true;
                    for (let i=0; i<factors.length; i++){
                    let element = factors[i];
                    if (num % element !== 0){
                    flag = false;
                    break;
                    }
                    }
                    return flag;
                    }

                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));





                    You can also use Array.every to check the same in a concise way:






                    function checkFactors(factors, num) {
                    return factors.every(element => num % element === 0);
                    }
                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));








                    share|improve this answer















                    Inside the loop the input num was was tested for divisibility, if the num was divisible the control was going in the else block from where the function returned true.



                    The loop was not checking for all numbers of the input array it was returning true when the first number was divisible.



                    Just use a flag variable to see if all of the elements are divisible by the input number num, if any one is not divisible the flag will set to false and then we can break out of the loop and return it as there is no point to check the other numbers.






                    function checkFactors(factors, num) {
                    let flag = true;
                    for (let i=0; i<factors.length; i++){
                    let element = factors[i];
                    if (num % element !== 0){
                    flag = false;
                    break;
                    }
                    }
                    return flag;
                    }

                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));





                    You can also use Array.every to check the same in a concise way:






                    function checkFactors(factors, num) {
                    return factors.every(element => num % element === 0);
                    }
                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));








                    function checkFactors(factors, num) {
                    let flag = true;
                    for (let i=0; i<factors.length; i++){
                    let element = factors[i];
                    if (num % element !== 0){
                    flag = false;
                    break;
                    }
                    }
                    return flag;
                    }

                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));





                    function checkFactors(factors, num) {
                    let flag = true;
                    for (let i=0; i<factors.length; i++){
                    let element = factors[i];
                    if (num % element !== 0){
                    flag = false;
                    break;
                    }
                    }
                    return flag;
                    }

                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));





                    function checkFactors(factors, num) {
                    return factors.every(element => num % element === 0);
                    }
                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));





                    function checkFactors(factors, num) {
                    return factors.every(element => num % element === 0);
                    }
                    console.log(checkFactors([1, 2, 3, 8], 12));
                    console.log(checkFactors([1, 2], 2));
                    console.log(checkFactors([2, 4, 3, 6, 9], 12));
                    console.log(checkFactors([3, 5, 2, 6, 9], 15));
                    console.log(checkFactors([4, 2, 8, 1], 16));






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 2 days ago

























                    answered 2 days ago









                    Amardeep BhowmickAmardeep Bhowmick

                    5,45821128




                    5,45821128























                        0














                        Yes, "else" causing the issue. I removed it and added "return true" outside of for loop.



                        function checkFactors(factors, num) {

                        for (let i=0; i<factors.length; i++){
                        let element = factors[i];
                        console.log(element)

                        if (num % element !== 0){
                        return false
                        }
                        }
                        return true;
                        }





                        share|improve this answer



















                        • 1





                          He is looking for an explanation as well though

                          – Icepickle
                          2 days ago











                        • I see Icepickle has explained in the question comments nicely! Jonas Wilms's answer too.

                          – javapedia.net
                          2 days ago


















                        0














                        Yes, "else" causing the issue. I removed it and added "return true" outside of for loop.



                        function checkFactors(factors, num) {

                        for (let i=0; i<factors.length; i++){
                        let element = factors[i];
                        console.log(element)

                        if (num % element !== 0){
                        return false
                        }
                        }
                        return true;
                        }





                        share|improve this answer



















                        • 1





                          He is looking for an explanation as well though

                          – Icepickle
                          2 days ago











                        • I see Icepickle has explained in the question comments nicely! Jonas Wilms's answer too.

                          – javapedia.net
                          2 days ago
















                        0












                        0








                        0







                        Yes, "else" causing the issue. I removed it and added "return true" outside of for loop.



                        function checkFactors(factors, num) {

                        for (let i=0; i<factors.length; i++){
                        let element = factors[i];
                        console.log(element)

                        if (num % element !== 0){
                        return false
                        }
                        }
                        return true;
                        }





                        share|improve this answer













                        Yes, "else" causing the issue. I removed it and added "return true" outside of for loop.



                        function checkFactors(factors, num) {

                        for (let i=0; i<factors.length; i++){
                        let element = factors[i];
                        console.log(element)

                        if (num % element !== 0){
                        return false
                        }
                        }
                        return true;
                        }






                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered 2 days ago









                        javapedia.netjavapedia.net

                        575312




                        575312








                        • 1





                          He is looking for an explanation as well though

                          – Icepickle
                          2 days ago











                        • I see Icepickle has explained in the question comments nicely! Jonas Wilms's answer too.

                          – javapedia.net
                          2 days ago
















                        • 1





                          He is looking for an explanation as well though

                          – Icepickle
                          2 days ago











                        • I see Icepickle has explained in the question comments nicely! Jonas Wilms's answer too.

                          – javapedia.net
                          2 days ago










                        1




                        1





                        He is looking for an explanation as well though

                        – Icepickle
                        2 days ago





                        He is looking for an explanation as well though

                        – Icepickle
                        2 days ago













                        I see Icepickle has explained in the question comments nicely! Jonas Wilms's answer too.

                        – javapedia.net
                        2 days ago







                        I see Icepickle has explained in the question comments nicely! Jonas Wilms's answer too.

                        – javapedia.net
                        2 days ago













                        0














                        Your code's logic is wrong. You should check all the array's Elements, if all elements satisfy the condition, return true, but if one of them not satisfy the condition, return false immediately. The else means one item satisfy the condition, but not all elements. That's where the problem is.






                        share|improve this answer








                        New contributor




                        W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                        Check out our Code of Conduct.

























                          0














                          Your code's logic is wrong. You should check all the array's Elements, if all elements satisfy the condition, return true, but if one of them not satisfy the condition, return false immediately. The else means one item satisfy the condition, but not all elements. That's where the problem is.






                          share|improve this answer








                          New contributor




                          W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.























                            0












                            0








                            0







                            Your code's logic is wrong. You should check all the array's Elements, if all elements satisfy the condition, return true, but if one of them not satisfy the condition, return false immediately. The else means one item satisfy the condition, but not all elements. That's where the problem is.






                            share|improve this answer








                            New contributor




                            W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.










                            Your code's logic is wrong. You should check all the array's Elements, if all elements satisfy the condition, return true, but if one of them not satisfy the condition, return false immediately. The else means one item satisfy the condition, but not all elements. That's where the problem is.







                            share|improve this answer








                            New contributor




                            W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            share|improve this answer



                            share|improve this answer






                            New contributor




                            W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            answered 2 days ago









                            W.BrightW.Bright

                            133




                            133




                            New contributor




                            W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.





                            New contributor





                            W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.






                            W.Bright is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.






























                                draft saved

                                draft discarded




















































                                Thanks for contributing an answer to Stack Overflow!


                                • Please be sure to answer the question. Provide details and share your research!

                                But avoid



                                • Asking for help, clarification, or responding to other answers.

                                • Making statements based on opinion; back them up with references or personal experience.


                                To learn more, see our tips on writing great answers.




                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function () {
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55549338%2ftest-whether-all-array-elements-are-factors-of-a-number%23new-answer', 'question_page');
                                }
                                );

                                Post as a guest















                                Required, but never shown





















































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown

































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown







                                Popular posts from this blog

                                Færeyskur hestur Heimild | Tengill | Tilvísanir | LeiðsagnarvalRossið - síða um færeyska hrossið á færeyskuGott ár hjá færeyska hestinum

                                He _____ here since 1970 . Answer needed [closed]What does “since he was so high” mean?Meaning of “catch birds for”?How do I ensure “since” takes the meaning I want?“Who cares here” meaningWhat does “right round toward” mean?the time tense (had now been detected)What does the phrase “ring around the roses” mean here?Correct usage of “visited upon”Meaning of “foiled rail sabotage bid”It was the third time I had gone to Rome or It is the third time I had been to Rome

                                Slayer Innehåll Historia | Stil, komposition och lyrik | Bandets betydelse och framgångar | Sidoprojekt och samarbeten | Kontroverser | Medlemmar | Utmärkelser och nomineringar | Turnéer och festivaler | Diskografi | Referenser | Externa länkar | Navigeringsmenywww.slayer.net”Metal Massacre vol. 1””Metal Massacre vol. 3””Metal Massacre Volume III””Show No Mercy””Haunting the Chapel””Live Undead””Hell Awaits””Reign in Blood””Reign in Blood””Gold & Platinum – Reign in Blood””Golden Gods Awards Winners”originalet”Kerrang! Hall Of Fame””Slayer Looks Back On 37-Year Career In New Video Series: Part Two””South of Heaven””Gold & Platinum – South of Heaven””Seasons in the Abyss””Gold & Platinum - Seasons in the Abyss””Divine Intervention””Divine Intervention - Release group by Slayer””Gold & Platinum - Divine Intervention””Live Intrusion””Undisputed Attitude””Abolish Government/Superficial Love””Release “Slatanic Slaughter: A Tribute to Slayer” by Various Artists””Diabolus in Musica””Soundtrack to the Apocalypse””God Hates Us All””Systematic - Relationships””War at the Warfield””Gold & Platinum - War at the Warfield””Soundtrack to the Apocalypse””Gold & Platinum - Still Reigning””Metallica, Slayer, Iron Mauden Among Winners At Metal Hammer Awards””Eternal Pyre””Eternal Pyre - Slayer release group””Eternal Pyre””Metal Storm Awards 2006””Kerrang! Hall Of Fame””Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Bullet-For My Valentine booed at Metal Hammer Golden Gods Awards””Unholy Aliance””The End Of Slayer?””Slayer: We Could Thrash Out Two More Albums If We're Fast Enough...””'The Unholy Alliance: Chapter III' UK Dates Added”originalet”Megadeth And Slayer To Co-Headline 'Canadian Carnage' Trek”originalet”World Painted Blood””Release “World Painted Blood” by Slayer””Metallica Heading To Cinemas””Slayer, Megadeth To Join Forces For 'European Carnage' Tour - Dec. 18, 2010”originalet”Slayer's Hanneman Contracts Acute Infection; Band To Bring In Guest Guitarist””Cannibal Corpse's Pat O'Brien Will Step In As Slayer's Guest Guitarist”originalet”Slayer’s Jeff Hanneman Dead at 49””Dave Lombardo Says He Made Only $67,000 In 2011 While Touring With Slayer””Slayer: We Do Not Agree With Dave Lombardo's Substance Or Timeline Of Events””Slayer Welcomes Drummer Paul Bostaph Back To The Fold””Slayer Hope to Unveil Never-Before-Heard Jeff Hanneman Material on Next Album””Slayer Debut New Song 'Implode' During Surprise Golden Gods Appearance””Release group Repentless by Slayer””Repentless - Slayer - Credits””Slayer””Metal Storm Awards 2015””Slayer - to release comic book "Repentless #1"””Slayer To Release 'Repentless' 6.66" Vinyl Box Set””BREAKING NEWS: Slayer Announce Farewell Tour””Slayer Recruit Lamb of God, Anthrax, Behemoth + Testament for Final Tour””Slayer lägger ner efter 37 år””Slayer Announces Second North American Leg Of 'Final' Tour””Final World Tour””Slayer Announces Final European Tour With Lamb of God, Anthrax And Obituary””Slayer To Tour Europe With Lamb of God, Anthrax And Obituary””Slayer To Play 'Last French Show Ever' At Next Year's Hellfst””Slayer's Final World Tour Will Extend Into 2019””Death Angel's Rob Cavestany On Slayer's 'Farewell' Tour: 'Some Of Us Could See This Coming'””Testament Has No Plans To Retire Anytime Soon, Says Chuck Billy””Anthrax's Scott Ian On Slayer's 'Farewell' Tour Plans: 'I Was Surprised And I Wasn't Surprised'””Slayer””Slayer's Morbid Schlock””Review/Rock; For Slayer, the Mania Is the Message””Slayer - Biography””Slayer - Reign In Blood”originalet”Dave Lombardo””An exclusive oral history of Slayer”originalet”Exclusive! Interview With Slayer Guitarist Jeff Hanneman”originalet”Thinking Out Loud: Slayer's Kerry King on hair metal, Satan and being polite””Slayer Lyrics””Slayer - Biography””Most influential artists for extreme metal music””Slayer - Reign in Blood””Slayer guitarist Jeff Hanneman dies aged 49””Slatanic Slaughter: A Tribute to Slayer””Gateway to Hell: A Tribute to Slayer””Covered In Blood””Slayer: The Origins of Thrash in San Francisco, CA.””Why They Rule - #6 Slayer”originalet”Guitar World's 100 Greatest Heavy Metal Guitarists Of All Time”originalet”The fans have spoken: Slayer comes out on top in readers' polls”originalet”Tribute to Jeff Hanneman (1964-2013)””Lamb Of God Frontman: We Sound Like A Slayer Rip-Off””BEHEMOTH Frontman Pays Tribute To SLAYER's JEFF HANNEMAN””Slayer, Hatebreed Doing Double Duty On This Year's Ozzfest””System of a Down””Lacuna Coil’s Andrea Ferro Talks Influences, Skateboarding, Band Origins + More””Slayer - Reign in Blood””Into The Lungs of Hell””Slayer rules - en utställning om fans””Slayer and Their Fans Slashed Through a No-Holds-Barred Night at Gas Monkey””Home””Slayer””Gold & Platinum - The Big 4 Live from Sofia, Bulgaria””Exclusive! Interview With Slayer Guitarist Kerry King””2008-02-23: Wiltern, Los Angeles, CA, USA””Slayer's Kerry King To Perform With Megadeth Tonight! - Oct. 21, 2010”originalet”Dave Lombardo - Biography”Slayer Case DismissedArkiveradUltimate Classic Rock: Slayer guitarist Jeff Hanneman dead at 49.”Slayer: "We could never do any thing like Some Kind Of Monster..."””Cannibal Corpse'S Pat O'Brien Will Step In As Slayer'S Guest Guitarist | The Official Slayer Site”originalet”Slayer Wins 'Best Metal' Grammy Award””Slayer Guitarist Jeff Hanneman Dies””Kerrang! Awards 2006 Blog: Kerrang! Hall Of Fame””Kerrang! Awards 2013: Kerrang! Legend”originalet”Metallica, Slayer, Iron Maien Among Winners At Metal Hammer Awards””Metal Hammer Golden Gods Awards””Bullet For My Valentine Booed At Metal Hammer Golden Gods Awards””Metal Storm Awards 2006””Metal Storm Awards 2015””Slayer's Concert History””Slayer - Relationships””Slayer - Releases”Slayers officiella webbplatsSlayer på MusicBrainzOfficiell webbplatsSlayerSlayerr1373445760000 0001 1540 47353068615-5086262726cb13906545x(data)6033143kn20030215029