Matrix using tikz packagealigning a multiline formula with the bullet of itemizeRotate a node but not its content: the case of the ellipse decorationvertical lines in matrix using tikz packageSubequation aligning using matrixNumerical conditional within tikz keys?Missing } inserted when using beginmatrixDrawing this matrix using TikzAlignment for equationsLatex matrix tikzCreating 6x6 matrix using bmatrix
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Matrix using tikz package
aligning a multiline formula with the bullet of itemizeRotate a node but not its content: the case of the ellipse decorationvertical lines in matrix using tikz packageSubequation aligning using matrixNumerical conditional within tikz keys?Missing } inserted when using beginmatrixDrawing this matrix using TikzAlignment for equationsLatex matrix tikzCreating 6x6 matrix using bmatrix
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
New contributor
add a comment |
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
New contributor
add a comment |
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
New contributor
I am working on my dissertation and I have no idea how I should do this in LaTeX.
And the shading definitely is challenging.
I have only been able to do this so far, I am still an amateur at it.
usepackagecolor
newcommandxtimes
newcommandycellcolorgreen
begindocument
beginequation*
left[
beginarrayccc
y & y & y \
& y & y R \
& & y \
endarray
right]left[
beginarrayc
\
a_j \
\
endarray
right]=
endequation*
enddocument
tikz-pgf math-mode equations matrices
tikz-pgf math-mode equations matrices
New contributor
New contributor
edited 2 days ago
Tarini Ramsewak
New contributor
asked 2 days ago
Tarini RamsewakTarini Ramsewak
334
334
New contributor
New contributor
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
yesterday
Thank you so much!
– Tarini Ramsewak
yesterday
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
yesterday
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4 - cycle;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-blastX) node[midway] (aX) $a_X$;
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
draw (mat2.west
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
-RlastX.north) rectangle
(f.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
-bX);
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
2 days ago
@Sebastiano Mille grazie!
– marmot
2 days ago
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
yesterday
add a comment |
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2 Answers
2
active
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2 Answers
2
active
oldest
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votes
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
yesterday
Thank you so much!
– Tarini Ramsewak
yesterday
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
yesterday
add a comment |
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
yesterday
Thank you so much!
– Tarini Ramsewak
yesterday
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
yesterday
add a comment |
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
With TikZ matrix
:
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarymatrix, positioning, patterns, backgrounds
tikzset
every matrix/.append style=
matrix of math nodes,
nodes in empty cells,
inner sep=0pt,
outer sep=0pt,
column sep=-pgflinewidth,
row sep=-pgflinewidth,
,
mylargenode/.style=
text centered,
text width=30pt,
text height=20pt,
text depth=10pt,
,
mylongnode/.style=
text centered,
text width=20pt,
text height=40pt,
text depth=30pt,
,
mysmallnode/.style=
text centered,
text width=20pt,
text height=20pt,
text depth=10pt,
,
mylonglargenode/.style=
text centered,
text width=30pt,
text height=40pt,
text depth=30pt,
,
begindocument
With delimiters like in your image:
[
begintikzpicture
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
% delimiters:
foreach mymatr in A,B,C
draw[very thick] ([xshift=4pt]mymatr.north west) -- (mymatr.north west) -- (mymatr.south west) -- ([xshift=4pt]mymatr.south west);
draw[very thick] ([xshift=-4pt]mymatr.north east) -- (mymatr.north east) -- (mymatr.south east) -- ([xshift=-4pt]mymatr.south east);
endtikzpicture
]
Or with ordinary delimiter:
[
begintikzpicture[
every matrix/.append style=
left delimiter=[,
right delimiter=],
]
matrix[
nodes=mylargenode,
column 6/.style=nodes=mysmallnode,
row 6/.style=nodes=mylonglargenode
] (A) \
&&&&&;
beginscope[on background layer]
foreach ind in 1,2,3,5
draw[green!70!black,fill=green!40!lightgray] (A-ind-ind.north west) -- (A-ind-ind.north east) -- (A-ind-ind.south east) -- cycle;
node[anchor=north east] at (A-ind-ind.north east) R;
endscope
draw[dotted, green!70!black] (A-4-4.north west) -- (A-4-4.north east) -- (A-4-4.south east) -- cycle;
node[font=Huge,shift=(-1,-2)] at (A) $0$;
node[font=Huge,shift=(1,3)] at (A) $0$;
matrix[
right =of A.north east,
anchor=north west,
nodes=mysmallnode
] (B) %
underlinea_1 \
underlinea_2 \
underlinea_3 \
\
underlinea_M\
underlineb\
;
foreach ind in 1,2,...,5
draw (B-ind-1.south west) -- (B-ind-1.south east);
draw[dotted] (B-4-1.north) -- (B-4-1.south);
matrix[
right =4em of B.north east,
anchor=north west,
nodes=draw,mysmallnode
] (C) [fill=yellow!10!white];
path (B-4-1) -- node[midway] $=$ (C-4-1);
draw[dotted] (C-4-1.north) -- (C-4-1.south);
endtikzpicture
]
enddocument
answered 2 days ago
CarLaTeXCarLaTeX
33.7k551138
33.7k551138
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
yesterday
Thank you so much!
– Tarini Ramsewak
yesterday
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
yesterday
add a comment |
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
yesterday
Thank you so much!
– Tarini Ramsewak
yesterday
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
yesterday
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
How nice is yours, too. I'll vote for it now.
– Sebastiano
2 days ago
1
1
@Sebastiano Thank you!
– CarLaTeX
2 days ago
@Sebastiano Thank you!
– CarLaTeX
2 days ago
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
yesterday
I used this one in my dissertation and I am very happy with the result.
– Tarini Ramsewak
yesterday
Thank you so much!
– Tarini Ramsewak
yesterday
Thank you so much!
– Tarini Ramsewak
yesterday
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
yesterday
@TariniRamsewak You're welcome! I'm happy my answer is useful.
– CarLaTeX
yesterday
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4 - cycle;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-blastX) node[midway] (aX) $a_X$;
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
draw (mat2.west
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
-RlastX.north) rectangle
(f.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
-bX);
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
2 days ago
@Sebastiano Mille grazie!
– marmot
2 days ago
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
yesterday
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4 - cycle;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-blastX) node[midway] (aX) $a_X$;
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
draw (mat2.west
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
-RlastX.north) rectangle
(f.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
-bX);
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
2 days ago
@Sebastiano Mille grazie!
– marmot
2 days ago
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
yesterday
add a comment |
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4 - cycle;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-blastX) node[midway] (aX) $a_X$;
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
draw (mat2.west
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
-RlastX.north) rectangle
(f.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
-bX);
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
It is indeed a bit tedious. (EDIT: Fixed the first R
to become math mode, mille grazie to @Sebastiano!)
documentclass[tikz,border=3.14mm]standalone
usetikzlibrarypositioning,backgrounds,patterns
begindocument
begintikzpicture
beginscope[local bounding box=mat1]
path node (R0) $R$ foreach X [remember=X as lastX (initially 0)] in
1,...,4
ifnumX=3
node[below right=1.5em of RlastX] (RX) $phantomR$
else
node[below right=1.5em of RlastX] (RX) $R$
fi
;
beginscope[on background layer]
draw[fill=green!70!black]
foreach X in 0,1,2,4 - cycle;
draw[densely dotted] ([xshift=-1em]R3.north west) -- ([yshift=-1em]R3.south east)
coordinate(b3) |- cycle;
endscope
node[pattern=crosshatch,pattern color=purple,anchor=north west,
minimum height=6em] (F) at ([yshift=-1em]R4.south east) $F$;
draw[densely dotted] ([yshift=-1em]R3.south east-|R4.south east)
rectangle (F.east|-R3.north);
foreach X [evaluate=X as Y using int(40+10*X)] in 0,1,2,4
-RX.north);
endscope
path (mat1.south west) -- (mat1.north east)
node[pos=0.3,font=Large] $0$ node[pos=0.7,font=Large] $0$;
draw[thick] ([xshift=0.7em]mat1.north west) -| (mat1.south west) -- ++ (0.7em,0)
([xshift=-0.7em]mat1.north east) -| (mat1.south east) -- ++ (-0.7em,0);
%
beginscope[local bounding box=mat2]
foreach X [remember=X as lastX (initially 0)] in 1,2,3
-blastX) node[midway] (aX) $a_X$;
path ([xshift=1em]mat1.east|-R4.north) --
([xshift=2.5em]mat1.east|-b4) node[midway] (aM) $a_M$;
node[below=0.5em of aM] (b) $b$;
endscope
draw[thick] ([xshift=0.5em]mat2.north west) -| (mat2.south west) -- ++
(0.5em,0)
([xshift=-0.5em]mat2.north east) -| (mat2.south east) -- ++ (-0.5em,0);
foreach X in 0,...,4
draw (mat2.west
%
node[anchor=west] (eq) at (mat2.east|-mat1.center) $=$;
%
beginscope[local bounding box=mat3]
node[pattern=dots,anchor=north west,pattern color=yellow!60!orange,
minimum height=6em] (f) at ([xshift=0.1em]eq.east|-F.north) $f$;
foreach X [remember=X as lastX (initially 0),
evaluate=X as Y using int(30*X+10)] in 1,2,3
-RlastX.north) rectangle
(f.east
fill[yellow] ([xshift=0.1em]eq.east|-R4.north) rectangle
(f.east|-b4);
draw[densely dotted] (f.center|-b2) -- (f.center|-b3);
endscope
foreach X in 0,...,4
-bX);
draw[thick] ([xshift=0.3em]mat3.north west) -| (mat3.south west) -- ++
(0.3em,0)
([xshift=-0.3em]mat3.north east) -| (mat3.south east) -- ++ (-0.3em,0);
endtikzpicture
enddocument
edited 2 days ago
answered 2 days ago
marmotmarmot
110k5136255
110k5136255
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
2 days ago
@Sebastiano Mille grazie!
– marmot
2 days ago
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
yesterday
add a comment |
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
2 days ago
@Sebastiano Mille grazie!
– marmot
2 days ago
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
yesterday
1
1
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
2 days ago
Spectacular! There is the first R on the top left that is not in math-mode. :-)
– Sebastiano
2 days ago
@Sebastiano Mille grazie!
– marmot
2 days ago
@Sebastiano Mille grazie!
– marmot
2 days ago
1
1
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
2 days ago
@JouleV Thanks! The second code shouldn't be there so I removed it. (I have one file for answers and accidentally copied the code for another answer, too.)
– marmot
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
I hope I've been of some help to you. This is what I so much regret about my mistakes, which are the result of naivety and which, by emphasizing my mistakes, the haters find fertile ground in my regard. Peraphs is better "grazie mille". Why? See this link youtube.com/watch?v=KvS_BVda9ww. :-)
– Sebastiano
2 days ago
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
yesterday
Thank you very much, this has been useful. I learnt quite a few things.
– Tarini Ramsewak
yesterday
add a comment |
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
Tarini Ramsewak is a new contributor. Be nice, and check out our Code of Conduct.
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